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大家好，我从Excel中引用一组数据，进行三元线性回归拟合。利用regress，得到系数可能会为负数。请问如何对系数范围进行约束（0~1之间）$ o# J& k" r$ |7 o# `. v
下面是我的数据和过程. M, b: {9 f5 |0 \: I! i
A=xlsread('G:\提油率测算20200704.xlsx',4,'H156:K185')
4 D3 E ^' k3 F! h3 q1 A% c q; @- G: @
A =2 n+ ~' B8 ]9 r6 N/ x( Z$ y
. w" x$ c9 n# \ 15.1200 272.5640 11.5880 1.9000
* h' `( X! Q7 d* C 15.4800 277.3200 11.2400 1.82004 X3 q/ P' u. s
15.3360 285.3600 11.6240 2.0800
# v, n6 s' b/ ^2 n 12.8160 295.3960 11.9280 1.9200
$ T2 |4 V( _3 _2 P* s 17.0000 300.7920 15.1080 2.5000, m3 C7 `. Q; l+ b$ j! ` \, ]/ r
16.2800 296.5760 15.4040 2.7200
^. t f8 [+ `1 A. t+ Y0 b0 n 15.5600 291.5120 12.8200 2.2200
q& ?3 }9 i! ? 15.3440 289.1520 13.8640 1.9600( b6 _2 b% S* l( ]" u1 f
17.3600 288.3760 14.1440 1.9600
' d* F, _7 |, C% e# O 14.7600 290.2400 14.4920 2.0400
7 e5 x& N a. _) x. J* M3 h+ y0 Q 15.6240 294.0520 14.8720 2.2400
, c' _' M t5 B4 E2 S* ] 14.5440 297.4480 18.4120 3.08002 U% ]- \( E8 V& j! u
16.4880 297.4160 17.7680 3.3600
- h* F. j& d: L9 z 16.0560 294.9120 14.1920 2.7400
! R( J7 Y& c- f7 q& u! g/ \ 13.6800 300.9440 14.5720 2.3800
0 a9 I. Q! o; _) s7 M2 | 13.3920 302.0360 14.5120 2.3600
" I/ }# a8 {# D$ P 15.4800 307.5560 14.4200 2.4200; `4 G# [8 `0 a
12.8880 303.6000 14.6480 2.40005 k: K$ |- Z' Z& n
12.8480 306.8360 18.2720 3.0600% S* @7 p& U. p; R. v+ D- G
14.3600 304.0480 17.6880 3.3600
% B+ E& x' ~# \$ c 13.7840 300.0320 14.1720 2.7200& @+ l/ w t5 g5 p
12.7760 301.1600 15.1240 2.1000
7 I( I* _7 G Z8 Q 12.9200 307.6480 15.5280 2.1200
. @2 ]$ ^4 Q; L0 J$ ` 12.8880 306.4080 16.0800 2.0400, m4 S+ x0 O' C+ j, K+ t$ C8 l: P
14.4000 300.1880 12.7560 1.8000
9 M4 A3 M4 e' y% a 14.1120 296.6520 17.1200 2.4600
5 o- D. E; u* z/ E 14.4720 290.6160 17.0080 2.8400
7 L* L$ ? N# D1 O1 x. j/ S) K 15.1200 287.3560 12.8280 2.26001 D/ l2 m! D2 O7 {; y) L1 S. O
14.6880 290.6920 13.2520 2.00005 u7 }) \9 m6 W4 a" D, v
13.6800 298.2680 16.7680 2.2800% M! [2 ~: u: l1 ~# J
%第一列为因变量，后面三列为自变量
$ W, g# G/ M: k U8 w>> y=A(:,1),x=A(:,2:4)
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y =
" x& U, q8 W( K# E' E8 e3 X, N1 f/ G7 ^# |$ R5 i5 b+ X; L
15.1200
- \, s/ y1 Z& B( D 15.4800
2 k7 y2 \& n+ m- j/ g 15.3360
. \1 x, n. J" \' p1 \ 12.8160- e2 o3 ^$ r$ S% i
17.0000
# \: T( P: m! X8 B- y 16.2800
" n# d% A; d" U O' R2 X9 j 15.56004 G3 ]6 ]0 J& K4 {$ e
15.3440/ [* A4 V' C3 P/ Q# N4 j8 o
17.3600' A9 R; K2 q' F, ?! t
14.7600$ j0 ~4 j3 w% N5 _0 r7 P* x
15.62408 n6 R) ^9 l4 l1 B* ^1 J$ V
14.5440
7 g) p/ s2 x% h) f. a 16.4880
; N: t& W# R& K. O% f/ ^$ L1 m) z0 O, C 16.0560
" Y& O- l! b1 L 13.6800
5 ?! {5 L& _$ t" }. e 13.3920
- B8 A6 C, h4 P2 d/ W' s 15.4800
) n5 [% _. T8 g, p( e$ B: t3 N F6 O& x 12.8880
! E1 f4 `+ `' s, } 12.8480* Y% S( ~' ^ l" c
14.3600
: R$ Z5 A- g: o 13.7840* m2 r0 [4 s0 P5 j" Y
12.7760
+ j, }, w ^5 u( S 12.9200* @; y' g2 K$ ]7 K6 ?
12.88805 T0 g: S9 a0 M* I3 l8 }
14.4000* ]+ ~+ X! h6 g: [
14.1120
$ {/ j* j6 X! w, P 14.4720
6 g1 ]/ a' h, m+ R+ C 15.1200, w. c% M+ E9 N/ f v& L6 m
14.6880
/ X! b. S% o% J+ P: L& O0 `6 N- T1 n 13.6800 T& g/ \+ K- L/ C
* ?7 V( ]9 S1 O
: t2 }+ G! O/ f; D6 r
x =
+ N8 j) K3 ~$ h- C; D& i6 u; ?# {- b* M
6 r9 C2 k1 J3 ` 272.5640 11.5880 1.9000$ R( M) m5 D" n$ X7 J& q
277.3200 11.2400 1.8200% O; b; ]' }/ P7 C$ e. p5 p
285.3600 11.6240 2.0800
! K# b0 X% [3 u 295.3960 11.9280 1.92005 D' K0 t# Z+ f! v
300.7920 15.1080 2.5000& u3 u9 a1 R8 Z0 b7 |4 A
296.5760 15.4040 2.7200
% x/ Y. y L( y 291.5120 12.8200 2.2200( H* E" l; M) W) j! L. n1 Q
289.1520 13.8640 1.9600$ p* X8 Q! Y! P, ~
288.3760 14.1440 1.9600
' k" X: S3 Z m 290.2400 14.4920 2.0400
6 n6 W! n! ?/ d. S1 ?7 |/ Y 294.0520 14.8720 2.24008 k+ ^" P5 {' U+ h& S1 w. e. s5 W
297.4480 18.4120 3.0800& N6 C- O O+ {+ P6 w; ?: T1 u, [
297.4160 17.7680 3.3600
* O$ G6 r) |% q. c. f- y 294.9120 14.1920 2.7400, T9 m0 T3 t/ B( u) Q4 P. z: w
300.9440 14.5720 2.38003 m7 C9 K6 x- f" w+ M& R" L& |& O
302.0360 14.5120 2.3600' m+ D0 Q0 b% J" i3 `0 Q
307.5560 14.4200 2.4200# E& e* q! e7 Z f1 w" p# k4 Z
303.6000 14.6480 2.4000& {$ w+ \$ Y. p1 |" F
306.8360 18.2720 3.0600! A6 i* j5 i5 s% }: \6 R
304.0480 17.6880 3.36001 Z/ j0 `6 w! ?5 |
300.0320 14.1720 2.7200
1 G5 o) N8 o9 z% f 301.1600 15.1240 2.1000
) y( {# }. D( |* N* U8 r7 ^ 307.6480 15.5280 2.1200
; d" N6 }# z5 C9 w 306.4080 16.0800 2.0400$ ]" i# \7 W' F2 G/ m' n9 p
300.1880 12.7560 1.8000
/ B& T1 J5 m+ [! B/ V1 ] 296.6520 17.1200 2.4600) K& V2 i' S/ J1 g. }
290.6160 17.0080 2.84004 @- x* w' M: z( e
287.3560 12.8280 2.2600
: _ K$ A7 r2 ] 290.6920 13.2520 2.0000
& m4 z K& f% }- h" V, Q- m* R+ | 298.2680 16.7680 2.2800
' p6 l" k6 v: e1 K. F/ T+ f
. w& |7 J+ ^3 l2 V' n) k>> B=regress(y,x)
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B =: m, y* `. {1 f$ ?1 X
0 P6 n5 C- n# m, l3 v% b4 {
0.0587. M2 Q+ a3 p- T& R& t) ~
-0.4411
/ d8 Y( I: D! s+ O3 ?9 F4 F% k$ j 1.5818
+ P' z! }7 x' ?
7 r* T& \# p* S$ @& Q请教大神，怎么对系数进行约束（0~1之间）。
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发表于 2020-7-22 09:43
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