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有个问题请教大神。
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0 ^( _% T: I$ `+ y原程序& f8 E `6 \& C. ] d- n% B) r
4 R* i5 z6 E1 }, F( ~( ^( jmodule SPI(mcuWR,SPICLK,MCUDO,MCUDI,SPICS,SPIstart,rxdDATA);- b. ^( ?9 M) |, O6 `- F
input MCUWR,SPICLK,SPICS,SPIstart,MCUDO; //收发转换(高电平接收),SPI时钟,SPI使能,SPI复位,单片机发送7 V8 t2 p8 H$ z: p8 o
output MCUDI,rxdDATA; //单片机接收,接收缓存8 @7 d- `. Y0 n6 ^/ y0 |
reg MCUDI;
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reg [9:0] rxdDATA; //接收缓存 P& ^5 q1 ~: q3 j* x+ V# j
# U" O/ o: m- c; Y' Creg [6:0] Cnt;/ z; s: r) X$ q' N9 o1 _7 ]
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2 v% g) Z3 M5 }0 e5 h7 r+ ^4 @always @ (negedge SPICLK or negedge SPIstart)
* [6 q. E2 j% R2 ]( ~; Nif(!SPIstart) //SPI复位信号
. R1 N- L2 a/ A. s: M, X3 s/ ubegin
0 j9 p( x' |/ Y7 f3 u6 C- { Cnt<=6'd0;
/ Q6 E$ r# \* L. A rxdDATA<=0;
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else, ~: ]) P' }; }) D& N
begin+ @; b$ Q4 y7 r; [. j% b% p8 N: J0 T
if(!SPICS) //SPI低电平使能% n- w& I: Y8 j6 F; P2 L/ h- z
begin- u3 B4 u6 P/ f8 y) R( [
if(MCUWR) //切换为cpld接收
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Cnt<=Cnt+1'b1;6 h1 W* D! U0 [) Q# y$ h; N; b
case(Cnt)
& P6 p5 K, U% S 2'd0:
+ H$ c0 X7 l) }& d1 D9 F rxdDATA[0]<=MCUDO; k' P- H5 `* `0 v" R' z; ~
2'd1:
1 e7 g/ ?- _) T F3 g) h9 U rxdDATA[1]<=MCUDO;% {1 a6 d5 I& ?+ J! V! e5 s2 p* y8 g
2'd2:2 w/ m+ h. }8 y" b
rxdDATA[2]<=MCUDO;
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rxdDATA[3]<=MCUDO;
% O$ ~* k( d# u/ y8 h# j9 b 2'd4:
; g6 D; `) d' F( y rxdDATA[4]<=MCUDO;. w0 \6 o/ }- N9 `2 X
2'd5:/ X' V9 `4 W: e u' P" ?+ [
rxdDATA[5]<=MCUDO;) E* `- j/ k- v2 w1 D
2'd6:1 ^, | }( G: V3 c9 q3 d3 r
rxdDATA[6]<=MCUDO;0 k: G" E' H8 U# \) A* D
2'd7:
8 p# W3 T! p3 t& h7 N4 V& s1 A rxdDATA[7]<=MCUDO;3 [# w, Z! }/ k2 {" K$ r0 Y
2'd8:0 A* {& Q4 e( H! ^+ e
rxdDATA[8]<=MCUDO;) `% Z5 }) ?) q2 I* S
endcase5 \/ R% b$ Q0 p
end
* [) z- D1 E: \: z4 P- j# h1 x4 p9 I0 v end
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endmodule$ ?' |( z, o: V4 s7 p
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) O1 l6 s9 s9 a+ |测试程序:4 O& S+ Q% {' }' E
`timescale 1 ps/ 1 ps
9 D$ l/ k( ~! N4 V. T; D6 Xmodule SPI_vlg_tst();
6 b4 ^) b: S2 N$ V" Kreg MCUDO;
7 I) {$ P% i+ Yreg MCUWR;
: O# f9 q- _ I3 S- N+ ereg SPICLK;
1 o* S0 E" ?3 treg SPICS;4 B9 Y* o& W6 `+ Y! |/ M
reg SPIstart;
/ v: R6 v+ b' |& O2 ]9 I" `wire MCUDI;
* e# P6 k- ^. ]# K9 D2 ^) g0 bwire [9:0] rxdDATA;( H+ T4 N7 j* C7 W3 z
5 t0 d8 f2 b5 l" j( M0 E) s: a+ treg k;
0 X" K9 x4 }5 g1 r1 Sreg [6:0] testcnt;- H, s. c7 L8 s9 x
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; y1 P$ {# L4 } C6 y8 iSPI i1 (8 `- O2 }8 z4 l! f+ K
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.MCUDI(MCUDI),6 l5 H' W& {+ {+ D4 q, H5 g
.MCUDO(MCUDO),; ^7 c. a) j8 s9 v8 j9 Z" l
.MCUWR(MCUWR),
9 k. }1 [0 Q% H7 t4 k0 E .SPICLK(SPICLK),
" p/ J$ \) H- Q; U F .SPICS(SPICS),, y5 O( f2 t& ^" I' U
.SPIstart(SPIstart),4 @$ A* ^6 z- V& S6 Z, U
.rxdDATA(rxdDATA)
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initial 1 X' o% W/ A8 h2 G) C! P7 F& H: {
begin & w/ |0 f, _8 D; G' x
testcnt<=0;- p* f; m0 B! @* a, d
SPIstart = 1;1 P8 k+ G/ C) `2 c6 t d! A
#10 SPIstart = 0;* y8 I6 \6 t6 a; y) D' ]7 n8 l
#30 SPIstart = 1; //产生SPI复位信号 % ?4 q% C9 I& M. Q I& q( k* H
end 2 d5 ~3 |) s V1 d/ C7 _5 i
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initial
+ i# ]* P8 `+ k/ G Lbegin " K# j% \( ~: ~" A8 ?
SPICS = 1; p B' a5 J2 L
#30 SPICS = 0; //产生SPI使能信号- G3 @: |5 S0 ~0 v
end
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initial
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MCUWR = 0;
" f# X* a& j$ l#30 MCUWR = 1; //产生CPLD接收使能信号6 `9 A+ g5 a' R# T
end
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initial; i: @! W ~7 C- f
begin " B0 Q$ T) i) b% K
SPICLK = 0;
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for(k=0;k<29;k=k+1); v) T* W* T Y! _2 i/ [, V! b
begin
# H% n' f; D/ j2 z' Z n0 t, I, `#10 SPICLK = ~SPICLK; //产生SPI时钟信号
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2 \1 ]0 r! n. N# c. uend
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8 z5 J! m: d# O7 }( Lalways @ (posedge SPICLK)2 E% F, I7 e' x! C0 ]
begin
0 n) d7 L$ |1 y' c' I4 n; U testcnt<=testcnt+1'b1;2 ^5 H) e; x3 M0 q( z5 |& I
case(testcnt)
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begin 5 N0 _% v3 K% s& K+ R6 v- R2 P
MCUDO<=1'b1;
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begin
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' Z# b8 x+ d9 m- X end
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begin 4 |2 x; R% i0 y. t% [
MCUDO<=1'b0;: j. L& v6 d% C( e
end - F. Q) y" K) j
6'd3:3 {& V/ Y& b) \+ h, D6 m% p I; O
begin
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end 7 m" `4 {' Z+ t* k
6'd4:% l+ K! a" |1 K' z
begin
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$ I% `" @3 w( n# r: {, e4 o end
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begin
* W/ P. b% ^% m% q5 C+ y% t8 | MCUDO<=1'b1;
3 L [$ |& I6 t end
/ N9 P8 g+ j. ]; G! w0 R8 q 6'd6:
0 D- c6 a% x( H9 D7 m( \6 Z$ L begin
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end 8 A" s$ U+ r5 p# F: H
6'd7:- x2 h& w5 A4 ]) N# t. ^3 X- d
begin
9 F9 b; b- Q9 Y: A" w MCUDO<=1'b0;5 ~) C) B: I w) x5 Y
end
' G/ t4 } \1 z4 ?0 O5 _ 6'd8:6 F5 Y6 I! v# w% E2 \! v- f
begin
( D8 [3 `1 r4 Y& T3 F MCUDO<=1'b0;
# ]/ ]$ T# c% L( a, k end
: I& ]$ X0 Y" \2 b+ y3 {6 C endcase
& u) Q) V d( R3 s end
. u$ c! r# Y4 Oendmodule. }; h1 x9 g- l" j2 S4 P' Z: ~
从MODELSIM仿真出的波形来看,rxdDATA[5],rxdDATA[6]在testcnt为5和6时分别应该为高电平,可仿真结果 却一直是低电平,恳请各位大神帮我分析下,代码是否有什么问题,非常感谢!
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