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计算二重积分的时候,结果就是一个式子,不是积分值,这是为什么呢?求教5 T" t$ M* Z; Y- ?3 H" n' @$ l/ B
3 {! Y* E8 @; Y. ]; S+ U代码如下:
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! q. L( u( |6 H7 R- w; L9 Tclear all0 c9 {- I" T' I; b; j# `% d
close all( n+ f! e) e% C
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syms x y$ Y1 M* Y1 ?: r' P
omega=1;9 M+ g n& L2 Q
mu=0.001; B6 i( J; q: r) p5 I6 a
alpha=0.13;
1 ~3 Z/ }, T# lbeta=0.0031;
9 R# T3 D- Q* p: s3 A3 }; Zu=0.001;v=-0.02; ) Y- u$ i c0 k9 a* \
tau=2.2;tau1=1.5;D=0.11;/ Q* H- @5 c9 _) j
tau01=1.42;tau02=1.5;tau03=1.56;tau04=1.9;( X0 s# s. _0 b! D
omega2=1-u*cos(omega*tau)-v*omega*sin(omega*tau01);
7 F6 T9 n4 f3 o1 i) eeta=1+(1/mu)*(-(u/omega)*sin(omega*tau)+v*cos(omega*tau01));
- \7 q+ B5 S0 KK=D/(omega2.*(1+omega2.*(tau1.^2)));
" v2 U: Z$ ]9 {# ]$ j# |) tf1=(1./(omega2.*K)).*exp(-(mu./(1536.*K)).*(15.*beta.*(x.^2+y.^2./omega2).^4-32.*alpha.*(x.^2+y.^2./omega2).^3+96.*(x.^2+y.^2./omega2).^2-768.*eta.*(x.^2+y.^2./omega2)));5 |3 K) D+ C) a, y5 R# P, B6 \
F1=int(int(f1,x,0,10),y,-10,10)! b+ E Y2 X( w+ r4 r
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4 u! [5 t! P8 r' Q" N6 B' m- B结果:7 j$ [9 g; M" m' `
F1=
. _" j, n( t, r! p+ f9 rint(int((1029484437153*exp((76368780973521777*(x^2 + (2251799813685248*y^2)/2297649917499219)^3)/922337203685477580800 - (17623564840043487*(x^2 + (2251799813685248*y^2)/2297649917499219)^2)/9223372036854775808 - (546330510041348097*(x^2 + (2251799813685248*y^2)/2297649917499219)^4)/590295810358705651712000 - (3488543873076974433998624506509*x^2)/81129638414606681695789005144064 - (1162847957692324811332874835503*y^2)/27593854166072889506733609713664))/34359738368, x, 0, 10), y, -10, 10)4 ^8 F2 ?# B0 B. m
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