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这段文字如何理解呢?为何会进入亚稳态?

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    2020-1-14 15:59
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    发表于 2007-12-18 21:19 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式

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    这段文字如何理解呢?为何会进入亚稳态?
    + }0 \$ Q! [4 a7 z" [& \: |2 U
    ' ^$ S2 V. Y# \) k, _If the asynchronous reset is released at or near the active clock edge of a flip-flop, the output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
  • TA的每日心情
    擦汗
    2020-1-14 15:59
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    [LV.1]初来乍到

    2#
     楼主| 发表于 2007-12-18 21:50 | 只看该作者
    The biggest problem with asynchronous resets is that they are asynchronous, both at the
    4 U8 Q' N9 B0 p* I; E; @  ^assertion and at the de-assertion of the reset. The assertion is a non issue, the de-assertion is the* x% ?3 j4 Z7 I: e7 \: P9 Z
    issue. If the asynchronous reset is released at or near the active clock edge of a flip-flop, the# F5 j+ w5 J5 ?
    output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
    ' ?% H% R; k$ Z* x1 O3 EAnother problem that an asynchronous reset can have, depending on its source, is spurious resets
    + W# g: x: [* W& X& o$ Y  Ndue to noise or glitches on the board or system reset. See section 8.0 for a possible solution to, S, a2 f% y$ C. ~; ]+ ^: x
    reset glitches. If this is a real problem in a system, then one might think that using synchronous* T9 b  E! L+ r8 z2 c+ m4 d
    resets is the solution. A different but similar problem exists for synchronous resets if these
    ( _# R; A; F1 O% M/ X: Rspurious reset pulses occur near a clock edge, the flip-flops can still go metastable (but this is+ K% Z* F- p) p( l! a9 `
    true of any data input that violates setup requirements).
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