rulelist问题

nkkopd

rulelist这个在help里怎么没有？下面这个矩阵是建立控制规则表吧，求解释一下！
rulelist=[7 7 7 1 1;
7 e5 b6 Z0 `, C& Q6 [9 e7 X                  6 7 7 1 1;
' S( z4 c2 i+ y* q                  5 7 7 1 1;
  p3 [5 A4 P, j1 _: i                  4 7 6 1 1;
                  3 7 5 1 1;
。。。。。。。]

shuddkk

帮你顶一下

zzz.dan

此为规则列表，此表能够唯一性地定义模糊系统的规则：
  c  [9 F' M. ]! F+ _$ O例如：
( ?; b0 @3 A  R4 A! R5 C7 N; h. g5 q. ~ruleList=[
        1 1 1 1 1
3 a, b" F; k4 _0 d! t        1 2 2 1 1];
8 l1 ]5 n9 n: d# o( N1 z. C/ Ra = addrule(a,ruleList)；
6 J2 ^$ J' I9 J) z  y( a: p说明系统具有两个输入一个输出：
"If Input 1 is MF 1 AND Input 2 is MF 1, then Output 1 is MF 1."   此规则的权重weight=1
2 v9 \( w; j; E9 s# ?- j"If Input 1 is MF 1 AND Input 2 is MF 2, then Output 1 is MF 2."   此规则的权重weight=1
" ]8 _" U% `8 K! K6 B! X5 B补充说明：
# ~3 T0 t4 T' Q" G- JThe first m columns refer to the inputs of the system. Each column contains a number that refers to the index of the membership function for that variable.
The next n columns refer to the outputs of the system. Each column contains a number that refers to the index of the membership function for that variable.
The m + n + 1 column contains the weight that is to be applied to the rule. The weight must be a number between zero and one and is generally left as one.
The m + n + 2 column contains a 1 if the fuzzy operator for the rule's antecedent is AND. It contains a 2 if the fuzzy operator is OR.

勇往直前11

来学习一下，二楼分析的很详细

小小鲁班

就是规则表用矩阵表示出来了，但总是最后多一位，基本后两位是“1 1”，即权重和？