了解一下C语言字符串的拆分函数strtok

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char *  strtok ( char * string, const char * delimiters );
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% x$ e5 N, b) T4 F6 ?( GSequentially truncate string if delimiter is found.
. X# A. d2 s" x: s. u: `9 p1 H4 ^6 C  If string is not NULL, the function scans string for the first occurrence of any character included in delimiters. If it is found, the function overwrites the delimiter in string by a null-character and returns a pointer to the token, i.e. the part of the scanned string previous to the delimiter.
  After a first call to strtok, the function may be called with NULL as string parameter, and it will follow by where the last call to strtok found a delimiter.
  delimiters may vary from a call to another.
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Parameters.

" z7 N8 q! r" ?string
Null-terminated string to scan.
% g7 t8 N% z- e" C, Cseparator
Null-terminated string containing the separators.
  m* R/ y1 c$ h- Q; X& ZReturn Value.
' T0 L" t, t0 t( l0 S; a  A pointer to the last token found in string.   NULL is returned when there are no more tokens to be found.

/ z, J% L! ~5 x( b& [( x! APortability.
/ \' C+ ~) r, }8 R3 h  Defined in ANSI-C.
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+ Z! T# W9 {3 M" O% d8 bExample.
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/* strtok example */
#include <stdio.h>
#include <string.h>

: M2 s7 C" Y: J8 h0 @+ \% Fint main ()
{
  char str[] ="This is a sample string,just testing.";
3 ]" U9 m/ t' D% l, N  Z  char * pch;
: Y+ D2 O9 V4 Z  printf ("Splitting string \"%s\" in tokens:\n",str);
+ Y$ c1 q2 a' l9 r  pch = strtok (str," ");
  while (pch != NULL)
! l, F$ }& w+ a& ]( g- w% Y  {
    printf ("%s\n",pch);
* ?7 R' U$ A# ^( h1 c/ @    pch = strtok (NULL, " ,.");
8 X. |4 e& x( s  \  }
8 n& p( g1 V5 A) b) R# i! a; G! K5 p" k  return 0;
}
: r% h/ U' H2 s4 W, cOutput:
Splitting string "This is a sample string,just testing." in tokens:
This
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8 h) k' `- x* r3 Gsample
string
just
testing

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了解一下C语言字符串的拆分函数strtok