PCB线宽与电流（PCB line width and current）

ddddaaaaa

PCB 线宽与电流(PCB line width and current)
The withstand current of 1 square copper wire is 5 -- 8A, 380V can
) P* S: f! L" v8 i% [be brought with maximum 4KW, 220V can be maximum 2KW.
2 square? Three square meters can be pushed like that
0 B  b& r" W" QPCB line width and current relationship
I. calculation method is as follows:
1 l. g* b, T% ?First, the section area of Track is calculated. The copper foil
; B. a/ I2 M3 t- i5 Zthickness of most PCB is 35um (the PCB manufacturer can be asked if it
0 N, l' Q# f2 ^4 k3 ?" sis not certain). The width of the PCB is the
cross-sectional area. There is an experience value of current
density for 15 ~ 25 amperes per square millimeter. We can just call it
- \& U- w* v$ Uthe area where we get the volume.
I = KT0.44 A0.75 (K is the correction factor, which is 0.024 in the
inner layer of the copper line, and 0.048 in the outer layer)
2 R* {/ ?3 [: ?2 b3 Q3 k6 GT to the maximum temperature rise, the unit for degrees Celsius
3 P  `! Y4 k+ h0 v7 I(copper melting point is 1060 ?)
# ]/ S* o6 i. M) a. W# nA to cover the area of copper, the unit is square MIL (not mm mm,
the attention is square MIL.)
! p2 `2 b4 [5 ^, R% K* V, d8 ]I is the maximum allowable current, the unit is ampere (amp).
The average 10mil = 0.010 inch = 0.254 May be 1A, 250MIL = 6.35mm,
which is 8.3 A  
, Z9 i3 S* @3 `

' J9 t/ Q( v1 c
/ A, Q, f1 f  e/ h

游客，如果您要查看本帖隐藏内容请回复

1 ~) a+ \& u! _1 O4 e$ u2 M

ExxNEN

PCB线宽与电流

lqf

学习一下，谢谢。
5 N* ?: f" j# d# G/ P$ |0 `