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本帖最后由 ce958www 于 2021-2-22 16:55 编辑 6 \; f' F2 z+ q3 N0 ]
. N0 ^+ [3 Y$ f F( a麻烦大神帮忙看看这个错误提醒要怎么修改?非常感谢!$ l7 G7 @3 C x8 I% Z7 |
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错误使用 Idletime (line 37)/ ^6 A; ?6 U- V4 b- A& {
在 'Difference' 的工作进程上引发了 UndefinedFunction 错误。这可能是因为在这些工作进程上无法访问包含 'Difference' 的文件。使用1 |" X) E* @* L. q" p8 B5 a3 v% ?
addAttachedFiles(pool, files) 指定要附加的必要文件。请参阅 'parallel.Pool/addAttachedFiles'的相关文档以获取更多详细信息。, ~$ N, a/ H; c) f" q
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出错 IDLETIME_NEH_PR_LJP (line 7)3 Z3 v! T( J# p' c. q( W
paRFor qq = 1:120
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( G J. u$ \) ~- A8 u- G: |原因:
G f+ T/ o/ U- x8 ? H7 O 未定义与 'double' 类型的输入参数相对应的函数 'Difference'。
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7 K' G8 t9 B! K i代码如下:
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: I- X6 S1 f; H& qfunction [OUTPUT,OUTPUTTIME]=IDLETIME_NEH_PR_LJP2 p m, Q, c% p- G
% Take idle time as objective when insert new job to partial sequence- u+ I1 Y! K' ?! b# c
% martix including job operation time, n jobs and m machines' E% {' }* {' P7 {
%
# `6 }6 x: v" K) I1 n) F! E, x; n4 k% E, r, n) n: o5 s& w# x
%% read data from excel
! N& U; |4 m q2 ^$ @: T0 \parfor qq = 1:120! A" ?. E: a4 k% h B
filename='';; d/ D: |' i. B5 F! i* ~
filename=strcat(filename,'Taillard\');+ e2 E1 [; R: E
filename=strcat(filename,num2str(qq));2 h1 p( a8 V+ `* A: l; w7 G
filename=strcat(filename,'.txt');
5 U. g/ ?# U; o) t( c3 U [A]=load(filename,'%*s%n');
2 }. X+ |: \6 c) P3 @ T=A(:,2:2:end);0 H' B7 C( E7 Q( c0 A1 Z. }, b5 r
tic
5 u: j0 ?/ l% m! v%% input variables% q8 F, y7 V/ D, C" V% b6 j
[n,m]=size(T);
* ~' G, Z6 s4 H+ u3 B' kFinalsequ=zeros(1,n);
6 E9 t! ?. d1 c z! T$ iH=zeros(n,m);- n8 b% H4 L/ g) m
S=sum(T,2); L; m9 `8 L$ y2 c- t
M=[];$ t* j# t; j$ L% ]+ A5 F" G
HH=[];
) `6 s1 o) z4 {4 P, ]- pSSequ=[];- L/ g. m: t/ }, M+ b( @' k
Sequ=[];
* U7 [" a- o8 |: t2 pTOTALIDLE=0;
2 w1 ]3 [5 h* r, `1 p, cAVG=[];
4 n1 b( a' k' { E" n! |DEV=[];$ E' q' Z4 m1 ]
SU=[];$ c3 _. r- b4 `) W$ \1 E) a9 U
SUM=[];) o0 v3 L+ u7 _6 [5 }0 g7 t$ H* H
%% Obtain the initial sequence8 O* a" z; A/ j6 b8 w Z1 T
for i=1:n3 v- Y% E* q4 w* o' ]- l% V6 T5 z* u
AVG(i)=mean(T(i,: ));, ?% k% x5 K3 @+ s8 J! ^
DEV(i)=std(T(i,: ));! B- X7 m* x! v6 j3 j" W
for j=1:m0 R, z+ p3 _, |9 U' T/ t
SU(j)=abs(T(i,j)-AVG(i));
1 A. ~* Z8 ]3 I1 {; _5 p end
! d P6 v* C- d+ R& Z% t SUM(i)=AVG(i)+mean(SU(: ))+abs(nthroot(skewness(T(i,: )),3))+1/kurtosis(T(i,: ))^(1/4);
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[a,b]=sort(SUM,2,'descend');$ d/ G! _4 ~# {5 W
%% NEH-INSERTION. K3 _3 s- \4 @ ~
% choose first two jobs
6 _- E. e* `, YH(1,: )=T(b(1),: ); % let the job with largest sum of processing times be the first job
: E# p( z6 v4 u) O$ JH(2,: )=T(b(2),: );
1 z2 g6 r. S' F) E8 qSequ(1)=b(1);' w' {' g$ F2 g3 f# T
Sequ(2)=b(2);! K7 r) J$ Z& L) V5 w
TSequ=1:n;4 {5 i, q- w* Q7 k4 g# f, M# P
Profile=zeros(1,m-1);
# [$ @) o: I) V3 h; E8 p[TOTALIDLE1,NProfile]=Idletime(H,2,TSequ(1),TSequ(2),Profile); %#ok<*NASGU,*ASGLU>6 z. _$ O* ~% D8 m/ E
ttt1=TOTALIDLE1;
: \1 ^9 U5 S, {9 A, M. t& ` \1 f: SH(1,: )=T(b(2),: ); % let the job with the second largest sum of processing times be the first job
9 w0 \6 f2 t8 o; P/ ^, UH(2,: )=T(b(1),: );
) N/ p& _, {! f- r) pSequ(1)=b(2);
. y6 d" U+ W% r" N- hSequ(2)=b(1);. G. O, r3 \' l( k$ ~6 N
Profile=zeros(1,m-1);2 H, _( Y1 M- u/ V+ d
[TOTALIDLE4,NProfile]=Idletime(H,2,TSequ(1),TSequ(2),Profile); %#ok<*NASGU,*ASGLU>7 y; E6 t/ }5 Q' G
ttt2=TOTALIDLE4;! ?, \4 k' z, Y6 L$ p( e
if ttt1<ttt2 % compare the makespan.
9 D9 z6 e9 d# ]+ ?& g H(1,: )=T(b(1),: );+ I/ ] r5 b4 A. ?4 @6 Y5 e; }
H(2,: )=T(b(2),: );( V: {; {/ ^1 f" V4 G! s) O
Sequ(1,1)=b(1);. ?! Y3 E# K e# {: m: |# T+ ]3 C
Sequ(1,2)=b(2);
) x$ }" v7 Z! p1 d1 X( z TTT=ttt1; %#ok<*NASGU>
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H(1,: )=T(b(2),: );+ B9 s" ^$ p# T# e
H(2,: )=T(b(1),: );; G* f" {! R* E, y5 Y: T
Sequ(1)=b(2);
3 f% t$ k& Q& X# _4 ^4 s$ w: z/ n7 m Sequ(2)=b(1);
7 i! b$ Y. A( D/ S5 ~ TTT=ttt2;
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5 ^; K4 _ b* C8 W) c- J6 r% choose the subsequent job and add to the partial sequence
5 ?1 m. ~& x* E" e6 \$ O: B, f3 fe=zeros(n+2,m+2);
, X" ?6 m% |7 m, ?4 q! }7 E8 g9 wq=zeros(n+2,m+2);
6 P- ]1 W! E- b7 l6 `# x7 yf=zeros(n+2,m+2);
. S( d6 ~& g Q# \2 sSSequ=Sequ;2 Y* {9 w- G! G8 f
for i=3:n % insert the rest of jobs
N/ Z9 J6 {1 Q) l# n& _- q2 F7 v Sequ=SSequ;& q9 I" a6 `9 u) {% A4 B* C7 c5 Y8 ?
for d=1:i-1 % calculate earliest complection time of each job on the sequence
* T2 I$ n. ~% q" k) _ for y=2:m+1
, n4 n- C1 R0 |4 [$ |# p8 l e(1,: )=0; % machine number starts from 2 to m+1
5 S5 j6 r8 e* W$ W( `8 ?. X e( :,1)=0;
/ U8 k+ ]( ?2 i' X! J' A e(d+1,y)=max(e(d+1,y-1),e(d,y))+T(Sequ(d),y-1);7 O9 g5 e& L% C# |( r" l/ n
end
5 [$ i4 d9 {+ ?* Q+ ~1 X6 q6 n' f end
# i; F, i* |, M1 |4 m for x=1:i % x indicates the position where the new job is going to be inserted6 k0 ~, y, Q5 J) y8 j2 L
TSequ=Sequ;
0 k" ?" ~. h2 @7 z t=e; \+ B5 o4 h, ]! `- m
# |0 \; j" w0 r L for p=i-1:-1:x
' T1 D# F B' Y; ?2 ]3 C TSequ(1,p+1)=TSequ(1,p);( E; u0 ^( f6 h: b$ w1 ?; _
end1 K' v' _* f3 z8 Q& h4 p) k6 h( S
TSequ(1,x)=b(i);/ Q F; h1 J0 w- P; A, `, w
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for y=2:m+1
, `$ r" m8 q- e t(1,: )=0; % machine number starts from 2 to m+1
2 |% t' `3 l) C, K6 C5 c$ b t( :,1)=0;6 @7 `; z, ]3 e
t(x+1,y)=max(t(x+1,y-1),t(x,y))+T(b(i),y-1);( ]/ T$ ^9 @) K! U
t(p+2,y)=max(t(p+2,y-1),t(p+1,y))+T(TSequ(p+1),y-1);
8 \; A' V, D5 L1 Z2 b b end
; K. S- o9 g+ T* o+ b end
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for y=2:m+1
5 \* Y' x4 S) ^$ Y! N) i/ I t(1,: )=0; % machine number starts from 2 to m+1% n6 Q0 k% w; }) {- [
t( :,1)=0;
1 P5 b) Z+ N! \1 k, I2 Z t(x+1,y)=max(t(x+1,y-1),t(x,y))+T(b(i),y-1);
9 l! H; I# S" r* P9 m$ V9 @ end
1 W. V: ]. u5 h" V; I q it=zeros(i+1,m+1);- u8 ~) B, C/ p; r# M7 f5 D: Y, Z. M
for d=1:i % computate idletimie martrix
8 Z! V9 Q1 `7 n7 q$ h for y=2:m+1
( y/ ~# f, y2 g. n# J( H$ ? it(1,: )=0;- F( T$ Q! p0 s- {2 ]/ a1 a! c
it( :,1)=0;
5 g7 e9 p h/ X2 Q0 v" }: p% e it(2,: )=0;
1 u- Q, I& w8 L6 K it(d+1,y)=max(0,t(d+1,y-1)-t(d,y));
1 l, t( D; s5 V2 m0 z& h& Y2 K end
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if x==1
* @: e Y' {- i. x7 B) Z TOTALIDLE=sum(it(: ));( o/ K0 M! }6 p) Y
Finalsequ=TSequ;
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if sum(it(: ))<TOTALIDLE
; l$ j2 O* _3 a. N TOTALIDLE=sum(it(: ));" Y [. e2 `2 T3 k% B; t1 e M8 @
Finalsequ=TSequ;
' v5 `( g8 k1 x2 c( d" H end: y( n2 R. M: k+ z, M" F
end
/ F/ \, A0 u% _) }$ P5 y SSequ=Finalsequ;
) }' C$ B, C# k+ P, A; tend
% u9 T9 A' W4 D* E2 H7 }9 a1 q* L%% WRITE DATE INTO EXCEL
! j5 s! Q# {, D% E. ]' X5 v% Mtime=toc;
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1 n, D& `' \) _1 h/ z# D1 c4 EOUTPUT(qq,1)=TOTALIDLE;
8 J* F. _1 P! i: n. lOUTPUTTIME(qq,1)=time;4 l6 S) H: x7 U6 m& X0 s
end
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