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function L2=lunwen(N,M)
+ x2 H3 [; @! k0 U' olx=0;rx=1;lt=0;rt=1;
3 ^( q: d; k' D0 `7 J$ E) uh=(rx-lx)/N;# }9 R m' P5 |8 z; N
th=(rt-lt)/M;1 p- G) n4 @. q
x=0:h:1;4 ^: }" l" j- J# i; J5 p( Y6 P2 g
t=0:th:1;
) ^3 g: T' [* z' w( i- S6 T1 X" ^A=zeros(N+1,N+1);& v' Y/ S, S1 A9 b
B=zeros(N+1,N+1);) v5 s" h+ d& p1 d0 R9 n: i
D=zeros(N+1,N+1);
/ W* n4 i: Y8 @* OE=zeros(2*N+2,2*N+2);
& j0 U: }$ ~5 C- J7 {2 k% BF=zeros(N+1,1);
8 Z- f& r9 A2 j; b o9 ^( W Au3=zeros(N+1,1);
# @( X7 s* q( e' {! \% v8 p/ ~P=zeros(2*N+2,1);4 ^7 d5 C5 C" K# G, q' r, ^
X=zeros(2*N+2,1);
7 } A4 {9 I1 T. h3 IX1=zeros(2*N+2,1);5 C5 L' f7 ` J& B( a' R5 v
X2=zeros(2*N+2,M+1);
, S; _) a0 M" gfor i=0:N
8 u/ `2 Y, ^/ b8 u! Y- Q. f u3(i+1,1)=sin(pi*i*h);! H9 f* X9 W' F f# f
end
" ^; ?. x5 S% z7 w& M: ZX(N+2:2*N+2,1)=u3(1:N+1,1); X# j$ q6 W: B& \4 ?
for i=1:N
( L2 i* g# h$ b, p: h+ B, w. T e=[x(i),x(i+1)];
8 V, T4 B Z2 Q. j- }/ p- I) T" | A([i,i+1],[i,i+1])=A([i,i+1],[i,i+1])+ganddu1(e);( ~! r4 `( H7 J( F" Y
B([i,i+1],[i,i+1])=B([i,i+1],[i,i+1])+gangdu22(e);
1 R' E$ B' K& C2 i4 t, x D([i,i+1],[i,i+1])=D([i,i+1],[i,i+1])+gangdu33(e);
1 D+ X! s! G8 tend* P# d* Z# D4 |4 K% P! O, w
% E(1:N+1,1:N+1)=A;
( R; `/ g4 G- K* i0 t% E(1:N+1,N+2:2*N+2)=-B;
2 @! @6 L0 p P3 ?8 d# x# p# F9 P% E(N+2:2*N+2,1:N+1)=-th*B;/ y$ ]2 o- c1 B1 m0 e4 M
% E(N+2:2*N+2,N+2:2*N+2)=B-th*B+th*D;
3 q0 G- }) ^% {! @2 ~2 x( Z/ i/ TE=[A,-B;-th.*B,B-th.*B+th.*D];
6 j/ z1 M5 F+ S0 y7 Rfor j=1:M" @: V/ ~% m6 @8 K. T
F=zeros(N+1,1); %%记得归零
6 t) `6 ^$ P% w% N5 Y( c( q y=exp(-t(j+1));) V0 }; R4 Z7 \/ |
for i=1:N
- ~+ r! X5 W3 R, W) `: J" o e=[x(i),x(i+1)];
7 `/ F( L5 T) ~1 j F([i,i+1],1)=F([i,i+1],1)+y*Hezai3(e); D) T4 n g( N( V& I- ?& c8 w
end
4 Y U4 m+ M3 `2 J3 h( o X(1:2.*N+2,j+1)=E\[zeros(N+1,1);-th.*F+B.*X(N+2:2.*N+2,j)];
3 L' q8 b8 Y! }end
$ i8 B+ u8 G' z2 B. N/ c7 q3 X, xX1=[A\B*X(N+2:2*N+2,1);X(N+2:2*N+2,1)];
7 D6 S% e' F% a( AX2=[X1;X];
4 t2 k6 ?. ^; i7 A3 q6 [- ?错误使用 vertcat% @5 D% N% w; y
要串联的数组的维度不一致。
" V' u1 E; E% Y7 r
4 S( s5 p7 X+ _) U出错 lunwen (line 39)6 f( { j( F5 ]! u; N5 M+ U, D* ]1 ?
X(1:2.*N+2,j+1)=E\[zeros(N+1,1);-th.*F+B.*X(N+2:2.*N+2,j)];0 \/ C% i% ]* [" d5 V# k
检查半天也不知道哪错了
) j: s) [3 f! ?( u. L9 f4 d# m4 o0 V0 w" w1 L. O. }
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