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这段文字如何理解呢?为何会进入亚稳态?

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    2020-1-14 15:59
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    发表于 2007-12-18 21:19 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式

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    这段文字如何理解呢?为何会进入亚稳态?
    3 m( _! ]2 E$ S
    ! T; K. u4 w( M: B- [( LIf the asynchronous reset is released at or near the active clock edge of a flip-flop, the output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
  • TA的每日心情
    擦汗
    2020-1-14 15:59
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    [LV.1]初来乍到

    2#
     楼主| 发表于 2007-12-18 21:50 | 只看该作者
    The biggest problem with asynchronous resets is that they are asynchronous, both at the
    $ ]. X; F/ q# X' O# lassertion and at the de-assertion of the reset. The assertion is a non issue, the de-assertion is the
    7 J6 L+ p/ k2 B9 E3 aissue. If the asynchronous reset is released at or near the active clock edge of a flip-flop, the7 J( T! v2 W8 v3 D; j8 Z9 F- t
    output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
    , t1 ^# P* n2 t# BAnother problem that an asynchronous reset can have, depending on its source, is spurious resets
    9 G2 V  \0 i  ^3 ~  G9 idue to noise or glitches on the board or system reset. See section 8.0 for a possible solution to
    . B7 r- y7 V2 d  u% }# S" Kreset glitches. If this is a real problem in a system, then one might think that using synchronous
    ( R, N# K6 F2 g# `9 j/ A8 ^+ Fresets is the solution. A different but similar problem exists for synchronous resets if these
    7 O8 _, M+ `! e7 _8 o+ Tspurious reset pulses occur near a clock edge, the flip-flops can still go metastable (but this is% }# T" B0 A/ X3 g) L
    true of any data input that violates setup requirements).
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