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当你出现如下错误:- `' @& `! ^( v: |
Error using sym/subs>normalize (line 201)6 U+ [: |5 G1 N4 r1 ] v# \5 T4 P9 N
OLD and NEW must have the same number of entries.
: g* s4 ?" f% w1 C% K% |+ f7 M% {% Y6 N5 z0 V8 e6 }$ c
Error in sym/subs>mupadsubs (line 136)1 q9 B# `! R' f0 B% Z3 ]5 x
[X2,Y2,symX,symY] = normalize(X,Y); %#ok1 }7 k' Z, s( j7 ]
0 u% U( V( X; v2 ~* x6 E A5 e" }" GError in sym/subs (line 124)
4 y: u* ], h6 W, X! n( Y3 ] G = mupadsubs(F,X,Y);
: }2 ^5 S3 V- z5 i( k6 z4 r3 m: `, E2 I+ R. G7 s/ O
Error in Funval (line 20)6 G! c5 u! l, w% U
fv = subs(f,varvec,varval);
/ ?+ `% y5 q2 p% L% x3 b- o7 t. m! K- ]4 H
Error in minNT (line 17)
& W! v* N. H I/ @! Q! S& u1 _/ s v=Funval(gradf,var,x0);; h" ^) x4 _8 w- L$ x
2 s" _& p; {1 JError in syong1 (line 4)
2 q) T$ G5 k. k' s0 O, t# l[x,mf]=minNT(f,[0 0],[t,s])7 G9 w/ G/ M0 B0 k1 m, x$ @
3 n! T9 z- w, K: U4 r- F
你该考虑矩阵是否对应的问题,也就是行列向量的问题
+ S8 r8 _- y4 U4 X其实问题就出在这个地方:
& F0 y7 y1 a9 w7 c8 |5 Cfv = subs(f,varvec,varval);中varvec是【t,s】而varval是【0;1】
: U ?, F j8 a, A1 A4 J: c所以正确的Funval如下:. [, V/ f# x) r$ S$ r
! W ?+ _3 z# E" o
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