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PCB线宽与电流(PCB line width and current)

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发表于 2020-2-17 15:30 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式

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PCB 线宽与电流(PCB line width and current)% ?& B# I+ V5 w; X% C8 q
The withstand current of 1 square copper wire is 5 -- 8A, 380V can
( g( {/ h& l4 i& a6 `6 v& H# S, Bbe brought with maximum 4KW, 220V can be maximum 2KW.
& ~; @, ^+ I2 W- [& H/ ?5 q2 square? Three square meters can be pushed like that
3 g# M: p; Y. R9 |6 U; V, R+ mPCB line width and current relationship
* e4 f# u- |- o* p& G& a3 v! ]' _$ aI. calculation method is as follows:
) K6 V9 ]( T9 [3 F" zFirst, the section area of Track is calculated. The copper foil
) d- f* z7 O0 W  \thickness of most PCB is 35um (the PCB manufacturer can be asked if it  r& f! Q. ^8 b1 `
is not certain). The width of the PCB is the- s0 c8 w0 w) {1 P, a
cross-sectional area. There is an experience value of current
% `3 _# P1 D' `( Qdensity for 15 ~ 25 amperes per square millimeter. We can just call it
1 H; R# @4 p! S2 S/ }. N- N9 cthe area where we get the volume.  l4 _; J7 ]& R, }' C
I = KT0.44 A0.75 (K is the correction factor, which is 0.024 in the& Y: A; R" G/ B  l2 `9 m& Y
inner layer of the copper line, and 0.048 in the outer layer)2 ~7 |) s% D; w6 m7 j$ e9 f- ~
T to the maximum temperature rise, the unit for degrees Celsius$ }! p' C5 b  a
(copper melting point is 1060 ?)+ b+ N: \9 ^' q& ^$ @; }8 o
A to cover the area of copper, the unit is square MIL (not mm mm,9 T1 \  W- i* x& g! A; U
the attention is square MIL.)8 l; o- S$ a0 M& E5 @. q; X
I is the maximum allowable current, the unit is ampere (amp).
+ d- H- w4 A* z, e5 [. YThe average 10mil = 0.010 inch = 0.254 May be 1A, 250MIL = 6.35mm,
4 V9 x. Y" P$ h$ A# q) f* `1 Fwhich is 8.3 A  6 U6 Z3 r: _# M) V/ ]7 C) E' R
0 n8 O8 F5 k9 e9 u+ ]
3 p, |/ q8 E2 P: F  k+ m
) O( `. f% X. i. O! J3 Y, \. E
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发表于 2020-2-26 14:30 | 只看该作者
PCB线宽与电流

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3#
发表于 2020-3-3 14:24 | 只看该作者
学习一下,谢谢。1 X% K4 o+ L$ \; G
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