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" |0 I" ?8 D' T& M; _! H0 C! P( C/ ?MATLAB Coder可以从MATLAB代码生成独立的、可读性强、可移植的C/C++代码。% U r1 R% R4 {
使用MATLAB Coder产生代码的3个步骤:准备用于产生代码的MATLAB算法;检查MATLAB代码的兼容性(有些matlab代码语句并不能生成c/c++代码);产生最终使用的源代码或MEX。
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9 h! Z0 ]4 _9 r* ]; B( K( P4 ]利用MATLAB Coder生成c++代码,并在vs2008中验证:
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" O+ N c$ {' S! T% l; i6 {一个简单的例子,两数相乘:. ?7 v7 L# Z# k
; Y+ T: ]9 N! h) q- Q1、安装matlab2011a或者更新版本;
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* A0 `. V0 ?( R' x5 ~! w2、简单生成一个foo.m文件;0 x+ R/ ]! Y- H3 n( S5 Z! D- e
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function c = foo(a, b)%#codegen
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1 _1 v) ]* B1 H%This function muliplies a and b
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8 T, L- i' Z# D! v! s4 p. j l: yc = a * b
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: J& r6 W$ z4 T2 L6 ?! X其中,%#codegen可以防止出现警告错误: m0 A% K8 ?- r6 b3 a8 z" y
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3、在命令窗口,输入mex -setpu,选中一个存在的编译器;: X" J M- u% c$ `
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4、在命令窗口输入coder(图形界面),回车,弹出MATLAB Coder Project对话框;, Z! g9 _! v! b6 {6 w8 A6 v
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5、在New选项卡Name中输入一个工程名foo.prj;点击Ok,弹出MATLAB Coder MEX Function对话框;
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6、在Overview选项卡中,点击Add files,弹出对话框,选中foo.m打开;( r0 [( X- W: R
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7、单击变量a,选择Define by Example…,弹出MATLAB Coder Define by Example对话框,在MATLAB Expression中输入5,点击OK;同样变量b也进行相应操作,输入6;: m. ~3 ~9 p9 A8 s1 p: n
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8、选中Build选项卡,Output type中选择c/c++ Static Library;选中Generate code only;
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9、点击More settings,GeneralàLanguage选择C++;InteRFace选项中去掉所有选项;Close;6 G+ |* q1 Z7 Y
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10、点击Build,进行编译;点击View report,弹出Code Generation Report对话框,此时,变量a、b、c会显示相应的变量信息;- {( ~! ]( t. v, N
) g' R* z4 H" k: a11、利用vs2008建立一个控制台应用程序,将生成的相关文件foo.h、foo.cpp、rtwtypes.h、foo_types.h拷到相关目录下并添加到应用程序中;
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12、在foo.cpp文件中添加#include “stdafx.h”;' t; r" i2 P$ w% [% b% u5 R
* i1 o* V6 F% H& q13、test.cpp文件中代码为:1 k% H6 z6 u9 S# [/ z
! Y, ?6 ^' b' S#include "stdafx.h"% J" G) F: O, G
# D3 h8 i' p+ V! P v) y& j#include "foo.h"
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#include <iostream>) D+ G5 r3 G x0 B- q G( K
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using namespace std;
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: r0 K% o# v: J0 Bint _tmain(int argc, _TCHAR* argv[])
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6 G$ a" `, m' s0 g# T double a = 0.0, b = 0.0, c = 0.0;- g/ V. t9 O" A' f: d, ]
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cin>>a>>b;
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0 J b Z8 J2 J; o1 f- { c = foo(a, b);) d( T) G Z5 x: f0 Y8 _
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0 o2 w! V/ c' W cout<<"c = "<<c<<endl;1 {& ?4 @" m; ]9 O
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0 p- ^; ]( H* U# o* a return 0;; K1 d+ M* L2 O2 D Y
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6 E# W+ d5 B& M一个复杂的例子,求一个数的n次方根:# V! y* D; Y# Q$ G
# N$ P) a# f" b1、 两个.m文件:
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function [nth_rt, iterations, hstry] = nrt(varargin)%#codegen
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%This function will use a Newton Search Technique to find
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; Z3 R6 c9 w" A" ]%the nth root of a number, a, to the tolerance, tol.& O2 `$ Q- r c: Q9 M) a* G. ^
7 q' i: }6 }5 _+ O4 C( z2 y%The square root- X4 Q6 k! n& h! B9 v
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% nrt(10, 2), or nrt(10, 2, 1e-9)
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& x t- c& ` z: k* g%The "n" root
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%nrt(10, n), or nrt(10, n, 1e-9)" j2 `0 T) t' q! Z- }! f- \
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2 C* N2 ?- ]/ A+ |a = varargin{1};
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n = varargin{2};( F' ~, T1 T1 \* s" A: ]
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2 A5 U5 w$ W2 {& Q3 pif nargin ~= 35 ]( E. U0 s$ L8 r
% R+ q2 H4 ]- L8 d3 I( @ tol = 1e-9;
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- g; d8 f, F/ m K6 ^, x tol = varargin{3};
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6 G4 ^2 e% T: ^2 M7 Dend
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if a < 0
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hstry = 0;
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: Q$ e6 _/ }" i9 f' `; C [nth_rt, hstry] = newtonSearchAlgorithm(a, n, tol);
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iterations = length(find(hstry ~= 0));" ^; g" Y g- |
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%iterations = sum(hstry ~= 0);
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newtonSearchAlgorithm.m:
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% S. o. p# d, w5 D2 gfunction [x, h] = newtonSearchAlgorithm(b, n, tol) %#codegen3 d$ v( y: |' E5 f/ @% ~8 G1 i0 P. y
9 p1 Z4 Q* O, x* X6 |3 y2 T* K# W0 h" N%Given, "a", this function finds the nth root of a1 D, E5 s5 y7 b. n
9 L* t3 i! y7 r7 v1 c%number by finding where: x^n-a = 0# ?" c6 U4 O8 X' o
) \# J8 W% M; L9 A/ m6 D/ hcoder.inline('never'); %使其生成一个单独的c++文件% k% z c6 I3 c( h) l2 ?1 k
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notDone = 1;
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6 [. k# t) f: A M8 ?, i" waNew = 0; %Refined Guess Initialization
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( T" C; e( Y% t( t8 J( ea = 1; %Initial Guess- v! K0 m4 s, ^- {/ s
' m' ~6 ?2 \5 j# P6 x: rcnt = 0;! Y4 M: }- O" ~/ }" m, I
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h = zeros(50, 1);
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h(1) = a;0 ?- T! ^. d9 R1 _* [4 P. s
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while notDone
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W# o: k" s) w1 k) F2 G cnt = cnt + 1;( J! i' @0 F5 R3 M# i" ]* H7 W" Q
3 ^! k2 x% j% [ [curVal, slope] = f_and_df(a, b, n); % square; ?7 Q: ^, p3 e ~ z0 j) T
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yint = curVal - slope * a;9 K5 o5 x( D0 ]' ^
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aNew = -yint / slope; %The new guess
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+ I$ V8 E7 Z, O: w" v h(cnt) = aNew;8 k4 w( s. j4 G1 ^3 z6 [
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if (abs(aNew-a) < tol) %Break if it's converged
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notDone = 0;" U/ f: u) i" s' F8 C- R0 S
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elseif cnt > 49 %after 50 iterations, stop1 b0 v v7 ~8 q- v
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notDone = 0;2 ?, q1 M* Q2 @2 M) Y4 J) H0 b* p
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aNew = 0;
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else! ?0 Q' g1 G) x( \
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a = aNew;1 K2 A7 C0 b: \6 w4 R7 y! |
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x = aNew;* j' _( b. h1 I, z
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3 v! q4 P6 y* J" [2 T- Ifunction [f, df] = f_and_df(a, b, n)
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%Our function is f=a^n-b and it's derivative is n*a^(n-1).. U9 }$ f& ]0 v5 W
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* n; v( D) \1 @f = a^n-b;5 f+ p ]' R/ x9 X" v* B; ~
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& j, J0 }1 ?) z; H$ a( P2、 在命令窗口输入coder(图形界面),回车,弹出MATLAB Coder Project对话框;
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; Q$ l" A% [! Z5 e- z J3、在New选项卡Name中输入一个工程名nrt.prj;点击Ok,弹出MATLAB Coder MEX Function对话框;
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4、在Overview选项卡中,点击Add files,弹出对话框,选中nrt.m打开;$ E. x0 ^% p) g) l: u
0 a7 G3 o! X) [# i5、添加三个输入,分别为10、2、1e-9;两个输入也可以;
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6、选中Build选项卡,Output type中选择c/c++ Static Library;选中Generate code only;
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7、点击More settings,General-->Language选择C++;Interface选项中去掉所有选项;Close;+ @+ N* N4 |6 B: d0 f
" Q6 y6 r& d* @8、点击Build,进行编译;点击View report,弹出Code Generation Report对话框;
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# Q( |" y7 n1 U4 R1 {* V9 I9、利用vs2008建立一个控制台应用程序,将生成的相关文件nrt.cpp、nrt.h、newtonSearchAlgorithm.cpp、newtonSearchAlgorithm.h、nrt_types.h、rtwtypes.h拷到相关目录下并添加到应用程序中;- C% Y4 \0 d9 q' g4 _6 o% [
/ T) F! W4 k3 v* D10、分别在nrt.cpp、newtonSearchAlgorithm.cpp文件中添加#include “stdafx.h”;6 u( a% Q2 X6 S, _
. m' v8 ~4 m2 `- J7 m. D/ |6 |/ Y11、test.cpp文件中代码为:
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1 t* U" x3 K# F- a: j! p5 e" p#include "stdafx.h"* {! |! `! n% v/ Q3 L
6 N& C* t- P4 p! b, Y0 S3 J#include "nrt.h"
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#include <iostream>" m' K# [5 l7 }; d# P' z
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using namespace std;
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6 v1 L* Y+ n9 b. r8 lint _tmain(int argc, _TCHAR* argv[])" J( E/ `! Z5 o$ c Z
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{
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double varargin_1 = 0, varargin_2 = 0, varargin_3 = 1e-9;3 A( ?) @ n! O( f7 t( |
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cin>>varargin_1>>varargin_2;
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double nth_rt = 0, iterations = 0;
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double hstry_data[50] = {0};
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int hstry_sizes[1] = {0};
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nrt(varargin_1, varargin_2, varargin_3, &nth_rt, &iterations, hstry_data, hstry_sizes);9 L/ `# ~! T+ o" |1 a" C3 I
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0 J# v% H5 N! q. t4 M7 [& @ cout<<"nth_rt = "<<nth_rt<<endl;
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( R7 r5 F; F/ {" j9 s: ~; ] cout<<"iterations = "<<iterations<<endl;6 p5 R% y. o% {
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; P: }7 a, M: m4 U$ d: o7 a cout<<"hstry_data = "<<endl;
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for (int i=0; i<50; i++)
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{
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: F5 o3 R5 ]7 l, B$ Y2 m* T cout<<hstry_data<<endl;
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2 _# z" R( @4 _: }1 Y' a- r cout<<"hstry_sizes = "<<hstry_sizes[0]<<endl;& u/ O9 G2 v' t" ]0 K5 z! b( S
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return 0;
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