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, \; t. \, M7 B9 @我用一个调用函数来计算一个区间上的函数值并画图。此调用函数的输出是x = [x1; x2; x3];我想要把三个值的图像都画出来,编写的plot语句却都错了。错误信息:$ I( R0 n) F5 G7 y( b& d- c
错误使用 plot。3 j; ]- @7 \% L& S- y
数据必须为可转换为双精度值的数值、日期时间、持续时间或数组。
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出错 Untitled3 (line 3). U$ K( O# E& u$ P$ c8 N' b) y. N V
plot(y,c(:,1));+ W* w% ~ H5 [$ h
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以下是程序,使用的64位R2018。
/ n% ?5 r! c& m8 Ty=9.9:0.01:10.1;
8 c! X) m& b. J5 g8 I2 Bc=Solve3Polynomial(1,2.*k-20,power(k-10,2)+0.00005,-0.000001);2 P m) r* F0 ~
plot(y,c(:,1));! S4 p- k7 ^2 ~: G- }% o6 W
plot(y,c(:,2)); p. O/ Z& ~1 z1 }4 N0 n* W
plot(y,c(:,3));( ]$ M+ Q& P* o$ X& G4 o) V
function x = Solve3Polynomial(a,b,c,d)
# g: f( \ w T4 B% V# d% 范盛金. 一元三次方程的新求根公式与新判别法[J]. 海南师范学院学报,1989,2(2):91-98.7 ^* L" B! ?( e* d" X6 U5 Z4 I
syms x1 x2 x3;9 {( R S' a4 R9 N
A = b.*b - 3.*a.*c; if abs(A) < 1e-14; A = 0; end
5 a" n, F, R) t, vB = b.*c - 9.*a.*d; if abs(B) < 1e-14; B = 0; end
" { |# E$ R2 Z/ r! zC = c.*c - 3.*b.*d; if abs(C) < 1e-14; C = 0; end - _1 @2 G O8 d3 C, O- F5 u0 U7 ]
DET = B.*B - 4.*A.*C; if abs(DET) < 1e-14; DET = 0; end
# Y* u* H: Y' {; p9 rif (A==0)&(B==0)
7 [# H5 G: ?. | x1 = -c./b; x2 = x1 ; x3 = x1;6 H( B" y0 D) b5 P
end9 A$ d( o# H* n# G2 m
if DET > 0
4 N7 t1 x5 |6 j Y1 = A.*b + 1.5.*a.*(-B + sqrt(DET));4 e& O7 b) \, t
Y2 = A.*b + 1.5.*a.*(-B - sqrt(DET));
8 \$ X, l5 k& [9 M' B% o5 `2 J- b y1 = nthroot(Y1,3); y2 = nthroot(Y2,3);% ]' \: }4 n7 |8 k
x1 = (-b-y1-y2)./(3.*a);6 r5 V! v+ K/ J/ Y
vec1 = (-b + 0.5.*(y1 + y2))./(3.*a);
. K8 A" j+ d$ ?! H vec2 = 0.5.*sqrt(3).*(y1 - y2)./(3.*a);
5 D7 A B& j7 [ x2 = 0;
+ T: T7 k6 d+ Q8 T# g0 w7 x+ Q x3 = 0;
; \; J1 M$ K- } a- t clear Y1 Y2 y1 y2 vec1 vec2;3 |2 k/ h; D/ g
end
3 F0 y# V9 {& G; I1 ]; J- ?- t( xif DET == 0 & (A ~= 0) & (B ~= 0). |' E5 D1 _9 d `
K = (b.*c-9.*a.*d)./(b.*b - 3.*a.*c); K = round(K,14);
7 g9 @# r2 N0 Z/ ]- S x1 = -b./a + K; x2 = -0.5.*K; x3 = x2;9 P2 i% A1 I3 d2 M2 o# h* e
end% S- V1 c) c0 G$ p- H1 @- T
if DET < 0) r6 T& E1 q, h K
sqA = sqrt(A);+ k w3 M! h/ t' D* S1 p5 [
T = (A.*b - 1.5.*a.*B)./(A.*sqA);0 B2 e4 E; t3 i& e
theta = acos(T);/ _9 E2 N) E K. [( T+ u: X
csth = cos(theta./3);
% _9 o. S/ T- d# G: G sn3th = sqrt(3).*sin(theta./3);1 k# @6 U; Q/ I, K+ O7 D
x1 = (-b - 2.*sqA.*csth)./(3.*a);
5 M$ q5 W% B# v% [3 f, c+ b: S( P$ c2 | x2 = (-b + sqA.*(csth + sn3th))./(3.*a);
2 F. Q' C/ i6 i' j3 e2 S/ v: q8 [ x3 = (-b + sqA.*(csth - sn3th))./(3.*a);
1 Y/ d; b& l: H: j( o1 p$ D/ L clear sqA T theta csth sn3th;) W3 ]" ]2 x: G1 |# J7 K+ Q# a% F
end
7 D }1 U+ K$ D5 o* W9 ox = [x1; x2; x3];% a% i6 R( z! I! B7 F
end" n/ {# N$ g7 {8 j
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麻烦大神帮忙指点一下,非常感谢! |
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