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这段文字如何理解呢?为何会进入亚稳态?

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    2020-1-14 15:59
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    发表于 2007-12-18 21:19 | 只看该作者 回帖奖励 |正序浏览 |阅读模式

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    这段文字如何理解呢?为何会进入亚稳态?) t. R5 V! a# ~

    0 k5 t8 ~' l0 q4 G3 ^) LIf the asynchronous reset is released at or near the active clock edge of a flip-flop, the output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
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     楼主| 发表于 2007-12-18 21:50 | 只看该作者
    The biggest problem with asynchronous resets is that they are asynchronous, both at the- E( L( M, x5 t/ x# ?: O9 ?
    assertion and at the de-assertion of the reset. The assertion is a non issue, the de-assertion is the7 ]3 u& h2 M: _) X: b1 G( W
    issue. If the asynchronous reset is released at or near the active clock edge of a flip-flop, the
    4 F! I0 T* x8 s; i/ Xoutput of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
    - ^3 v: a7 G" R+ l( c# X" mAnother problem that an asynchronous reset can have, depending on its source, is spurious resets
    % t, J! T0 \1 `% P. wdue to noise or glitches on the board or system reset. See section 8.0 for a possible solution to( u9 G$ J3 w! H# ]' C
    reset glitches. If this is a real problem in a system, then one might think that using synchronous- g% k- W& o8 q2 G  S% R
    resets is the solution. A different but similar problem exists for synchronous resets if these4 |- O1 A( y0 ~
    spurious reset pulses occur near a clock edge, the flip-flops can still go metastable (but this is
    + D3 O/ o7 y& ^% d: V$ b# r1 htrue of any data input that violates setup requirements).
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