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大家好，我从Excel中引用一组数据，进行三元线性回归拟合。利用regress，得到系数可能会为负数。请问如何对系数范围进行约束（0~1之间）
) U" _: j, Z# f, v) o下面是我的数据和过程
s. n9 r- Y4 Q9 B& BA=xlsread('G:\提油率测算20200704.xlsx',4,'H156:K185')
( S/ A5 h3 _% C, }2 b/ l
" M" M" ?3 o/ s# {" j/ v, A2 `A =
! f7 J, h* n) k$ P' T* |5 _4 v" H2 w8 O$ L# h. T( T/ D) S
15.1200 272.5640 11.5880 1.9000
% E1 `3 j( b: s, ?! G; m$ `. d 15.4800 277.3200 11.2400 1.82000 B9 o( K- b- F- E2 A1 \
15.3360 285.3600 11.6240 2.0800
4 l6 \3 }* q. s$ J" K 12.8160 295.3960 11.9280 1.9200
2 Y0 X9 }; Q3 x/ M 17.0000 300.7920 15.1080 2.5000# J! d; x; A4 A9 J% y
16.2800 296.5760 15.4040 2.7200
' \2 g$ W7 H- A3 c+ s3 c 15.5600 291.5120 12.8200 2.2200& S" j0 J9 A# I2 r- X+ w
15.3440 289.1520 13.8640 1.96004 C- y6 T* v' p- H
17.3600 288.3760 14.1440 1.9600, x9 z e% C9 e: G! T( V2 ?
14.7600 290.2400 14.4920 2.04001 Q3 _* I( z" P% b
15.6240 294.0520 14.8720 2.2400. H: O2 o- w" Z2 v$ k+ p
14.5440 297.4480 18.4120 3.0800
4 I7 e4 r& a c V/ a# @) G/ c 16.4880 297.4160 17.7680 3.3600
. w' F) T r' G) T: S& n; }' S 16.0560 294.9120 14.1920 2.7400/ d$ M0 W1 Q1 ]: p" T ?$ t7 D2 ^
13.6800 300.9440 14.5720 2.3800
9 ?9 v2 J: b, y1 I% N5 Q 13.3920 302.0360 14.5120 2.36007 i! [, p! k, O3 D1 u" H0 ^$ a
15.4800 307.5560 14.4200 2.4200; m/ K, {( ?0 v4 Q3 s7 }0 j$ @
12.8880 303.6000 14.6480 2.4000
/ B K2 C/ ?& E 12.8480 306.8360 18.2720 3.0600
/ S. ^; v H, \# d! i* ? 14.3600 304.0480 17.6880 3.3600 G" j' a' {: C3 }3 G3 r* ?
13.7840 300.0320 14.1720 2.7200" c4 `5 p. B6 z6 m
12.7760 301.1600 15.1240 2.1000
" U7 z0 k5 O$ f7 s& p: p/ ~ 12.9200 307.6480 15.5280 2.12007 u) b8 A5 Z: m- m9 A+ Y3 K
12.8880 306.4080 16.0800 2.0400
$ g, g9 K5 Y }. [" t. n/ i 14.4000 300.1880 12.7560 1.80007 b" g" s* ~. C" W: F7 ^& e: V
14.1120 296.6520 17.1200 2.4600. j3 h1 u. m. ~& G, \! ^2 ~
14.4720 290.6160 17.0080 2.8400 h7 @* ]6 l0 }
15.1200 287.3560 12.8280 2.26003 g; Z( Y7 _) K' {; l* B% P. P0 w
14.6880 290.6920 13.2520 2.0000
# q" v$ X& a2 T4 e3 l, `: n 13.6800 298.2680 16.7680 2.2800
$ K0 W8 n! j3 X" x, `+ k, L$ a%第一列为因变量，后面三列为自变量
; _: S7 @( e4 Z3 M9 G' ^>> y=A(:,1),x=A(:,2:4)! L8 n/ O- O, B" A/ B: L" q
1 w# ~! Y5 I$ }4 e& i- c6 by =3 x) @ q$ ]/ Z$ a$ e+ ~. T
: N3 F) M$ s, V5 t0 Q
15.1200
7 l' M g G( I }( ] 15.4800% M3 R2 p3 o' A* O9 M' ^! w3 c: f
15.3360; c ] n, u" }- K6 K7 s
12.8160
7 ]! G& v% l, n, s 17.0000" R6 I' T# r$ N! E7 e0 S1 j+ Y" E
16.2800! r' j' V2 X" b$ v* j; v8 C
15.5600
! m- G0 W, Y/ i 15.3440
' U N8 F7 h& l. Y 17.3600: g4 T! p$ N1 W! g# z' k' g' k$ b& M2 f
14.7600 Q# {, C. f- O; m6 R2 e% H
15.6240
: G" r, M" d# R+ C 14.5440
1 m5 t, r9 ]3 K& f. L% g1 X 16.48809 d0 U% j9 T: G F3 C, @" c
16.05606 T+ O' `. \; v$ g7 |
13.6800
4 t2 q4 Y! F5 C. S) @+ `( N5 ~ 13.3920
( {9 O0 n/ ?6 J* p$ Q 15.4800& p3 [" }7 ?2 j- _
12.8880
0 I; I0 R* u9 ?1 A 12.8480
( u. r/ B* J: K8 h 14.3600
( f: f. G0 S3 j% |0 j( e5 v$ N 13.7840
6 O0 w' X1 ^! O 12.7760
7 b* ~- t! i+ C! g6 D& }. H1 z# Q 12.9200
* T3 n' U9 V, M! j$ [! \ 12.8880$ F, l# [# a6 I$ G9 h1 K; F
14.4000
' _. W$ V. z/ z, m5 X: \- y 14.1120
k, V+ i+ X. m0 u 14.47203 d) B8 y; I5 j: f, j$ D# j
15.1200
+ H' R9 a- A7 o; J$ I 14.6880
! v9 ^1 Q/ x6 p% f4 t4 g0 L/ _' E0 x+ Z 13.6800
( ~9 c/ X8 e+ h& q( C8 a) n
D9 S( O! I! [6 G' Q2 t2 o8 R9 [/ O4 _1 D
x =0 _+ x* u: ?- I
9 M+ f8 D2 J" C9 \3 B 272.5640 11.5880 1.9000; d9 z0 ]4 N9 l. C8 O" n
277.3200 11.2400 1.8200
I6 A7 N6 u' y$ u3 k1 i$ \! R 285.3600 11.6240 2.0800
! d$ ?( z9 y# v 295.3960 11.9280 1.92002 ]! p7 W7 o' L2 E+ r; ^. p
300.7920 15.1080 2.50004 w+ Z7 B. v" C* `6 J
296.5760 15.4040 2.7200: {5 v* I8 O' c$ V8 J
291.5120 12.8200 2.2200
$ u0 m0 l* _, B/ n' w 289.1520 13.8640 1.9600% G; M% ]1 c& M @. Y+ _3 ?4 ^
288.3760 14.1440 1.9600
4 `$ E6 P$ o. L 290.2400 14.4920 2.0400; d/ E7 x9 t3 G" T+ @# v" [
294.0520 14.8720 2.2400
3 n0 p) B8 e: j" Y0 V3 T4 o+ G! c3 Q 297.4480 18.4120 3.0800% \6 T8 K' C) S0 L- {
297.4160 17.7680 3.3600
9 ]& P- z7 v- [% Y4 ^6 d 294.9120 14.1920 2.7400
+ H& E8 e% ]/ H 300.9440 14.5720 2.38001 K! N& G4 c: D3 g/ z. f) L4 y
302.0360 14.5120 2.3600
- ]* k7 A4 R; G' w( P 307.5560 14.4200 2.4200, Z9 t0 @8 }" g; b7 c) `
303.6000 14.6480 2.40007 E6 d& {% Y" a
306.8360 18.2720 3.0600 F; | I7 v2 [4 O* D2 P
304.0480 17.6880 3.36005 ]) b, F% f. v1 L9 W; ]) k
300.0320 14.1720 2.7200
0 g8 p3 Q* k* }6 C 301.1600 15.1240 2.1000
2 n3 e* a. t' E" z8 F( e 307.6480 15.5280 2.1200' c1 X! S3 i9 Q- S5 x
306.4080 16.0800 2.0400' h. Z; i* P% O
300.1880 12.7560 1.8000
. x& K: e8 }0 V# a! V I, l* v 296.6520 17.1200 2.4600- Q* S( U5 h/ w5 i3 L: p7 S0 I
290.6160 17.0080 2.84005 N; ~+ f V' ^- N) A$ d2 Z
287.3560 12.8280 2.26004 w9 n) r! K9 t7 v9 H. n. }
290.6920 13.2520 2.00001 V5 @( h" h' q) W4 z; z" Q! g
298.2680 16.7680 2.2800+ t! }( f3 y8 v% { B
! u9 B( X6 `! P. } W: e& g/ _7 }>> B=regress(y,x)
: A. u; d/ U$ a1 G6 X. G' O* L: [" h( u( A
B =
8 g7 ?' G2 F# G% c) d3 b1 P n
~) q( I! u# S9 T/ }# c8 O p6 S3 y 0.0587! m0 z [/ i6 d4 Y. ~
-0.44118 u7 D8 q( ^- t3 h% v8 U7 E1 {
1.5818
F- A7 e1 y6 m
. s' L, y4 D7 V9 ]$ _请教大神，怎么对系数进行约束（0~1之间）。9 i1 k: [7 [6 F, B
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发表于 2020-7-22 09:43
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