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大家好,我从Excel中引用一组数据,进行三元线性回归拟合。利用regress,得到系数可能会为负数。请问如何对系数范围进行约束(0~1之间)
: ?# q: R1 L3 Z ?下面是我的数据和过程
6 M& ?& S1 {" A4 A& C2 i. y, |A=xlsread('G:\提油率测算20200704.xlsx',4,'H156:K185')
- P- _$ d& f! c
4 A4 j0 d0 j& u8 N7 _% wA =" c( _9 K7 N$ z5 L
0 e5 p3 Y: _; d! C8 r$ |" W
15.1200 272.5640 11.5880 1.9000
, `- s9 C" ?4 r- y# t 15.4800 277.3200 11.2400 1.8200' l+ [% O% Q# f2 A+ O
15.3360 285.3600 11.6240 2.08003 u8 i }2 U2 O
12.8160 295.3960 11.9280 1.9200+ R% l9 P: T% O8 f' t% B |& ~
17.0000 300.7920 15.1080 2.5000
& T8 T% G9 j- o5 Y7 g3 w9 v9 n 16.2800 296.5760 15.4040 2.7200
+ t5 O0 O. X7 s+ W9 V 15.5600 291.5120 12.8200 2.2200
+ R$ h4 d+ M2 D' u" K/ l; ~ 15.3440 289.1520 13.8640 1.96004 M& X+ R8 L) i; ~
17.3600 288.3760 14.1440 1.9600
% r" w- C B2 U, y* W: `4 Y1 U 14.7600 290.2400 14.4920 2.0400/ `) E$ h' r7 |" k* @
15.6240 294.0520 14.8720 2.2400
( \) O9 g6 J. A8 n1 f4 N 14.5440 297.4480 18.4120 3.08009 ^- v6 b* }2 v' G" Y- @/ ~6 ~/ J$ E
16.4880 297.4160 17.7680 3.3600
% Y, l, F" m; \3 ] 16.0560 294.9120 14.1920 2.74002 }6 d! P4 ~6 a9 w6 x3 i3 I; J7 H
13.6800 300.9440 14.5720 2.38002 H' v/ O, g, [7 v2 R+ J- F
13.3920 302.0360 14.5120 2.36002 }: \$ G9 g& V0 Q* K' P6 c1 ~
15.4800 307.5560 14.4200 2.4200% {) f! z4 R: S0 m/ j8 D
12.8880 303.6000 14.6480 2.4000
0 |; F4 c3 u! a 12.8480 306.8360 18.2720 3.0600
' u2 ?; \2 g6 I* Q2 { 14.3600 304.0480 17.6880 3.3600
: [/ B3 s& Z0 g p) ` 13.7840 300.0320 14.1720 2.7200* u2 h; D7 W$ m! p7 Q
12.7760 301.1600 15.1240 2.10007 a" I/ G% R* y- P
12.9200 307.6480 15.5280 2.12007 j" l7 h# m" V9 w9 G6 P- |
12.8880 306.4080 16.0800 2.04002 J/ ]# f7 }# z6 d9 T/ H/ [2 d
14.4000 300.1880 12.7560 1.8000( R4 Q/ V: n- t, F- G8 V, P0 Q
14.1120 296.6520 17.1200 2.4600+ F: Q! Y& X. x
14.4720 290.6160 17.0080 2.8400 x0 h9 q( L8 G. O v9 J* O
15.1200 287.3560 12.8280 2.2600
+ p. w$ w3 W: g1 X5 H' s% a# P- @ 14.6880 290.6920 13.2520 2.0000' Z0 }! s$ N* ^7 d4 Y% u7 V5 J
13.6800 298.2680 16.7680 2.2800 ~0 x9 {& m1 k; t( B
%第一列为因变量,后面三列为自变量- K5 I( |: Q2 n" G6 l
>> y=A(:,1),x=A(:,2:4)( i9 S* c/ f: m' W A
, K% a. u5 X2 P) C- ]
y =% {0 V2 w7 x6 v+ u+ J
8 N: Q! ]7 B2 Q 15.1200" Y: l1 e- U& g: `2 [6 h+ d; z0 k
15.4800
' y8 n6 t- V9 _+ d% E8 C9 O 15.3360
_/ f/ T# ^5 z0 U# }8 G1 N 12.8160( H0 A+ h: ^$ K, I2 }, z
17.00004 S4 o8 K1 b' ~ M
16.2800
& B: @- v% Z) H6 w3 ~* ] 15.5600
; T: y* Z: K& m4 _* a$ S 15.3440
7 o4 ?3 s* X) C4 H" y& U. s5 { 17.3600
* k, r4 ~" O3 o$ R* i 14.7600 D( c) G9 W1 Q6 l% p7 a1 `
15.6240
/ C- w1 m U3 ]6 K) Q" z% _ 14.5440
& a1 n' ~/ N# k1 e 16.4880. R0 I# \) ^6 I7 |8 o) D
16.0560
- t) q4 e7 s& J0 k5 \: X: K 13.6800
* |7 ]. }' x$ I3 H: E z" O2 x 13.3920
. G$ ?1 x, M# x1 u 15.48009 F6 t" V7 {7 _8 T5 z) w/ ~
12.88809 |, ^, V0 K4 p* }
12.8480
; G* r8 n& ~3 Z9 } V- | 14.3600
- G) u X6 k( } 13.7840, ~; W% [# x7 ]- b w) v( X: Y2 o
12.7760
: Z8 o1 W N3 C5 t4 ?1 W; p8 [ 12.92004 p, o6 J [ h$ A
12.8880+ _( g. f% X* Y
14.4000
$ B( A: Z0 c$ I/ j* a* A0 O+ \$ s 14.1120
0 X* Q5 Q$ x/ L% s+ O 14.4720
5 G: E. M# b; C+ m) D! c 15.12003 p( C- g7 n9 D' a$ r; [" k4 r
14.6880' V3 S$ }1 a/ p& [' |
13.68004 \" |6 l$ g, C- H! d
1 C/ _$ W7 b, r9 n
: Z$ g @0 i' \. b/ q# S
x =
! c0 a$ }" H* l6 _+ f) ~6 Z% ^) a$ r, n
272.5640 11.5880 1.9000$ v) |# z! L7 e2 ?) \/ F5 e3 E
277.3200 11.2400 1.8200: ~" Z& j: e$ _% C* R
285.3600 11.6240 2.0800
7 H1 M' m+ \8 F. |. { Y; P* ^) K# I 295.3960 11.9280 1.9200
: z s& R0 y0 U- c, F0 p 300.7920 15.1080 2.5000$ r7 |+ e1 _7 y+ U8 Y' c. X# d
296.5760 15.4040 2.7200
+ B/ {/ {5 A4 ?, n4 P 291.5120 12.8200 2.22002 R P$ l- s, G) a/ s0 g
289.1520 13.8640 1.9600
) \$ A4 Y) t8 Y% t4 K2 Q 288.3760 14.1440 1.96000 n8 G, e4 u8 F F0 y
290.2400 14.4920 2.0400 t/ D1 R3 W; M' t! I9 W$ [
294.0520 14.8720 2.2400! ~7 z3 ?* I# y# W; U! ?. v
297.4480 18.4120 3.0800
; B6 U$ v. x; Y0 \+ A1 I1 w 297.4160 17.7680 3.3600
8 o2 O5 C9 q: Q: R8 P 294.9120 14.1920 2.7400+ b2 M0 q; B/ n5 K
300.9440 14.5720 2.38006 _% F5 ` M l1 D
302.0360 14.5120 2.3600
8 `2 q6 f! x$ W( y' R7 t9 f 307.5560 14.4200 2.42000 F6 V5 v; S: b O3 j! X8 d) L3 d
303.6000 14.6480 2.4000
4 b7 U; O6 v% v9 Z% ?: i, e 306.8360 18.2720 3.0600; U7 o9 ?5 t" R( O6 m4 g
304.0480 17.6880 3.3600
* `1 S0 M; G/ h! ~ 300.0320 14.1720 2.7200
2 z9 k. F% ^% ^7 ]# D& o. U 301.1600 15.1240 2.1000
4 H/ m4 e5 B1 w 307.6480 15.5280 2.1200' G* ]$ Y7 f$ ~* a" l$ k
306.4080 16.0800 2.0400
1 F! d. Z8 Q4 `* W' l9 a" X 300.1880 12.7560 1.8000
; Y2 u( r6 V, x8 M# X$ a. ]( {+ f+ o 296.6520 17.1200 2.4600, ~! g: P, ?" j" Q
290.6160 17.0080 2.8400& _9 i4 A1 B! \! M/ `' l* S5 X! e
287.3560 12.8280 2.2600& D. G4 l( r0 G
290.6920 13.2520 2.0000
$ ]0 c7 B* {( B$ A# q 298.2680 16.7680 2.2800
B: y# Q5 z% K* j0 q) s
, o' |6 h% p0 @. C3 M" S>> B=regress(y,x)
, p+ y1 [, G M' x2 d# M& |1 b0 F
B =* p F; ?+ x. z! R6 P3 y
4 [6 i4 K1 ?/ G q" @, ]
0.0587
( F4 ]) R: R1 ] }/ ~ -0.44119 ?* l+ S4 `( G; @' T( l! h
1.5818& h0 _* U( g; M6 _% P6 D" t3 x/ K) u
* A' a4 V8 E0 s& W, x# t5 ?请教大神,怎么对系数进行约束(0~1之间)。. t0 t4 v* `3 K0 h3 @8 j3 i
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