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大家好，我从Excel中引用一组数据，进行三元线性回归拟合。利用regress，得到系数可能会为负数。请问如何对系数范围进行约束（0~1之间）
9 n2 v& P( X! Q8 x" R& c( O下面是我的数据和过程* n" e- A$ @0 T7 R0 p+ D
A=xlsread('G:\提油率测算20200704.xlsx',4,'H156:K185'); w! E& h# o" q& [+ A
3 _( n* y w$ P5 T$ j4 iA =: L* T: _' N+ Z8 J8 _: ]
; z# v; ?( l7 Z3 w5 J
15.1200 272.5640 11.5880 1.90004 P4 d; O! F; a Z# u! ?
15.4800 277.3200 11.2400 1.82002 O _/ z5 P; v) h5 [8 h
15.3360 285.3600 11.6240 2.0800
3 U9 V) l% F9 U& i 12.8160 295.3960 11.9280 1.9200' w& D% W9 v* n$ U
17.0000 300.7920 15.1080 2.5000
+ I4 z+ P) ` Z% p 16.2800 296.5760 15.4040 2.7200
# l, H) o1 B! P$ K* l) a `6 y- z* T 15.5600 291.5120 12.8200 2.2200
: v6 j$ h2 l* @# [9 x7 w' s z- Q 15.3440 289.1520 13.8640 1.9600
% C. z5 Y ]. V- W+ P/ F 17.3600 288.3760 14.1440 1.9600
1 S3 y( P! q8 W% N t$ @ 14.7600 290.2400 14.4920 2.0400
Q$ _8 V6 {4 Z( f) g% `; N8 P 15.6240 294.0520 14.8720 2.2400
: v- C% e# `- p* V2 Q( d7 p 14.5440 297.4480 18.4120 3.0800
& u. _+ [' f6 \1 S* @) d 16.4880 297.4160 17.7680 3.36002 q3 Y) p- \5 R6 N7 z
16.0560 294.9120 14.1920 2.74003 r1 h" p4 I( w; H1 }; _2 b
13.6800 300.9440 14.5720 2.3800' U' f$ U. f2 P/ j; ?9 q, W" L, b1 u
13.3920 302.0360 14.5120 2.3600% Z5 J5 o6 m, \% L
15.4800 307.5560 14.4200 2.4200
8 p! G& u6 O# _' g 12.8880 303.6000 14.6480 2.4000
) D8 `) T! ^2 w8 e 12.8480 306.8360 18.2720 3.0600
$ E L$ \$ j: V; f7 M g 14.3600 304.0480 17.6880 3.3600
, k8 |/ i9 U6 q/ X n1 W4 ~, z/ | 13.7840 300.0320 14.1720 2.7200
1 F: X7 T# h/ Z8 x/ [# q d 12.7760 301.1600 15.1240 2.1000) s4 E# y1 g. I/ K3 `, z/ s
12.9200 307.6480 15.5280 2.1200- E/ q9 k4 n$ E) b+ X8 c( h
12.8880 306.4080 16.0800 2.0400, v c2 H; f H6 b$ i
14.4000 300.1880 12.7560 1.80007 _! F y" f, p( f9 P
14.1120 296.6520 17.1200 2.46005 e6 ^% V+ v' Z( p/ t4 k+ T3 F
14.4720 290.6160 17.0080 2.8400: @4 J# o- q" [% y5 K) _
15.1200 287.3560 12.8280 2.2600) l5 S1 ^/ ~+ e3 g0 U# W' z
14.6880 290.6920 13.2520 2.0000
$ ^5 M: D' P0 P X! t 13.6800 298.2680 16.7680 2.2800
& k: H; J) H, j! f# w" Z/ N7 ^%第一列为因变量，后面三列为自变量( ~8 N+ u8 e( d; R1 r3 }7 I/ t# H
>> y=A(:,1),x=A(:,2:4)
" @, e7 Q! ^4 O2 o
6 X$ f# O- S, u jy =
; p/ k" X! ~+ R' K, n" q1 |/ r$ Y6 m* A- S7 ?2 o- d
15.1200! k7 E* T2 h0 ~) T9 o3 I& M$ m
15.48008 V% z( a1 R, ~
15.33605 A( R6 e w5 V2 C
12.8160 A0 @0 b! v$ {* W+ r, {$ C
17.0000
0 N; v. E$ w% r$ ]+ V 16.2800
) e/ H' F4 U L, U7 m6 ^/ v 15.5600
; b/ o3 Z S& g5 g2 c5 c- R; y 15.3440# b3 m* M7 l" ~- ]
17.3600- ]! y w1 i; ^8 V7 |! B5 w
14.7600
; Q" T6 u, Q# l" q% _+ {$ d 15.62407 z' N9 `% t3 T) Y3 R
14.5440
. D T/ t- e- ?' c 16.4880
5 P0 [. e! o. F+ S7 @9 s 16.0560
) ~/ Q9 e& _. g/ D 13.6800+ v+ O+ q8 i5 U1 W4 J
13.3920
. v- y5 U& S' R% a! e7 @- G 15.4800
; S3 |9 U2 C9 ]3 I2 r! s 12.8880
- Y# @3 @8 E$ s" c 12.8480, n) l6 u2 D! y9 z/ h. G! C
14.3600) U' B2 Y9 a3 P$ w ~4 D9 q
13.7840
; M: R( p/ K" @8 J2 d# ^# v 12.7760
( C' T: o) J+ e% ]0 C( N$ l( n 12.9200
. h6 b/ M: E+ R; q 12.88801 R3 H7 |, M; P, K) y: S
14.4000' G2 G/ K. `) m! T7 B6 [
14.11205 r- ]2 C& D' b& U
14.47205 R8 O) f0 Q3 z K& ]; K
15.1200* ^9 C3 g Q ], m C ]* X) S
14.68806 A) `' o0 b, E
13.6800- g$ }( r+ x1 w5 R) Z
4 |- g% c" V& A6 ?6 {/ h/ N% U
4 ~5 J4 E9 o9 Z) o1 f& tx =
9 K% A( X5 g4 d) y% H% R$ Y+ W7 K+ C! S% ~; }, j" F
272.5640 11.5880 1.90001 I a( @' o f! \" x
277.3200 11.2400 1.8200
4 q- p' c9 \4 r P2 t 285.3600 11.6240 2.0800
7 E3 f; C7 y8 h7 V: N2 N/ r 295.3960 11.9280 1.9200
# u& a3 t0 @; a( u3 w 300.7920 15.1080 2.5000! j% |0 ?8 _. `. L: o
296.5760 15.4040 2.7200
" }1 c* L/ w8 \2 \# k1 y) c8 e 291.5120 12.8200 2.2200
% }0 ^4 A# s" P( j+ t 289.1520 13.8640 1.9600
" O- k$ H! y5 t6 o& b3 w. [- R2 \ 288.3760 14.1440 1.9600
& D0 k' F6 k3 n% ~1 Q, `' S& ` 290.2400 14.4920 2.0400* \8 E+ A+ W5 O1 A2 ~& S
294.0520 14.8720 2.2400' S* H0 t7 ^5 H5 Q$ E5 Y3 ?
297.4480 18.4120 3.0800; I6 l3 z4 a% C, `
297.4160 17.7680 3.3600 u0 ` j0 u: q
294.9120 14.1920 2.7400
. S3 o4 \$ y% Z3 v# Q2 m) w! e, S# M 300.9440 14.5720 2.3800
0 M5 z! f8 R; ? 302.0360 14.5120 2.3600
; I* O( t$ J. ^8 a, ] 307.5560 14.4200 2.4200
' W5 F* D7 m1 f+ H( I# h7 K 303.6000 14.6480 2.4000$ w X( u- u8 i1 ^" G6 d7 @! M
306.8360 18.2720 3.0600# c; _/ f$ K$ F A4 [1 N( B
304.0480 17.6880 3.36003 q8 e6 ^, s6 t% ]
300.0320 14.1720 2.72004 a4 f$ B) G* X4 s& O( q5 @; q
301.1600 15.1240 2.10009 H2 W. u: t! U- G: Y
307.6480 15.5280 2.1200 z0 U* S4 U }% ~: E' S* I. V F7 G
306.4080 16.0800 2.0400
, z: }0 U o8 V, B1 P9 p 300.1880 12.7560 1.8000! p( G) U% u& ]3 I
296.6520 17.1200 2.4600
! T$ P0 B8 j K" A 290.6160 17.0080 2.8400
; w* Z: \: |, I. Y% v+ L! q 287.3560 12.8280 2.2600' l+ D" Q8 {9 E4 C0 ^* p5 z
290.6920 13.2520 2.00009 ~; _$ \$ M [
298.2680 16.7680 2.2800
i4 a' V8 I: l5 }7 A+ A8 Y e4 ?
8 z H& `! U! E% i' h>> B=regress(y,x)0 ?$ S9 G. t$ e# h$ Z1 R$ @' P; ~
2 t, p9 t( K$ z4 x) d4 P
B =
% z9 p" w* D6 B( |: ]' w2 V3 s. ^0 P# t
0.0587
: w6 \# l" n1 l+ C& q* O" r -0.4411# m" J$ {. k" h5 [1 {
1.58182 s) _4 ^0 u$ E" b( s6 c
) s0 N' s4 c& c( Q5 _( u
请教大神，怎么对系数进行约束（0~1之间）。
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发表于 2020-7-22 09:43
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