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本帖最后由 ce958www 于 2021-2-22 16:55 编辑
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: T) {0 h; `" {! C0 Z' d麻烦大神帮忙看看这个错误提醒要怎么修改?非常感谢!
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1 Y7 E- p% {+ G& ?. v2 r2 G错误使用 Idletime (line 37) k8 }! k' B. M* x
在 'Difference' 的工作进程上引发了 UndefinedFunction 错误。这可能是因为在这些工作进程上无法访问包含 'Difference' 的文件。使用0 M/ r0 K5 `6 h+ ^7 k( t2 H* W& ^. B
addAttachedFiles(pool, files) 指定要附加的必要文件。请参阅 'parallel.Pool/addAttachedFiles'的相关文档以获取更多详细信息。
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9 {9 v$ y. g7 \( G: v出错 IDLETIME_NEH_PR_LJP (line 7); g1 A3 G3 f, N$ D8 ?4 U2 d
paRFor qq = 1:120
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/ ^8 B3 {7 {( l/ E; O+ ~3 V原因:6 A. C! B8 W3 L) b+ \/ T7 |5 p
未定义与 'double' 类型的输入参数相对应的函数 'Difference'。
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代码如下:
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function [OUTPUT,OUTPUTTIME]=IDLETIME_NEH_PR_LJP
S, G/ B2 N6 Y) j! b/ G4 @4 J/ X3 x% Take idle time as objective when insert new job to partial sequence
9 F9 M% }0 T1 v+ T" T% martix including job operation time, n jobs and m machines; W/ @& ^3 |0 G5 T
% 3 x3 z+ V/ M' v# D! ]
: d3 @6 {- ]" L8 Y%% read data from excel9 B5 Z8 m( y4 D0 U
parfor qq = 1:120 q( J7 G g4 \/ F
filename='';
5 g% W3 Y) D. f: \' n( L4 Hfilename=strcat(filename,'Taillard\');1 Z* o' C+ A9 A5 }$ P/ D
filename=strcat(filename,num2str(qq));" l- c) d& \. F: c1 {2 }3 `
filename=strcat(filename,'.txt');
2 x; q% U9 m E6 q [A]=load(filename,'%*s%n');
* X' z- O: Q) F' B* D T=A(:,2:2:end);
* T. }2 e& s9 _4 Y. i5 Itic
! `. b$ C1 K' {8 m: d& m%% input variables
8 q3 K1 g* ?$ u6 \[n,m]=size(T);
) u6 g1 r3 R) y+ e* {+ Q3 bFinalsequ=zeros(1,n);6 m! p& ?( X3 v1 {: l1 E
H=zeros(n,m);
% T4 r3 C* _- [S=sum(T,2);* W# h* P7 i( m; m% s
M=[];, q; W% M; h/ H7 a; s" h; g" ^
HH=[];3 z* ?3 X, ?3 p& c$ {. Q
SSequ=[];
- N& T# L, k6 J$ J* WSequ=[];
# l1 F% C% Q' X, ~. wTOTALIDLE=0;1 w# ]" `7 A9 v' c! ^- p9 p" n& {
AVG=[];
5 I* p# G- s0 q. [# K# ZDEV=[];4 U; `- z* p' z5 D& @
SU=[];* t* M! ?& a7 y+ e. b4 P8 w
SUM=[];% l( }" z: U, H( n4 D$ p1 j, M
%% Obtain the initial sequence
; p' l) T; t9 f2 j0 Z0 ~for i=1:n9 h! F; E9 k& ] _8 ~
AVG(i)=mean(T(i,: ));5 ^4 L1 Q6 D2 G
DEV(i)=std(T(i,: ));
9 a. P# O9 h. h+ A, w: F2 R for j=1:m% e: g4 @$ a7 n/ r3 V2 k
SU(j)=abs(T(i,j)-AVG(i));7 z! r: y) k: F: X- u0 L9 g, P
end. Q; {4 w0 q/ H0 F( T
SUM(i)=AVG(i)+mean(SU(: ))+abs(nthroot(skewness(T(i,: )),3))+1/kurtosis(T(i,: ))^(1/4);! h8 O. K) G( t
end" ^8 v* ~! h7 `2 e6 Q* J6 K
[a,b]=sort(SUM,2,'descend');- \( U' W0 z5 y( Q
%% NEH-INSERTION
. m r+ }( v! g0 T! G# @; Q7 p8 Z% choose first two jobs
, k. k/ p1 p- h: [' GH(1,: )=T(b(1),: ); % let the job with largest sum of processing times be the first job- t# ?2 l3 H* B" ]
H(2,: )=T(b(2),: );
- S1 c p$ X0 o" D; G% wSequ(1)=b(1);
! P" b. `8 y& ^! Y: J- WSequ(2)=b(2);
* Y+ d9 u$ n& q2 h; E- E+ [& ATSequ=1:n;
* R) P8 X5 b& N% x: qProfile=zeros(1,m-1);: v! I9 b) e; f5 |' N
[TOTALIDLE1,NProfile]=Idletime(H,2,TSequ(1),TSequ(2),Profile); %#ok<*NASGU,*ASGLU>
- ?) I# s0 c3 i8 }ttt1=TOTALIDLE1;
7 r4 m* G$ j7 N% n# w; gH(1,: )=T(b(2),: ); % let the job with the second largest sum of processing times be the first job3 G3 d& J# `( Q4 R6 }! @; K3 }
H(2,: )=T(b(1),: );
1 s6 p# T0 e% c8 K" p) l0 E, K: wSequ(1)=b(2);
b q6 U( y1 T6 h. L( oSequ(2)=b(1);
! x1 I. f9 O+ H0 GProfile=zeros(1,m-1);
4 U; S( g0 i7 O/ n) V3 @[TOTALIDLE4,NProfile]=Idletime(H,2,TSequ(1),TSequ(2),Profile); %#ok<*NASGU,*ASGLU>
' y) Q5 y/ I$ {" v4 Vttt2=TOTALIDLE4;6 ~8 @( _" P( j4 E' j- |- b
if ttt1<ttt2 % compare the makespan.
0 ~6 _5 H/ F, L7 Z H(1,: )=T(b(1),: );
! d5 P. D& W- ~9 y2 ^& o& G H(2,: )=T(b(2),: );
+ a* e4 P U( Q: m; k Sequ(1,1)=b(1);
4 c/ T% ]5 I3 G; m" |6 W0 I+ X% V Sequ(1,2)=b(2);
% z4 E. o% H+ F/ _ u7 O. M Q6 L TTT=ttt1; %#ok<*NASGU>
% p/ v: E9 M' |else
2 R6 k: s! f0 s8 W/ d4 d6 ~$ A: d, Y H(1,: )=T(b(2),: );
# r0 m5 [+ v- P0 C8 I- o H(2,: )=T(b(1),: );
. W0 R6 ^% \ B* {8 O6 I Sequ(1)=b(2);6 I8 F1 E! Y/ g) r' d
Sequ(2)=b(1);' s- d q6 u- r" b
TTT=ttt2;
( x# ^( _: k; ~: t! M/ Nend
3 k8 _7 T& b0 |% choose the subsequent job and add to the partial sequence
$ t% I) y1 A8 Z# {e=zeros(n+2,m+2);
$ g. O4 m+ }1 }/ j9 qq=zeros(n+2,m+2);0 Q0 ?; b A1 A" r( h E1 }/ V
f=zeros(n+2,m+2);
( l: w! _# T. ^; ^& _8 `- ISSequ=Sequ;) R/ [4 Z, K* X2 U# _0 Z+ c/ w
for i=3:n % insert the rest of jobs& H9 I% N: Z, n& I: R! n8 q) ?9 x
Sequ=SSequ;
! C: M- K) ^/ k1 a8 u for d=1:i-1 % calculate earliest complection time of each job on the sequence0 O3 e" ~5 h* t$ w6 G
for y=2:m+1
* h5 q2 m0 x1 G' [9 s+ A e(1,: )=0; % machine number starts from 2 to m+1
d8 e8 o) u8 |$ B) @ e( :,1)=0; ( f* R% F+ I- T9 H, A
e(d+1,y)=max(e(d+1,y-1),e(d,y))+T(Sequ(d),y-1);9 N2 C4 M% [& p: c/ `
end r2 M. U) Y: y0 [! _! r
end
+ G% l& ^$ N7 p- O for x=1:i % x indicates the position where the new job is going to be inserted, H6 W' o! x) H5 |3 K
TSequ=Sequ;
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for p=i-1:-1:x
% _4 u$ Y/ H3 G# T9 C TSequ(1,p+1)=TSequ(1,p);
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TSequ(1,x)=b(i);
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for p=x:i-1
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t(1,: )=0; % machine number starts from 2 to m+1
, N6 _1 W$ v1 M* t t( :,1)=0;$ `( @! l& _6 e5 @- \6 ^+ T! B' Z) f
t(x+1,y)=max(t(x+1,y-1),t(x,y))+T(b(i),y-1);
5 x1 C/ W" V! r t(p+2,y)=max(t(p+2,y-1),t(p+1,y))+T(TSequ(p+1),y-1);/ R+ X+ S u9 i. B* W+ K2 U' v
end" y- \0 i5 v2 h( v: W5 z, z2 U
end5 l. Y2 g; f9 z; D1 h
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for y=2:m+1& c/ a6 T, P7 u. N# p
t(1,: )=0; % machine number starts from 2 to m+10 K6 g9 [+ b/ u% r4 ]
t( :,1)=0;. L- I7 M1 x3 C8 D
t(x+1,y)=max(t(x+1,y-1),t(x,y))+T(b(i),y-1);! b3 V: I( b( c
end6 q |- a2 s1 x5 m, t1 s
it=zeros(i+1,m+1);
$ D8 V. A2 B4 @5 q [$ w8 | for d=1:i % computate idletimie martrix
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it(1,: )=0;9 v- g9 G1 E% n2 P+ V. O: P; H
it( :,1)=0;
% ]- p9 o# L. ?' b: v% R it(2,: )=0;
. B' s# H% ^! t# T/ [ it(d+1,y)=max(0,t(d+1,y-1)-t(d,y));* C/ [# Z I! T" c. {6 M' b2 W3 p
end
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if x==18 O) t$ T+ g/ @+ ^7 {
TOTALIDLE=sum(it(: ));& U |) ]! ^; t$ ~. I
Finalsequ=TSequ;
4 ]7 [: p$ t; \. d' k end
2 U: X+ Y( i3 p7 x if sum(it(: ))<TOTALIDLE
0 i0 h* V. I4 I1 Q' S TOTALIDLE=sum(it(: ));3 t+ E# |) [0 X2 E/ ^% B
Finalsequ=TSequ;
* h; ^: f. {, W @8 ~* x end
* m& d' m6 G; g+ X end
+ Y& A; x2 }% {4 E0 D0 D w SSequ=Finalsequ;" N- \6 ]9 m, I, M5 R2 Q! B& J
end& {1 T" l' W' I' V; d) J+ R1 j9 \
%% WRITE DATE INTO EXCEL
# E4 s& B0 y, Vtime=toc; c7 T) w0 ]* m9 P* c+ o7 X; @9 I( P
time
2 i, r7 G# Z: l ]' ZOUTPUT(qq,1)=TOTALIDLE;
/ |+ ^7 x7 g/ f x6 Q5 c- yOUTPUTTIME(qq,1)=time;
7 [3 B7 H0 ?9 x7 F( h; \" a; zend
~8 l8 V7 \& }* A9 R$ P5 z/ zend |
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