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PCB 线宽与电流(PCB line width and current)
! o7 ?0 S+ e! [7 aThe withstand current of 1 square copper wire is 5 -- 8A, 380V can
4 y9 K; e3 ~% c- h% jbe brought with maximum 4KW, 220V can be maximum 2KW.
- e3 z, k; r" p/ l' N- e% Y2 square? Three square meters can be pushed like that6 X0 Z7 Z* c7 l
PCB line width and current relationship: y. } f% @8 O' V3 D
I. calculation method is as follows:# _5 K6 \; |8 G& k: Q
First, the section area of Track is calculated. The copper foil
" [& ^! m# `, E- J! ~: d8 Pthickness of most PCB is 35um (the PCB manufacturer can be asked if it* T! o& I0 J$ M9 @
is not certain). The width of the PCB is the+ o0 G# }) N$ K# R5 u% I# }
cross-sectional area. There is an experience value of current9 l& z6 N/ X, J/ c0 B
density for 15 ~ 25 amperes per square millimeter. We can just call it: a5 O1 {2 E' |' h ?
the area where we get the volume.$ q ]( O; I/ Y+ i% m0 R! S
I = KT0.44 A0.75 (K is the correction factor, which is 0.024 in the6 J. I6 ]; g$ l O7 t9 C8 Y+ }
inner layer of the copper line, and 0.048 in the outer layer)" J, [8 `5 e. ]1 b. i# j2 h
T to the maximum temperature rise, the unit for degrees Celsius
4 _( K3 O5 O) g, Y2 L* @(copper melting point is 1060 ?)
0 ]0 Z, Y2 @) a9 q( _8 KA to cover the area of copper, the unit is square MIL (not mm mm,
" |/ I o9 X! d# Vthe attention is square MIL.)+ W6 ]. E# r/ R, g5 F
I is the maximum allowable current, the unit is ampere (amp).
. H, M! o& H. i: f% DThe average 10mil = 0.010 inch = 0.254 May be 1A, 250MIL = 6.35mm,+ x: {! g' S- C3 \- P0 u+ ]
which is 8.3 A S/ | T; l9 A% j( Z R/ r+ o
& C* ]% W; a5 g
$ R( g% n0 v! _; \' a) [ D7 s
, r J$ N9 v, O" {+ N% ^6 x! t2 p
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