ADC数字校准中，在testbench可以用小数分数的形式用于计算？

sunygd · 发表于 2019-3-28 14:37

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parameter  FS    = 268435456,//2^wid_des,

         FS_half =  FS/2,//2^(wid_des-1),
         //produced by baoqq 20161103//as matlab *.m,// initial in *.m//version first
         G1 = 2.2503,//1.759 ,//1.7839,//1.8181,//1.8054,
         G2 = 2.1226,//2.3075,//2.3567,//2.384, //2.3814,
         G3 = 1.8970,//2.3075,//2.3365,//2.384, //2.3911,
         G4 = 2.4982,//2.3075,//2.4311,//2.384, //2.3713,
         G5 = 2.0761,//2.3075,//2.4938,//2.384, //2.3607,
         G6 = 2.1416,//2.3075,//2.4131,//2.384, //2.3643,
         G7 = 2.1416,//2.3075,//2.5761,//2.384, //2.4490,
         G8 = 2.1416,//2.3075,//2.5761,//2.384, //2.4490,
         G9 = 2.1416,//2.3075,//2.5761,//2.384, //2.4490,
         G10 = 2.1416,//2.3075,//2.5761,//2.384, //2.4490,
         G11 = 2.1416,//2.3075,//2.5761,//2.384, //2.4490,

         FS_3_8 = FS*3/8    ,
         FS_2_8 = FS*2/8    ,
         FS_1_8 = FS*1/8    ,
         FS_1_16= FS*1/16    ,
         VFS_3_8 = FS_half*3/8 ,
         VFS_2_8 = FS_half*2/8 ,
         VFS_1_8 = FS_half*1/8 ,
         VFS_1_16= FS_half*1/16;

always @(*) begin
if(PD) begin
   vout1 = 0;
   vout3 = 0;
   vout5 = 0;
   vout7 = 0;
   vout9 = 0;
   vout11 = 0;
end else if(PH2) begin //PH2e)
   vout1 =vld_12 ? (vin1 -(D1 -3.5)* FS_1_8+t_pnS1 * FS_1_16)*G1 : 0;
   vout3 =vld_34 ? (vin3 -(D3 -3.5)*VFS_1_8+t_pnS3 *VFS_1_16)*G3 : 0;
   vout5 =vld_56 ? (vin5 -(D5 -3.5)*VFS_1_8+t_pnS5 *VFS_1_16)*G5 : 0;
   vout7 =vld_78 ? (vin7 -(D7 -3.5)*VFS_1_8)*G7  : 0;
   vout9 =vld_9a ? (vin9 -(D9 -3.5)*VFS_1_8)*G9  : 0;
   vout11=vld_bc ? (vin11-(D11-3.5)*VFS_1_8)*G11 : 0;
end
end

yxlk · 发表于 2019-3-28 15:20

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ADC数字校准中，在testbench可以用小数分数的形式用于计算？

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