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这段文字如何理解呢?为何会进入亚稳态?

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    2020-1-14 15:59
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    发表于 2007-12-18 21:19 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式

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    这段文字如何理解呢?为何会进入亚稳态?& o0 ]/ m- D9 b  \

    1 f- I5 j5 X6 \9 e2 Q; \If the asynchronous reset is released at or near the active clock edge of a flip-flop, the output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
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     楼主| 发表于 2007-12-18 21:50 | 只看该作者
    The biggest problem with asynchronous resets is that they are asynchronous, both at the
    0 g3 U" r2 r0 H0 ]* R+ M( Y* Lassertion and at the de-assertion of the reset. The assertion is a non issue, the de-assertion is the
    " X9 `0 ~5 {5 ^- n  v$ p* dissue. If the asynchronous reset is released at or near the active clock edge of a flip-flop, the
    3 h# N1 x. B/ u  B4 E) V0 ^output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
    ' T* @, z3 n) [' |6 uAnother problem that an asynchronous reset can have, depending on its source, is spurious resets( q+ |% l- Q/ k3 i0 n! {3 w! l3 K% H1 z" [
    due to noise or glitches on the board or system reset. See section 8.0 for a possible solution to- N9 }+ P. g. K7 W
    reset glitches. If this is a real problem in a system, then one might think that using synchronous
      Z# _  ?( d4 ]) l' yresets is the solution. A different but similar problem exists for synchronous resets if these
    1 Z  H# `9 P3 s( Hspurious reset pulses occur near a clock edge, the flip-flops can still go metastable (but this is
    $ y7 n" D6 _& dtrue of any data input that violates setup requirements).
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