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麻烦大神帮忙看看我这个错误提醒要怎么修改。非常感谢!
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, h1 i) u4 s, ~错误使用 Idletime (line 37)
$ ~/ j1 f- ]2 A$ D- o在 'Difference' 的工作进程上引发了 UndefinedFunction 错误。这可能是因为在这些工作进程上无法访问包含 'Difference' 的文件。使用addAttachedFiles(pool, files) 指定要附加的必要文件。请参阅 'parallel.Pool/addAttachedFiles'的相关文档以获取更多详细信息。- e+ n7 v0 w4 c, w E
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/ ^8 A9 A) d* m6 J, d2 ^( B# F出错 IDLETIME_NEH_PR_LJP (line 7)
& }# ~2 A2 r5 @7 `$ LpaRFor qq = 1:120* K' u! F# T! ? `
$ Q1 J: c0 B7 O! ^
6 k, `/ F; |3 O0 f7 |( ^& ^原因:
5 l h5 ^ q$ p7 O* g 未定义与 'double' 类型的输入参数相对应的函数 'Difference'。
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代码如下:' {1 R( f/ ?) V$ |
function [OUTPUT,OUTPUTTIME]=IDLETIME_NEH_PR_LJP
8 R6 m2 l% S1 U8 P6 W7 A% Take idle time as objective when insert new job to partial sequence4 @ O% a8 m6 m0 J5 [, c
% martix including job operation time, n jobs and m machines9 A* S" y0 z9 o0 q9 |7 z- h: n
%
/ @$ w( Q, U# O0 U5 J6 V) m# o* H+ `: n- N% | f& r. S+ i5 @
%% read data from excel) C" n8 v# j+ f2 A
parfor qq = 1:120+ j- y3 H& } `) }. n0 p3 w& S
filename='';
( Z- N" J I. s6 }8 B1 E, Z/ Y# d% Yfilename=strcat(filename,'Taillard\');
# ]8 y9 j+ `3 mfilename=strcat(filename,num2str(qq));% z/ o$ Q$ S9 b, F
filename=strcat(filename,'.txt');
7 X0 g; U6 o/ p8 o [A]=load(filename,'%*s%n');
v/ }* n1 c& \9 l0 m. f T=A(:,2:2:end);
- h# I3 N9 l4 K: b4 \5 Itic. }4 y: V' N6 P
%% input variables
$ X6 m6 j6 f: K5 U6 r9 Q[n,m]=size(T);& \4 |. O6 |& b6 q+ h$ G
Finalsequ=zeros(1,n);9 ^- f" i" ]: P4 ?1 }
H=zeros(n,m);
, c" a6 ~' ]' v6 |5 b/ CS=sum(T,2);; T3 z3 k9 n9 U) Z+ d9 _& I
M=[];
a9 p7 R+ p' w8 Z7 WHH=[];/ t9 O0 }, f5 g( N" R
SSequ=[];
# m( l! K8 }; ISequ=[];% t5 I: J- B1 _
TOTALIDLE=0;7 J8 z! _6 e1 ]7 S* ?
AVG=[];* A l! F! F( O3 D& W
DEV=[];
0 ?( z" G( A, A* T2 J' HSU=[];
: e9 ?4 q/ X4 u3 C! ZSUM=[];3 x' O! H( f- |
%% Obtain the initial sequence
: N3 q7 u% E* R. c8 |" H' e* L. N/ n" afor i=1:n# P5 G7 n0 E. S) j; E+ D6 f
AVG(i)=mean(T(i,: ));
8 k) O( q: t; G2 @0 V( r4 ] DEV(i)=std(T(i,: ));/ \4 q) D0 ]8 n9 Z
for j=1:m
2 e9 S% u& v' W" E5 { SU(j)=abs(T(i,j)-AVG(i));. S: ~( x2 W" k% a) U- K4 P7 B
end
4 C6 R& T, q- u3 ~3 L SUM(i)=AVG(i)+mean(SU(: ))+abs(nthroot(skewness(T(i,: )),3))+1/kurtosis(T(i,: ))^(1/4);) m/ K0 Z' X3 z! M% Z' P8 k- ]! _
end; w+ m4 U! a6 o- k+ Q; V
[a,b]=sort(SUM,2,'descend');7 {9 W. I; u- ?' Q' b) n: v1 g8 @ T# G
%% NEH-INSERTION+ I! g, l4 r; D7 ]% Q
% choose first two jobs
: h2 b7 l0 t2 C* NH(1,: )=T(b(1),: ); % let the job with largest sum of processing times be the first job7 z5 @( R; I7 z" Z- Y+ }5 n1 k
H(2,: )=T(b(2),: );- A6 v1 I6 r9 j1 {& A
Sequ(1)=b(1);$ p8 ^: Z7 X5 j' \0 O6 a
Sequ(2)=b(2);
# C; E, P! r4 K$ H2 f8 aTSequ=1:n;( _; o0 n& K, s8 j
Profile=zeros(1,m-1);) F2 L8 k; b2 ^- e! g3 u
[TOTALIDLE1,NProfile]=Idletime(H,2,TSequ(1),TSequ(2),Profile); %#ok<*NASGU,*ASGLU>- G9 ^1 y/ ~# s9 `& ]- D
ttt1=TOTALIDLE1;
" y( } j8 u2 E. @H(1,: )=T(b(2),: ); % let the job with the second largest sum of processing times be the first job
- F$ A0 o, V1 d" i) h# @. k7 AH(2,: )=T(b(1),: );
( w( f& ^- U) W1 L, YSequ(1)=b(2);9 i: `- ~* ]8 K8 ?0 j
Sequ(2)=b(1); M7 ~8 _- ^/ D( R- w: {
Profile=zeros(1,m-1);, ` I/ d- M4 o+ |
[TOTALIDLE4,NProfile]=Idletime(H,2,TSequ(1),TSequ(2),Profile); %#ok<*NASGU,*ASGLU>8 B) j* f0 r6 b" K) `6 i" U
ttt2=TOTALIDLE4;: g0 H0 F) k# J4 |" {% d6 |4 V
if ttt1<ttt2 % compare the makespan.
. H; T- {: Z( R: x7 {% ^8 b6 c9 }' ? H(1,: )=T(b(1),: );
$ S) V0 v( g9 m0 [+ @ H(2,: )=T(b(2),: );
+ t9 @" W% b9 P/ _% s3 ? Sequ(1,1)=b(1);
" l8 Y' t' o) R# d% c Sequ(1,2)=b(2);) J& A! r; O4 P j8 K
TTT=ttt1; %#ok<*NASGU>- N% B$ u% D0 x. w5 L
else' m( N. X! P% n2 l
H(1,: )=T(b(2),: );
' a3 Q2 F$ p" z$ y9 Q1 ^% P H(2,: )=T(b(1),: );
g$ F( A5 t: _+ P3 q9 @" J Sequ(1)=b(2);
6 k" z% R9 u( i7 K Sequ(2)=b(1);# Q& n. e! c7 `& Y
TTT=ttt2;
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% choose the subsequent job and add to the partial sequence5 [: F7 M6 m% f
e=zeros(n+2,m+2);
' [' \% b, p* U% Vq=zeros(n+2,m+2);( U9 \4 J9 n3 O: W, x3 g7 Y
f=zeros(n+2,m+2);
" T. H/ W6 N/ f0 w' |- { zSSequ=Sequ;
7 \( `- b/ u- z1 L* j# |8 Vfor i=3:n % insert the rest of jobs
. U G9 P) S1 M+ v6 w9 n Sequ=SSequ;5 N- G' r, i `. x/ f- }
for d=1:i-1 % calculate earliest complection time of each job on the sequence
/ A7 h! b* H# Z. w/ t6 s+ f for y=2:m+1 3 k3 W1 K* i+ m- T# O" l
e(1,: )=0; % machine number starts from 2 to m+1% t. [5 x3 O. A
e(:,1)=0;
; @4 S, k. Y. `9 W* ^; m e(d+1,y)=max(e(d+1,y-1),e(d,y))+T(Sequ(d),y-1);
: q* S) ]$ B* u1 U2 J$ C: v8 R end
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for x=1:i % x indicates the position where the new job is going to be inserted
( D \( n4 w3 y TSequ=Sequ;( d$ c0 b3 v0 A
t=e;$ G$ J. L( g3 ~ W7 _2 g
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for p=i-1:-1:x* v; ^, f# P6 F; O9 M
TSequ(1,p+1)=TSequ(1,p);
2 I F, Z0 @: F2 H/ k end
% Y3 ^# M$ ~% ?& g2 ~! p TSequ(1,x)=b(i);
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; R$ |7 ?7 R8 o- w- O; E for p=x:i-1
9 `% k" I$ ~5 l for y=2:m+1
' L1 S5 C' F# d5 k7 v' A t(1,: )=0; % machine number starts from 2 to m+1
: h; ^# ^; f, R4 `+ a t(:,1)=0;
6 c8 e- L- Z3 }* P* w, y t(x+1,y)=max(t(x+1,y-1),t(x,y))+T(b(i),y-1);% Z$ R( c8 q7 g" k/ l4 N+ q
t(p+2,y)=max(t(p+2,y-1),t(p+1,y))+T(TSequ(p+1),y-1);
8 c; @! @# v5 D/ J; l* G end
4 z5 p9 q4 Q- D, a8 f, A0 ]# B end. m& i3 O D3 H3 |/ E( v2 i
$ F6 J6 G: K0 G, Q4 s for y=2:m+1& {8 n7 w$ x$ S+ A
t(1,: )=0; % machine number starts from 2 to m+1
1 V( v$ P/ [1 D t(:,1)=0;! Q% _. T& e/ V/ g" c3 x9 B
t(x+1,y)=max(t(x+1,y-1),t(x,y))+T(b(i),y-1);
3 `: [) |% H( i+ l, ~: Q end
2 d" K) j; q6 g+ E it=zeros(i+1,m+1);
4 X/ u) q0 Z5 h for d=1:i % computate idletimie martrix
1 l7 t% @0 Z" e' n5 P& d3 _" U4 A for y=2:m+1
. J$ c8 q% r* Z4 K2 o; V it(1,: )=0;
. R. G" o$ Q# I+ x+ c$ z* u$ P% L it(:,1)=0;
2 Y: h2 r ^% q) {% R it(2,: )=0; * F& B0 l v$ S9 I6 p2 Y
it(d+1,y)=max(0,t(d+1,y-1)-t(d,y));; ~ K. y' |) P4 W) Z
end
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if x==1& _! r) @; F! j
TOTALIDLE=sum(it(: ));
0 V0 n" }: Y: y% c/ U8 E! ^0 f Finalsequ=TSequ;
8 [2 e0 e+ l- ?2 ], p end
7 T J; E# o7 o) e' D8 w0 |' X if sum(it(: ))<TOTALIDLE, F2 x& `' J+ } f9 _
TOTALIDLE=sum(it(: ));( N- L0 }1 U+ Y; J& c; N! P+ R
Finalsequ=TSequ;8 Z2 l$ K r' S5 v4 I) n' u
end3 [% |/ s; s# Z5 O* z# A, v8 Z
end4 v- M: b+ z, i; D$ e. y
SSequ=Finalsequ;2 M7 I! `& R5 a/ @. f0 N! m. r
end, A6 j# s! j+ f% }- B4 ]
%% WRITE DATE INTO EXCEL. l n/ h3 H. Q& F, k& B/ U
time=toc;# S& p7 Y5 Z* e
time- {. M3 h) r; K7 ]( F& C I
OUTPUT(qq,1)=TOTALIDLE;
# T: @) b, q( E) H, n1 [, h7 N2 v; MOUTPUTTIME(qq,1)=time;
2 j+ a! [, f: x+ M7 E: z% fend+ {4 {6 y2 c1 d2 w0 q1 F; ]
end |
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