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大家好，我从Excel中引用一组数据，进行三元线性回归拟合。利用regress，得到系数可能会为负数。请问如何对系数范围进行约束（0~1之间）5 s3 V* p* P# S5 q
下面是我的数据和过程
1 Q) C1 G, A9 H2 A+ M: o: Z6 DA=xlsread('G:\提油率测算20200704.xlsx',4,'H156:K185')* F F$ I0 v9 {: {& h6 M
; ]9 E8 h z' w, ^: W
A =
, @3 R% T( U3 O; S
/ i* V) d! W3 C9 e3 |: v 15.1200 272.5640 11.5880 1.90002 A# e7 P$ M. E& \% r9 l
15.4800 277.3200 11.2400 1.8200: n4 O. R% H9 t3 ^& [! s+ D
15.3360 285.3600 11.6240 2.0800# g. V- v N/ t" q- F
12.8160 295.3960 11.9280 1.9200* K( V+ v7 u D1 [% q/ {7 X" a
17.0000 300.7920 15.1080 2.5000; `7 k; I6 I$ E X
16.2800 296.5760 15.4040 2.7200
* {; D$ V* @# N8 W5 y9 J; f 15.5600 291.5120 12.8200 2.2200$ J4 o% Y: n4 O
15.3440 289.1520 13.8640 1.9600( s' ]) A- `0 _, j
17.3600 288.3760 14.1440 1.9600' Q+ p! d0 ~6 s* ]
14.7600 290.2400 14.4920 2.0400
3 j. N" d' x. W 15.6240 294.0520 14.8720 2.2400
2 v/ N2 W0 t$ r. S, b4 X 14.5440 297.4480 18.4120 3.0800 N: ?! {: \1 ~
16.4880 297.4160 17.7680 3.3600- P; n" }. V5 z; ~+ i0 t
16.0560 294.9120 14.1920 2.7400
0 c+ ?. @+ y: g 13.6800 300.9440 14.5720 2.3800
5 p/ a: C. _5 [/ h3 A+ Z 13.3920 302.0360 14.5120 2.3600
" h% G9 a8 \6 p: t1 ~; {2 P& L* L N( N 15.4800 307.5560 14.4200 2.4200
% M1 [, U: [# {: c+ ]. x% i 12.8880 303.6000 14.6480 2.4000+ _: L" [8 Y3 |8 R& H$ i, c$ U
12.8480 306.8360 18.2720 3.0600
# ]2 k' G$ x* C9 w6 z 14.3600 304.0480 17.6880 3.3600
) X% x) B3 |7 J5 o3 z, t 13.7840 300.0320 14.1720 2.7200, _( h* M" z" B, I- a
12.7760 301.1600 15.1240 2.1000% O2 N$ e) H, A# ?; ]8 d
12.9200 307.6480 15.5280 2.1200
2 O. G( M, ~8 T9 V- I5 }3 I 12.8880 306.4080 16.0800 2.0400" U8 e: {+ i4 R
14.4000 300.1880 12.7560 1.8000
0 F5 y- A3 d) m( Y 14.1120 296.6520 17.1200 2.4600
) M" J6 x# f& c$ { 14.4720 290.6160 17.0080 2.8400, B) A) s. r* q4 d/ n
15.1200 287.3560 12.8280 2.2600
+ [. J3 s$ h3 ]9 V E# ~ 14.6880 290.6920 13.2520 2.0000. k+ ^+ d, l4 M
13.6800 298.2680 16.7680 2.28004 t0 S# |2 ^6 y0 x& W$ p
%第一列为因变量，后面三列为自变量8 u5 ]- [- y) k) @2 v
>> y=A(:,1),x=A(:,2:4)
2 M. M9 D8 w6 O/ Z$ [( ^( L+ R k% a- J& U' h$ v! Q
y = Q) h0 }0 K9 D+ r. `
- p" x- {7 v( a, Q* i! d' ^
15.1200
$ u2 @% ^+ I0 B9 k! i 15.4800) O5 J! X* t" a6 h. G! p
15.3360
, x. y; Z5 E6 ~3 T5 |/ r 12.8160 c+ @% u% U, v* B3 J3 V
17.0000
0 I5 R5 l5 g# i J. \6 X& k 16.2800" [" Z: Z* a Q6 s# n
15.5600
W6 j3 A- \# m n3 ]+ j* C* M 15.3440
6 k5 ^0 C. p/ v1 `. Z" A& y9 T 17.3600
, a4 s& E1 v2 Q7 A% l k 14.7600
& g( G7 J9 n: x0 {) o; N 15.6240" R# n: C+ ^% a5 T, S$ L2 g
14.5440
/ F* s. X9 B& u 16.4880( G! E) O1 A9 u
16.0560
8 i2 {% K+ d. N- h% |/ V, m2 V/ { 13.6800- q0 H& V9 h w0 {' D( D
13.3920
: K: a+ r2 e2 } 15.4800
+ I8 g# g1 x; o8 r5 A' S7 { 12.88806 O3 L3 O/ b3 C) O
12.8480- v; l% ^4 x+ U7 V# q2 [
14.3600
2 J3 }. ^# X8 n6 O9 } 13.7840$ n! s6 j0 l; F6 a! H1 [# F
12.7760
$ _# `( s. e% c0 B. R 12.9200
4 V, F* J$ a: ~5 [" ] 12.8880: e9 A$ M- ^6 q5 ~$ V a, p4 j+ J# P
14.4000
7 ]9 {3 ] k" ~& V' \/ ~9 E 14.1120. P( g8 m, n @/ @: Z J
14.47204 c" }- `. c$ g ?7 d
15.1200
" S) [1 p; h3 J4 I9 A6 T5 O 14.68808 | U, h, U/ k1 x# Q5 T
13.6800
4 D# ^2 x! D- E# Z& T! c) y- O) x- F" x0 n- Z0 i
1 a; q" p, L' @4 p O' M0 y! Z
x =5 ?9 e$ W) Y- _
1 W- Z% {# N5 Q2 K& R$ ~
272.5640 11.5880 1.90008 `, ]$ @ q1 o( |- l% \
277.3200 11.2400 1.8200
& Y1 @6 l8 s3 i( a6 @; Z+ Y 285.3600 11.6240 2.0800 q( M8 M7 s6 o2 t; }
295.3960 11.9280 1.9200
5 |. b0 l7 v* X* C- s 300.7920 15.1080 2.5000
7 W) h S7 @) {* c) B1 [: t9 W 296.5760 15.4040 2.7200
4 Z: P* m; J& _4 Y+ S5 [7 } 291.5120 12.8200 2.2200
; R4 Q) g' x" n; L+ V! i 289.1520 13.8640 1.9600
2 Y. j/ `* r' U& L( b3 o6 R 288.3760 14.1440 1.9600
. _ q; ~. f" z- X, ? 290.2400 14.4920 2.0400' f3 G2 |- ^6 w! {
294.0520 14.8720 2.2400
Z2 U' j+ b, [7 l* \, X# n 297.4480 18.4120 3.0800$ N: C! D5 h9 ?7 X1 u/ a8 z( A Q2 U
297.4160 17.7680 3.3600
' x; Q6 E$ Z; K, ?2 m7 q- U' p 294.9120 14.1920 2.74006 H) ?* [* R0 h2 E- b
300.9440 14.5720 2.38009 f/ G% w1 O6 ?* f3 r$ d& N, ~" B
302.0360 14.5120 2.3600
) |/ L/ I1 T$ y( E 307.5560 14.4200 2.42001 M1 M- m5 T; N' O( M! v
303.6000 14.6480 2.4000# a' K, _. Z3 ~. X6 O& c/ S M
306.8360 18.2720 3.06004 ~9 x6 |& ?0 E. [# ]1 O$ B
304.0480 17.6880 3.3600
" ^2 V5 |7 L" n h2 B+ f 300.0320 14.1720 2.7200
r9 `' y4 m7 U+ d& N5 b 301.1600 15.1240 2.1000$ c4 K$ C. |/ X) v+ L
307.6480 15.5280 2.12008 T) ~# f0 `* b3 g- d# D
306.4080 16.0800 2.0400
# [' K4 g0 l7 `+ F6 _ 300.1880 12.7560 1.8000
4 x* W1 m; q; X7 A5 g, y 296.6520 17.1200 2.4600
- ?' M* p1 B! I/ u+ O: l$ M7 F 290.6160 17.0080 2.8400
. f8 t; ~6 w! H6 ? 287.3560 12.8280 2.2600
/ I2 D& ~) M; t6 f" H+ C 290.6920 13.2520 2.00008 d$ E1 \; C3 C f: K
298.2680 16.7680 2.28005 Z' D0 \+ a- q2 \
6 g$ K% K# D! k4 O>> B=regress(y,x)
; D5 g; Y9 S0 n, r3 P' z; B b" Z1 }7 F/ s; a
B =
4 o: U- d5 `1 Y0 @* U3 _* |$ C0 t
( F/ O W& Z: c" T! [) w! v% N 0.05871 w% D7 r1 E3 i- s8 P
-0.4411) C/ ^) E" t, ~3 w/ l8 B
1.5818* ?& E1 a3 ~2 d5 m1 J" P9 k& }
% ^4 R5 m- u! ^ O" d! K% w) E1 @请教大神，怎么对系数进行约束（0~1之间）。
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发表于 2020-7-22 09:43
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