找回密码
 注册
关于网站域名变更的通知
查看: 503|回复: 1
打印 上一主题 下一主题

MATLAB基础教程之实例原文件 部分

[复制链接]

该用户从未签到

跳转到指定楼层
1#
发表于 2020-3-25 10:24 | 只看该作者 |只看大图 回帖奖励 |倒序浏览 |阅读模式

EDA365欢迎您登录!

您需要 登录 才可以下载或查看,没有帐号?注册

x

% `) \" E4 G5 \+ y& [/ l>> str=['MATLAB 2006a']" A: a+ P9 }/ S- {# v0 u

- y' q+ A, h! ?7 ~! f- K>> str- |9 [6 |! _% v+ X/ d8 l' F! Y! F
2 e2 Y$ G( w* I. T5 M9 `
>> disp(str)
* W0 v  `( j! j$ A+ q1 g9 p. t
( p# ~3 z2 L5 A* s  q' G%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%1 w# C; S1 C3 r2 o( s" [; Q

1 U7 {- }: }6 L7 z>> x=-2:0.2:2;
  {1 ]+ C3 s2 M1 b; J' R2 h4 y# s3 [4 F. u& l
>> y=x.^2;
4 e( B6 R* F& I% \9 l
5 u/ ?' j+ Z9 @# w5 ^2 n0 c7 J>> plot(x,y)
5 O4 c- d0 z: b6 ^: ?
1 R' w& n, x3 Q/ b>> str1 = num2str(min(x));* y$ x2 }7 b8 @4 m1 u

& j4 s0 H: Q, r>> str2 = num2str(max(x));
4 L  U- b  j* l9 A, f$ D. |( f1 X1 `; ~
>> out = ['Value of f from ' str1 ' to ' str2];
" g9 l4 M, c, s6 A* T1 J
+ _  M" C- t, J( {' v- }7 D%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%55 S1 w( q- i& j

' t2 O7 K0 t+ y& Q! ]5 w4 M& n; Y>> A(1,1) = {[1 4 3; 0 5 8; 7 2 9]};* W- c, J$ h# ~0 K/ V# T, k
" }7 \8 Z5 w) Z5 [8 t
>> A(1,2) = {'Anne Smith'};
8 }9 n* J1 F3 i6 m" p& h, @/ `6 p: ^  P+ i& J
>> A(2,1) = {3+7i};
2 n, Q- P4 @9 f0 M$ d$ M  B4 f- k5 B2 {  \! n) J4 X; _
>> A(2,2) = {-pi:pi/4:pi}0 J0 w% M: k  M

; j( Y( A: @7 F6 q; g& B7 [* r$ I>> B=cell(2,2)
+ X* s- @9 j- m7 T8 f( P* W& ^
0 q  K# Q$ ^6 j1 g- h' l>> B(1,1)=A(1,1)) p' h1 A- R4 ]  s% E! [, w
>> celldisp(A)3 `% z; P' o2 y4 F6 B
>> A{1,1}! x: ?% b4 r. \( x% l" r$ ~$ N9 u
>> cellplot(A)& G/ L: a9 L6 c$ q

5 Z# n! I( p' Q6 H$ y; Y4 R2 v%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
9 f) e4 T9 X$ O( g
0 r, x- d# i& m- w; _" T>> clear( d8 U& _, K2 S& Y3 y6 S* i
A=cell(3,3);
* U6 N: E* L4 a4 H3 t* qfor i=1:3( t" c, f* X: v/ Y5 M' n
    for j=1:3/ j9 ~8 i: K$ x' D7 U
        A{i,j}=randn(i,j);
7 O8 h: p. a( b! }) B6 \    end
/ B) a8 g7 @5 F+ e" q7 c0 a" Iend
+ r$ `' J& V9 M7 }" Z( a>> subplot(2,1,1)
2 m! ^5 W1 W! w. d>> cellplot(A)
$ c% s: y4 Z1 o: L- B>> A(2)=[];8 l" m9 ^8 a1 f$ h: p' B
>> subplot(2,1,2)
7 s6 J( f$ p. l/ Z>> cellplot(A)
+ Z0 I6 H: i; Y! E4 [>> clear8 K& @! i# s# o5 ?
A=cell(3,3);
/ y; I4 J0 B" ]for i=1:3# |+ |1 N  }7 H" g; ~- T
    for j=1:38 _* C1 K/ V, H$ n
        A{i,j}=randn(i,j);
; R( _$ C8 ^5 b( @    end
# T7 r- N; s8 G, ]6 Q2 pend# Z0 A4 F& j: M2 e) q3 w6 u
>> subplot(3,1,1)
" b; ]& o- k3 xcellplot(A)
8 ^3 P9 L4 M! L1 Y1 O) R* hA(2)=[];
# A5 @. ~! P2 ]* v; H0 E: }subplot(3,1,2)
8 e. d6 w) S. G7 u1 ocellplot(A)
( B* a( e8 j! t4 T0 C>> A(3:5)=[];1 P3 U# n1 a; c" r# \0 t$ d
>> subplot(3,1,3)
- c& D: ?8 F1 Ecellplot(A)0 c; l+ f2 H  `4 C5 j$ B- R
; f! d$ h" U! j% z/ c$ b+ o* m
7 j' Y0 t' M7 t6 T4 k
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%) J- U; W4 I& b. u$ ]! [

# g& W: M  l# y% T, t. h>> person.name='liuhuiying';  B0 |6 @: C. {4 x4 G
>> person.height=162;
8 g. P$ `) i4 ?4 \>> person.weight=51;- S9 E# e! t" W1 V# S3 D7 @2 ~
>> person.hobby='swimming';
- ~( ^7 J$ X% b% c' b0 w% K>> person% H1 x; p" E. ?* f( d

, x1 N$ G' F# C+ A% l* W' `>> person(2).name='zhangqiang';* j" k- t7 e- l9 e0 R
>> person(2).height=175;
, f9 A5 i9 h" X* d3 C! T+ |5 w% e4 Y9 N>> person(2).weight=65;
% H/ Q/ t, B$ |5 w( v1 k4 u; w>> person(2).hobby='Game';
1 L1 _% R( B7 P>> person
, s0 A5 j0 _( p- M
* w. u6 ]  ]9 f" D% t6 s>> person(1)- T" v' u1 f. D( P/ M

0 h8 j3 h  @2 _/ t$ |>> person(2)
# u( h2 D  S2 {
; ~, b( w/ I" J$ M4 U. K$ c# @person =
" v0 T0 y, h! ~( T. j6 C  h
. O) H4 l" b# `/ \8 \$ E      name: 'liuhuiying'
0 ~6 r) {! }, D5 T; ]9 L8 |    height: 162
9 F0 Q0 y' I2 H1 P/ e$ B( o! ~    weight: 518 H1 I" ?) ~1 |  O9 o0 }
     hobby: 'swimming'2 X1 s! V% Z! ]$ ?( p1 E
' g$ U. y/ H! Q6 y

- `/ p4 g# V; {! N; Zperson =
# d' @8 Z# X3 g$ ?% h/ }) u9 Q6 y* W! ^5 ~& w
1x2 struct array with fields:& X' x  s7 r" ^" |
    name6 h% O1 e! d" \( d, x- Y. e9 N7 s  V
    height
9 _- M% B! C! o  G1 C+ d5 Y9 ]    weight3 S# z. Q* Z) S8 |
    hobby
9 X- }2 [5 u0 M, s* v
" z9 j% L1 A/ W' ~! v! r% E3 b* @( U% U7 m5 h
ans =% J5 Y9 E  }* H- R4 j7 z% U3 U1 L

9 B. H: O! I4 f7 [8 @5 m      name: 'liuhuiying'
1 i$ Q0 q3 d- \+ Q2 t7 [$ k4 z    height: 162
, O! b2 i" y% n; e- u. e    weight: 51+ ?& x2 g% d! q& d5 G+ x3 d1 X% q+ S
     hobby: 'swimming'. m) t/ c- `* M

, ^% Y2 l; J  J! @: ]' K' G: }5 \8 z9 ^8 e) @
ans =
) c+ J& ]' |- V9 j, I+ @' |9 w2 t! D2 d! ~! ~
      name: 'zhangqiang'" q2 H% i8 D9 y" D1 z
    height: 175
+ O5 e% J$ e% o    weight: 65
2 T8 U+ ~( W9 l/ r& N     hobby: 'Game'
/ U. O; _0 w: I; }$ ^2 h( O: A0 z  \' S" E/ O) {8 R
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%. s1 y; [2 M0 t0 f
7 @. Q: i# F1 [
>> person=struct('name','liuhuiying','height',162,'weight',51,'hobby','swimming')
1 r- A( m3 S4 a7 |; V- y2 d1 w0 H2 R: P" q% \8 ]; `
person =* w# s* @& |% h: A4 f/ {& t' a8 S8 f
. L- }' o" r3 @* a
      name: 'liuhuiying'6 D1 v% U2 H9 B2 n8 A' f
    height: 1627 l# Z- {+ S, J* p8 M6 v
    weight: 510 w; A+ b8 s( ^# M
     hobby: 'swimming'0 Z: P/ }! b, b( D) _5 }- f
4 o3 S; }: |! K6 P" i
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%) H# K9 n) {. R( s6 E. R/ R

6 V* t& \; u% j% @9 Q>> person=struct('name',{'liuhuiying','zhangqiang'},'height',{162,175},'weight',{51,65},'hobby',{'swimming','Game'})
. S9 x1 u) E2 R0 W, I9 y: E& O' z7 R0 R- h  @
>> person(1), {: j! l* b1 T) d/ A) p
0 ~' b' x1 i% b  H2 ^: H
>> person(2)
& h1 g, D6 {2 s/ Q! Y% z1 l5 ~6 t; g! o3 t3 O. [4 D( K

1 e4 \: ?' R  A8 @, D+ G0 h5 i+ i) H

: e2 ]5 H* Q& u/ N; lperson =
/ x/ Z) o, u7 `8 u5 a' j: K( X! r6 _- w. h# p3 x6 s
1x2 struct array with fields:) N3 t% I+ [+ j7 `. |' O- _
    name
; |3 `% D0 K  s. |4 Q    height6 R" A$ E8 L3 A) E; a' w" F* g9 ]
    weight
3 w9 l) R7 n" q    hobby' e. j. L7 b2 w; {

9 C# n, K2 q+ {6 w5 N5 G5 e/ s4 Z0 |, ?$ [* E* j! T
ans =
6 m- f( K) b% S& M- S+ }9 \
( E. p: u  J' T9 x# v      name: 'liuhuiying'
% j7 j, s1 Y+ c" E% B( h4 h5 Z1 A    height: 162# v# f) f8 i. i& t
    weight: 51
3 Y6 d0 B# X5 m- v4 [. C4 W     hobby: 'swimming'
' n; Y' H% K; ^/ q
: `9 v0 ], i9 |: v) b2 [- I& ^) U, _* y9 `
ans =4 |/ C8 i# m$ _" m& P, q
, k  L1 S- j$ Q0 a
      name: 'zhangqiang'7 W4 E: \# v" U) E9 o
    height: 175
6 r- C- F# @1 B# {0 U4 m- a    weight: 65
' z7 U! l9 g; O* O8 B     hobby: 'Game'
/ Q0 k- r# J- N! {; W# O  l& F( O) i0 p& e- x* d
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
5 U+ F  @+ x; s$ D- G) }& E8 O/ w) A' ?* k( y: h; v9 ^" X
>> person(1).gender='female* H8 O  b. R$ T1 R# j1 B7 \
( X% W: K- I) l- E! A
>>person(1)
( F, J1 F9 x9 d9 }# p5 v" Y& k- x5 |7 d
>>person(2)
9 s1 K) q# S) N1 A
7 a! Z3 o5 T' Xperson =
' C& z- n$ t7 J5 m) f6 b: m/ T3 M' w; y6 B; G' s% d5 ~6 }
1x2 struct array with fields:% Y+ r. E5 h* K: b  O: C" G2 X
    name. P4 |* h( v: G
    height# l+ ]; P! m: ]. Z
    weight
4 S  o9 n8 m" _9 V7 E    hobby0 ]/ Z( [' _1 Y! v& _# G& F
    gender
3 W# c1 G* O0 n2 |6 g. Y4 ]+ J, w, K

* _1 S2 @  k2 F4 X% U  A- f4 ]- eans =, h( w; f1 c% C4 O" }

1 M* e3 N9 p2 C& _( H      name: 'liuhuiying'
0 m3 o" r2 P" S- |    height: 1620 o2 [1 J: {/ Y2 J$ g
    weight: 51
* k* l. R! V- X     hobby: 'swimming'
4 q% b4 [7 e8 ^! Y    gender: 'female'
- `& ], j: i) j. w$ I) q0 s( B
* y1 S( ]$ g( r* I- L
% N+ W: J8 G8 J: P# E) T0 Wans =
+ k! v( s& t1 t# L8 Y, Q9 T8 \  @' o; U2 {( e& ~" I* N
      name: 'zhangqiang'
: O! ^$ a0 W+ {1 }    height: 1759 ~4 j) W: M+ e1 ^
    weight: 65
8 |7 t' P7 P) E6 S8 G1 u$ n     hobby: 'Game'
8 T8 S% U/ @) V4 [: Q1 I    gender: []0 |% X) {, r1 p

" C% {! w3 U4 z: H%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
- h! G8 W8 t% u- c9 H5 Z+ O8 w1 q8 U+ w7 S$ h
>> person=rmfield(person,'hobby')9 D1 P) J! Z0 t: z5 c8 a4 o

. R5 {$ B  A; z' O6 U1 ^! H1 R>> person(1)! ^/ @! |0 F! D# E

+ D: ]+ m& T4 l>> person(2)
& Y. Q' w, F, ~/ L4 \2 o8 a, G/ L* X0 g  |2 g3 V7 ^" V2 f9 [- \' I

% h. Q. H* K% `  d, ?
! S& D/ |: [% J) `) Z2 j" zperson =
. T+ W3 \% a& t2 ?: N% x$ \6 q$ f, n' W1 L( H# o
1x2 struct array with fields:0 r4 r. W7 }# a: l) C) e
    name( d. x/ E. j" h6 Q8 q
    height
, u9 T) ~/ a# R8 H  ?7 r    weight
$ p9 y. }2 M% r0 |    gender- ]5 |* c4 i" s6 l2 @/ b4 t- k
% w* M5 K) {" }% w

5 t' E# H  o4 s: v/ h4 kans =
; w+ N; J0 g1 }7 a3 Z$ A% h4 U$ k7 d  s$ N2 p: d
      name: 'liuhuiying'
- `2 Z6 P! X$ C! D9 t: n    height: 162
& r; T9 T6 ^: F2 `3 u3 \    weight: 51* q% f3 S8 j% ]. L6 W
    gender: 'female'6 Q# \/ \2 C* B$ t& D) w) h
' [" u# w! D' ^  |4 I' e

9 ]% u. j1 r; v1 @- h- kans =
7 N/ v. a  s8 O$ S
: O6 p' I0 i1 S, E1 K8 E      name: 'zhangqiang', \) W3 O" @, t3 g
    height: 175& L9 i. V" n9 E# e
    weight: 65
5 _5 A( V0 j! N    gender: []
7 W# W: R* F* d7 x. k) g% ^
( A3 U- ]1 k# n* ~+ t! d
' V' r$ I% [0 v3 U
. C! i  I; B! ]  m0 o% L%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
* e# X+ V( h" `9 H% T' n/ B8 O" }( p8 `& w, S
>> person(2).gender
) G$ R) W: ?3 ?& p# I+ n
% M5 W4 S0 t& h- L- M2 b, \# o>> person(2).gender='male';
' @' O' g5 m; R- }
# V$ n! M5 {- O2 T>> person(2), l; b2 }* _( M# y& ]5 V& G
! R, w2 `% w# z4 U
% o% |2 W9 f" j* e! Q+ P( B; G) A& X, |
8 ~% p6 s; G# ]0 A) U4 G, L9 q
ans =9 M. N$ X( l6 C! ], x0 ]. J
6 {6 E4 ^, _' i) l6 b
     []' p$ q4 c5 S& J: X, ]7 c$ G$ m' N

, P3 F, L: c0 a& x( U1 c6 E) x" k( A* L  }  [) U
ans =
, o0 V$ D6 j- v, Z1 e" _
- k. m& y- M6 a! X7 b/ g      name: 'zhangqiang'. |. F5 q% l0 r; D/ m7 C7 {
    height: 175/ e4 _' e$ x4 I2 w
    weight: 650 ~! l/ ?9 l5 \( z: k
    gender: 'male'
- D/ R* h5 `) q$ F4 V* T
9 Q0 X4 A* n; d) {- t % w3 ~  x7 f  n6 x5 ~: h& }$ o6 w# i5 F0 M

  ]7 K/ ]  a3 D! K1 s% w%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5# g+ L" _8 _4 E4 A& \- [

, C- u0 l4 S+ N9 |7 I2 b. }/ x3 e>> A=[10 20 30 40 50]
$ G3 N6 a$ t0 \7 \- w0 q( ~5 r- W. E  p* M; i0 @
>> B=[10;20;30;40;50]( M* }: J+ B2 _

6 p2 g! `; h4 s: ]$ |%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%50 h+ v2 _" b, \$ j) p' s% a- I& m
) _5 x) u4 J) A. F0 n3 ]
>> A=1:2:80 @& @* i- M1 |. I

1 O" ^% Q$ y0 S6 n& r" d>> A=linspace(0,12,4)
4 A5 C: i& O  n" D5 u: _- k  P5 p+ h' k' H, K2 q4 T2 Y
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
7 F' {& e3 @4 r. K
  \3 [& Z2 [4 r( _>> find((A>8)&(A<14))       %找出矩阵A中大于8并小于14的元素的单下标索引
2 N! f5 r1 S% {$ O' G* W, r4 @# R
8 m/ ?1 V, Z; X>> A(find((A>8)&(A<14)))    %找出矩阵A中大于8并小于14的元素- @" H! J* P: a& h5 W  k( `
- b: c# h; k0 g( w8 x' R
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
" T7 n+ e. C+ k) W$ |; y& I: }( r0 e! [7 q8 u8 g# [
>> A([1,3,6,8])2 i6 [* s  E! t$ v/ C6 K
, s! {  V8 |. p- z6 ~8 p1 j
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
& C" d, d5 ]/ g# R6 R( p
7 q0 g1 |. q! K. Q" r>> A=rand(3,3)
  q0 K* a$ U% |1 p
0 I4 _) A; v3 Z* w: ^>> A(:,:,2)=randn(3,3)+ l& o$ E; K3 g+ w+ i( t4 _% l. T
  R: ]- @) F+ x! f/ J
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5. w# b9 v7 d3 ?/ k

; G! N  Q5 ]+ v2 [- F4 b>> A = rand(5);
; x( H- Y  U6 e" N6 _* z8 P( J
) C' W4 j0 P6 l+ [* y+ b# M7 O) J>> B = A > 0.5;/ I% \6 u; O2 d: x4 m

; v; E; e5 ^5 \! _>> A(B) = 0; C% |% ~9 b5 u/ R/ h: a

5 G- e4 J" I6 x5 p+ {
4 d+ n& ~# i# `0 G: f+ G! i# u) d' R% E9 U# i* p% y, }7 C
A =
0 B4 q5 o$ _! }+ r+ s" I3 V/ G" t- i( ]
- t; _, q& {6 k- G0 O+ u    0.1450    0.4018    0.2400    0.4909    0.11128 N* B: ~  @5 q" C1 c
         0    0.0760    0.4173    0.4893         0/ R1 r' P( i  Y7 j/ c1 T5 P( s
         0    0.2399    0.0497    0.3377    0.3897
* D% ]4 t& q2 \9 |; {    0.3510    0.1233         0         0    0.2417
3 d& e5 d6 j2 S+ j         0    0.1839         0    0.3692    0.40391 E2 T8 ~. R1 ]/ T, w
& k/ _% U3 o: J4 _4 m" r. W" d
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5, ~8 m; [# v, T* P+ u4 t

( t4 F. [, l$ ?$ N) H. o. W' @ >> A = magic(4)
0 N# u1 r2 B3 H1 x7 o* D; j
: i; T6 K* \' }>> B = isprime(A)' v7 \7 Z6 R- k1 k
1 O2 H8 E% b9 G$ H
>> A(~B) = 0
9 I) G) h! k, N" Y5 g% b0 d& R$ n2 ]) r1 J

0 l  k  m/ Q5 Q5 m/ k% ?* G$ P( n$ \. h+ g
%%%%%%%%A =- P& X, b+ M( w

, F% V, o& R0 B0 ~    16     2     3    13
0 p0 D( U' \) Z2 p; t, V' M5 N     5    11    10     8
' l3 S  Y+ S% \  C1 ?     9     7     6    124 I0 c+ ~$ T. `. |6 q7 r7 G6 k
     4    14    15     1  S/ q6 D7 T! e; e  A" d

: a& h1 k8 Y  |1 @( I8 s4 h$ Y- |" z: i
B =
: q% u$ K" V( i- t. n% g6 Z" j! i+ v( P: ^1 n& \6 x
     0     1     1     1
0 G( i' \# a6 ~- y* Y& f/ [     1     1     0     03 a9 r/ ?" y% ^: K( L
     0     1     0     0
5 y8 ?8 ^8 V3 X9 k# F" S4 V7 Y, I7 ?1 V     0     0     0     0' R1 y* Y- `1 r/ D+ s8 c; B9 ~

0 k5 J% `( ?) l( }' Y
6 l7 Z8 ~' o; ?# k8 k% D4 b" r9 G: S8 hA =
3 V5 o' {6 a3 P1 e5 V
/ N3 g$ j/ E: R! h1 }; K) [     0     2     3    13) [; _5 C3 _0 C4 l" x0 M, ^+ u
     5    11     0     08 N9 \. }0 L: P
     0     7     0     0
7 a* k) j5 E& @8 g+ X     0     0     0     0& q. [+ F/ X1 T; a
' l4 C# k* U' q
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5( c  R% G& c! A. _3 X# l. K: z. r3 T
2 o( L  {7 ?; T$ }; F' w. ^2 u
>> r=[1 3 5];) J/ Z1 Q! p7 T  _. F+ l% v

; A  J+ O. [1 {4 x% E2 c>> p=poly(r)
( Q6 S" n  g7 t3 u  |
: G# X" \- q. s7 o; }>> poly2sym(p)
4 w2 e9 W, [7 ~$ \. e2 \4 K0 Y
& i0 o# v7 J3 N' G9 C>> roots(p)$ e. c$ O# E, p, F
1 S0 x) V2 v, A2 }, d! d0 D7 U+ ^
p =
: R: P" z% a8 C+ e9 P, ~- U6 P" _0 r9 s6 T3 @$ n
     1    -9    23   -15
% r5 S1 J" `: [1 s8 H* |
, b: a" H' M" c' X" `* R
( K! R- X& k1 j) d, ]/ Nans =
" p2 g8 o! i0 s: Z" d( w+ B - A8 `$ y3 o8 }4 g* i
x^3 - 9*x^2 + 23*x - 159 Z( @% Z" @! {" Y( ?( ?
9 U2 k( v% b2 K1 E3 ]2 r% T
* \1 e6 G9 P8 L7 @. U
ans =
  v# k2 l' a' P# G7 P; k1 F
: C  m4 m' _' H. d' R( E5 O! r    5.0000
4 [$ I% d4 S, v5 l( t- o    3.0000
/ E3 ?" m$ h) ~' }& k; [* }    1.0000
3 u4 \* K' V6 O. W- ]1 Y3 I4 N* h8 c, M" G5 n0 |( e
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
) c% F. ]7 t$ `" R% {  j" Y$ F7 e. E1 V" d* I1 I
>> p=[4 3 2 1];
* T% N- _: _% l0 `+ d: m6 }. {. S3 ^: @
>> polyval(p,4)$ D( g% @5 x# H1 z2 a

9 o5 a' R/ Z4 F! s>> 4*4^3+3*4^2+2*4+1
8 t+ D/ ?5 s( k% ?. {; i
% h7 }/ j+ h, o: O- P
6 t; D, |. `7 T0 }ans =
# C0 _: R5 e( a* n+ K' ~
  |  O, j) t2 z- E+ M3 U7 h   313
- P5 l1 c& u9 s, Q
" S1 |6 s' j- O- d* W& R
- {6 z; w. x# G1 }9 a5 uans =
6 [% k7 s8 b0 [$ r8 ~- L' @! ~$ x" v+ Q) V% c6 Y
   313
7 t/ w: n3 b+ R/ M* H9 }' U- s7 c2 U. u
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
3 d! ^* p5 F( m, a# h- I4 s+ o3 q) n% c# H  M
% fit sine between 0 and 2*pi using 3 order polyn0mial
1 [4 W9 G1 R8 [2 U, @2 \0 y7 P. fx = 0:pi/10:2*pi;3 S- P) p4 X8 X6 v6 i4 y
y = sin(x);! |7 a, J$ r  V7 H
p = polyfit(x,y,3);1 d6 w4 j4 R2 `) I
plot(x,y,'r*');# U8 t# o2 @6 t: t, h/ F
hold on6 D5 w- C& q+ N1 r- o, m" C
f = poly2sym(p);" ]! y6 V5 y2 E3 z9 |' O4 m2 N
ezplot(f,[0,2*pi]);7 j( p1 J8 K' C. D6 o0 L9 T$ k

- c3 s- W/ V, V" f>> p
8 ~, {2 O2 `: S' o5 a" R+ S' q! S6 V; F0 N7 P

' o( W7 [$ H1 C) J+ n1 }0 _: t9 b# F+ U9 t

0 Y$ E! l1 d, b%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%51 G4 o4 H/ O2 C) K. {- X# S
4 j; E% U* @5 ]) p( K7 a( `6 K# y
% Interpolation using the four methods
% k4 o: f1 H# z; G- U% ^x=[0 3 5 7 9 11 12 13 14 15];2 R6 T& Z5 U- E
y=[0 1.2 1.7 2.0 2.1 2.0 1.8 1.2 1.4 1.6];
( e6 A  k+ p- Ylength_of_x=length(x);1 ]0 W' k' }2 k
scalar_x=[x(1):0.5:x(length_of_x)];
# U: V! N0 N8 S; T  y3 Mlength_of_sx=length(scalar_x);
4 _) l4 I# `$ L1 j" @4 T$ B0 N$ gfor i=1:length_of_sx* X4 V# l8 k5 |1 A
    y_nearest(i)=interp1(x,y,scalar_x(i),'nearest');6 g. X! K$ t+ a1 M1 M; ?" S
    y_linear(i) =interp1(x,y,scalar_x(i),'linear');6 p; x! W9 T4 z$ M* {% s
    y_spline(i) =interp1(x,y,scalar_x(i),'spline');
0 V, @- G8 a3 k: V, a" a1 b    y_cubic(i)  =interp1(x,y,scalar_x(i),'cubic');  U; D2 m# Q/ T% H5 f' {; i- u
end1 x6 K2 w" |% M& s+ y: ]
subplot(2,2,1),plot(x,y,'*'),hold on,plot(scalar_x,y_nearest),title('method=nearest');- k% I* y8 N' o0 t' r3 ~; Z
subplot(2,2,2),plot(x,y,'*'),hold on,plot(scalar_x,y_linear),title('method=linear');9 L) ]. K% P1 B" B$ h
subplot(2,2,3),plot(x,y,'*'),hold on,plot(scalar_x,y_spline),title('method=spline');
, z' @  U' L7 A# i9 }) Ysubplot(2,2,4),plot(x,y,'*'),hold on,plot(scalar_x,y_cubic),title('method=cubic');' B3 `. n1 T2 s  K% ?1 Y% q
7 c( s  E8 x, X
! H. x' X. |, i" d( u' b
) B6 S1 h& r5 U8 \. v

# e* I/ Q6 ~( j' P! ^- i%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5: K- F# N! R/ B$ z) M4 J# y

& t7 p3 V/ {  M" {! q4 u& p6 B2 T>> fh = @(x,y)y*sin(x)+x*cos(y);* @9 J; R6 N. o. o; j/ A3 Z

3 @& I- |' G# r5 s* _>> fh(pi,2*pi)
! V. P# I" S; Q9 y8 r# l2 R* a- @5 I' z( s# Q
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5, B4 d% I7 P: ~" ?
1 S0 a/ Q; j) l; n. I9 @7 v- E
fh = @humps;! X8 m$ H" i; B! G% t2 G8 f
; c  z% O8 A+ c% ^- m+ _
subplot(1,2,1),fplot(fh,[-3,3]);
4 g/ t; G7 I9 }% I4 _
) `5 K+ k  ?/ `. f2 o" Ssubplot(1,2,2),fplot(fh,[-3,3,-10,30]);
) i* ~* W* }9 w4 Q# r) w& s
; o% n3 w7 {, P0 U; |%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5* S- O+ _0 v$ j  y6 `
6 r1 q6 |; Y' s3 T, p+ R  _! L

/ _" I' q  \0 J: _7 R+ t; d* C: y
/ u/ d; l4 j- e9 l) I) q% find the minimum of the function f(x)=x^3+a*x^2+b*x+c
) I6 G9 l% D- q0 ^; w- `- Efunction [x0,y] = funmin(a,b,c,x1,x2)
2 O8 h* J9 c( x3 h% C9 Woptions = optimset('Display','off');! x& F' d; |( K8 Z: X. o, }2 G
[x0,y] = fminbnd(@poly3,x1,x2,options);9 w% I; W$ L8 `  w/ g2 ~& G
    function y=poly3(x)        %the nested function9 ~$ H0 u9 x9 b5 S/ F
        y=x^3+a*x^2+b*x+c;; U, Z7 N# l2 M1 U$ y+ d
    end
7 c% T$ \0 L. L- e. S* G5 g2 p% plot the function4 H- u7 X% E( D8 H
fplot(@poly3,[x1,x2]);  x3 U, z# G* J! c3 @2 u( {, |
hold on;4 P4 c8 Z  A7 X* [
plot(x0,y,'.');% {2 d# m  }( M$ a+ h
end4 E! n' n! e4 D# N1 r/ T% a6 [

2 }5 a& o2 M+ P( h& Y6 C7 s>> [x,y]=funmin(-1000,10,0,600,800)
) U& c1 J- e  R$ v! W( x
4 z$ d2 G3 T- @/ J: [$ u
7 h* c! D8 A$ d- H" E  o. b4 b' x
, {6 l5 }! A* ^" l; U5 G$ K%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%3 n. H- h" {) @6 \* t; N
5 i2 V- _" ]. A% T* T' o  ]4 v! H
>> F = @(x,y)y*sin(x)+x*cos(y);
  S. g0 R- R1 m$ V  w. r  c
5 @/ @1 C/ q/ E8 ?>> Q = dblquad(F,pi,2*pi,0,pi). p6 `5 l7 V- N! f9 r+ [! i7 P& n* t
5 s4 U( |- d+ \# k
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
- P( @: g9 R  e7 y
; N. {% e. `4 Z- j: ~0 G3 i>> h_g=@(x,sigma2)exp(-x^2./(2.*(1:sigma2)))./sqrt(2*pi.*(1:sigma2));
- b$ T4 o2 ^* a$ O7 ~6 z( \2 k# h# E2 ]$ v$ P, l, K) k( e
>> quadv(@(x)h_g(x,3),0,2)) F% r$ Y7 A; E. t

2 h9 R! x# }  E0 Hans =  i& [# _6 Z  l9 z8 P

2 q" B2 ^: \* t0 x7 F3 o  f    0.4772    0.4214    0.3759  _% I/ |, G# }) s
2 F2 P* q& ^# e& |/ P# ?
>> quadv(@(x)h_g(x,2),0,2)3 {  a- @1 P, B
! W, D, }6 ]4 Y8 i
ans =) ?5 h" [/ C, j+ |

* O( ~9 |9 V6 M, f. O6 @- i    0.4772    0.4214
- _' y% N6 k4 W5 Z4 k
7 F3 x4 @9 `1 q8 Y5 Y$ M2 o>> quadv(@(x)h_g(x,1),0,2)
: R+ f2 n( X+ ]: X8 p3 L
0 u' }& D' A3 \0 O1 X0 k. Tans =
8 E' D: W% C  i  E, h( T$ U2 a1 E3 T$ \' M: P9 ?
    0.4772' B( L1 \8 L) c$ S- F' m8 \

- u0 y5 n5 k5 j: R" I%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%+ _6 e/ @* r3 [' \5 }
5 M+ y+ V# i( c+ |# E
% the file to creat a function with parameters
+ k' o, ~9 @% c, N0 ?( d: M1 `function y = poly3_fun(x,a,b,c)
9 x' l" |8 \! Jy = x^3+a*x^2+b*x+c;
6 |% a4 c5 e4 S: I$ s  I( z& m/ I' x' C- D$ i9 E- E

  Z  g& C: R1 [& ^. S! z2 M% find the minimum of the function f(x)=x^3+a*x^2+b*x+c
5 s3 t; ~4 @' n" `6 afunction [x0,y] = funmin_para(a,b,c,x1,x2)
% A% Z/ z9 C3 G' q5 moptions = optimset('Display','off');
2 f. }* J% T2 x6 X& u% x[x0,y] = fminbnd(@(x)poly3_fun(x,a,b,c),x1,x2,options);/ Y9 n( F# c8 F, h
% plot the function6 _; P' ^8 N7 k6 D) f
end/ I+ r" |( E- V6 e

' m2 Z+ R" v) b- p# `- @0 n; K+ w1 P1 \9 V* Q8 s
>> [x,y]=funmin_para(-1000,10,0,600,800)
; W2 g- E: U0 ~; ]1 z. @! e8 D+ n
) j9 a. Z: \0 F+ h7 K: B ! {: l" a9 b' M. _% v

, h( U- K; L4 h! E, W6 y- l+ L%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
7 w  X% G! W& e& X& B$ Q- X( ?4 M, M9 T  d" a8 J
" B, o9 H2 p; o- P2 B2 L$ P
$ K  m$ v& y) _9 v
% polynomial operation
& h: G- H  V) @9 bp1=[1 2 1];                         %定义多项式- S; o- V! j) S$ I. z7 {4 l8 I
p2=[1 1];
  q+ f( d4 A; f3 p! slength_of_p1=length(p1);) F; @5 s7 @9 Z- L
length_of_p2=length(p2);1 ^1 _1 v2 R- L/ B- ~( e1 o
if length_of_p1 == length_of_p2     %判断两个多项式长度是否相等
! j; s! w( U- ^2 r, D    p1_plus_p2 =p1+p2;              %多项式相加" @; l' j8 F2 {  w2 @
    p1_minus_p2=p1-p2;              %多项式相减
/ w3 t- {5 |% G* m1 celseif length_of_p1 < length_of_p2
% q& d% V3 o0 l2 `$ {' ?6 S        temp_p1=[zeros(length_of_p2-length_of_p1) p1];
, q  G% g0 M# W        p1_plus_p2 =temp_p1+p2;
% H, n6 m4 n4 C" }        p1_minus_p2=temp_p1-p2;2 ?- z4 P3 x1 S% y
else
8 l& E# g% Q6 h) k+ D. n. k& H    temp_p2=[zeros(length_of_p1-length_of_p2) p2];
. d- b, g1 O) E% d! l6 J    p1_plus_p2 =p1+temp_p2;* T4 j& a- C3 ]7 t- a
    p1_minus_p2=p1-temp_p2;
  ]# w0 q6 U7 lend) `( d, b8 n6 X+ Y
p1_multiply_p2=conv(p1,p2);         %多项式相乘
" Y: `7 O2 Z7 P/ n* _9 jp1_divide_p2  =deconv(p1,p2);       %多项式除法; U1 e# H* E, v) N8 E$ i
p1=poly2sym(p1)                     %显示多项式 p1
6 K. A7 O; `) \- t/ O' cp1=poly2sym(p2)                     %显示多项式 p2
6 q0 x; {' F8 V7 k+ Hp1_plus_p2 =poly2sym(p1_plus_p2)
% F4 }$ P  r$ Q/ Z% R0 L% d( xp1_minus_p2=poly2sym(p1_minus_p2)2 ]2 i! {6 n  s5 x/ S, G
p1_multiply_p2=poly2sym(p1_multiply_p2)) V8 \7 Q" U9 P' |+ h4 g
p1_divide_p2  =poly2sym(p1_divide_p2)* {9 x$ }) ?: D- f1 c

; M  E( x) |4 T8 I0 U& {6 |0 ?  T 2 b; a5 ]# B5 y3 d& Y* P
6 F" |; R2 W6 z' ?
- \4 n4 m. j* K: e3 t0 s
- u9 P9 o2 e# E& r3 `

1 }6 z  @) {/ \( Z2 d3 b( U
  T3 ]& @7 o. gp1 =6 {/ u: I+ e, `% |

8 o6 t  u! s! v1 U1 B/ }! dx^2 + 2*x + 1
' R0 r9 e9 R+ S6 o, A
" ~9 |& q2 E5 F3 f( |: @ ' z. s' X6 L2 |+ J' Y  m
p1 =! ?  L& M9 D( c' b6 [. D, I; B
) j- a+ w' x: o8 j) q* m: P
x + 1
- p/ v( O0 D$ J- q! B
5 F; M4 q  l+ v / |+ v  ?$ N+ @! l7 h) o, T0 t; Q
p1_plus_p2 =
5 s  c7 Y3 E  ~
/ K! g; s! U/ A. M0 ix^2 + 3*x + 2& o8 T  N6 w( z( ^) l& q& v

# Z& I7 y9 ~8 _/ M ) a2 e! `. @  d9 N$ A1 A) O% I
p1_minus_p2 =9 ~& z- `% _' t% }) \- V' Q" a; f
( R" j" H* m; v$ o; M
x^2 + x* `/ T& x$ }! G7 {

) {  O" e$ P2 j" H% ]
1 g* a8 d- h0 \9 w6 dp1_multiply_p2 =
2 z+ C4 z) |: J5 k7 A0 {0 M4 l $ J; W8 n, ^8 u0 C
x^3 + 3*x^2 + 3*x + 1
/ y0 @8 K- }1 d1 l) Q. g   v3 x8 d( N3 ^) j% q

$ Y' X; M/ N! @! |6 G) C2 hp1_divide_p2 =; j* x$ W! A( p0 ]$ E0 n
; }; m- q# K/ K6 @
x + 1
' y3 k- F& Q5 X% y) c; A6 P. f  i+ R. b  {! {5 c
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
" R" c; {2 A$ G0 T9 d
3 G! V( `: r8 q: } 9 i) P2 _6 X+ g# Z" L3 j% F+ j
* w% |9 K. X+ E6 S
2.编写一个脚本,判断输入字符串中每个单词的首字母是否为大写,若不是则将其修改为大写,其他字母为小写2 Y, y$ q/ }( Z+ p
8 @. i6 G; c2 Y; n& w# |$ E* [
参考答案:
! M1 P9 O+ N0 E5 S3 {! _  v% V- U, K& k3 s& u+ }# o  ?+ h  Q
脚本文件内容为:4 L$ ^, u  J! i9 X% _  S4 ^
+ A5 L' K3 |4 h- W8 p, ~
str = 'this is the string to be converted';* c5 W4 e' A7 e; K; _9 a

1 L( A1 K9 y" O# Rnlength = length(str);
+ J" X) k$ G% c. d' ~3 z) }8 o# d6 Z
6 t, @$ w2 X2 ~2 v1 c. |# Dfor k=1:nlength0 s% d" }) a0 u( c
' c- ^. s) o/ `# G! Q
    if (k==1 || isspace(str(k-1))) && (str(k)<='z' && str(k)>='a')' [4 [# s% l1 k; p# I

' j$ |9 \# \4 k: d! C& Y# B        str(k) = char(double(str(k)) - 32);, O  @$ b! }3 z8 @4 V: K

8 I+ k2 V: v# B6 k" {    end
) {+ z6 z: l% e, S& {: Q( }  l8 _
, [9 H7 ?8 }, z" \5 `: zend
; {) u/ Z- O  V0 M; m' Z# l  C5 \6 e  @5 z" ?1 d
disp(str);% z/ X  H9 {2 C& U5 Y4 ?) o0 V
! J6 m  X1 {% b% ~) j$ Y- o
; q' F+ a) @2 B7 K- k6 O
& P% O0 ^: T) ^% l9 ^6 m/ o7 N8 G% ^* \
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%$ [8 S! O+ z! F: c

- G: p* }8 v6 h9 z6 w4.创建一个结构体,用于统计学生的情况,包括学生的姓名、学号、各科成绩等。然后使用该结构体对一个班级的学生成绩进行管理,如计算总分、平均分、排列名次等。
  n; C/ `$ V) z7 l5 o( A
7 ~, B! L( x1 I: j# J- e参考答案:# m0 G" x1 p% Q$ ^' X6 h
8 f9 F0 \' o' [
>> structtest=struct('name',{},'number',{},'scores',{})
" z9 w/ U7 H* n+ z1 U9 q) o: z1 p& x8 P3 i8 @6 }

: c7 s6 W. C1 N8 G* O8 {
$ L# b4 K- M9 z% W% r%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%# |, a6 l& n1 c/ M! }
' W! l' _) q! y
1.创建符号表达式4 ?5 Z5 ?% }6 D# ]
& y/ F' K. m5 y8 O. K
参考答案:
0 a7 G+ F9 r2 q, E% {
3 F; K1 [/ _- e$ e>> f = sym('sin(x)+x');
) j- [2 D, E7 c. w& V3 u9 n. o6 U
# R% R9 v" a9 D2.计算习题 1 中表达式在 、 、 处的值* @' Q* T- l% x
3 g7 d; f* s1 Z. F  x
>> subs(f,x,0)- W7 L) K! s: z& a8 o, W

1 u$ A/ i) ~2 p; w8 b: i* ~- Mans =3 J. d2 v  ~. E0 ~
! j! R2 Q* r/ m% d
     01 z2 {, R5 n/ Z; u. y5 n& y: p9 t$ C2 o

- {" z9 e6 m) A: c, k; z* c) E2 x>> subs(f,x,pi/4)
% |) B* X) |# S- W( \% {% U2 y
# V  n" ]; R- v! Oans =* x" L" I3 N$ J3 e0 l/ k
, [1 I7 a: R* y' y/ t% O2 J% e1 y
    1.4925/ }) |" W, U. C  D% f

5 S: V2 ^" a6 E3 p1 g+ l ' S5 f" x3 x9 P2 p& m

* z( e4 j8 |2 e- d%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
" w. j2 j; l0 J/ o2 C2 ~. _+ H  {6 P4 n- q
xth = 0;) [# k6 g3 n$ `' n+ g  x2 M. R3 d: Y
tic
1 p" q7 H9 S, v+ u2 n/ [for x = -10:0.5:10
/ V, d. ?) F, r1 g    xth = xth + 1;" F% `+ x+ I. S, f
    if x <0
% ^7 k& [4 D3 k        y(xth) = -x^3 + 5;
3 P! |) P/ b( z  j. d  }+ X    else  X  z% X8 S" a, T- z
        y(xth) = x^3 + 5;% w: n: ?& |1 N, o3 @
    end
5 s* [5 ]; |0 K8 b2 C$ send! _7 K; Q8 C$ M1 [
toc
7 v! a* E, k* G2 H+ v5 e2 X
3 ]! y0 A. q  I' b" `: l%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%" S. t: z& C. d" q
1 F% g! O& n8 t( G  X4 j
tic
6 v% y# l1 A9 H1 l9 U$ ]7 wx = -10:0.5:10;; o; h3 ~. b6 L5 t# D1 R
y = zeros(1,length(x));
1 d; m$ E/ v/ Z4 ex0 = find(x>0,1,'first');5 W; y, I) N& o
y(1:x0-1) = -x(1:x0-1).^3 + 5;- a( v2 L/ B5 `* A8 c3 a
y(x0:end) = x(x0:end).^3 + 5;
+ `1 t4 N' O: wtoc
$ N6 [' p0 F) l1 W9 r% X( {2 ]6 p9 c) T- Y" C! S( G
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
; D/ E: }' ^# ~, k. F
3 [2 ?! F1 R' P! P- T: ~; b : w; h& k3 `2 n* r: c0 a
. |2 E" W* x' Z; ~; x
1. 在同一窗口中绘制函数在 之间的正弦曲线和余弦曲线,步长为 ,线宽为 4 个象素,正弦曲线设置为蓝色实线,余弦曲线颜色设置为红色虚线,两条曲线交点处,用红色星号标记
* U9 O" ]3 n3 O5 w# |/ L# e) a2 F, t3 I* @8 a/ p
参考答案:
  i4 o0 {3 Z# A. U, Q5 [; @6 v, C5 o. U
>> x=0:pi/10:2*pi;
1 i4 F, j) h2 c. a5 d
6 `: n' x+ k- a6 p1 X+ A>> sinx = sin(x);
, B7 X% \; F; U9 t1 x$ R5 a' Q) G8 ^- S7 L. Y  h
>> cosx = cos(x);
. v& w9 m& m2 U" o9 D2 e
; l6 q& k0 I3 _* E, _, L+ q>> figure,plot(x,sinx,'LineWidth',4)& s. V, {! C  \
$ \+ l$ j) Y% M( P* u3 B
>> hold on,plot(x,cosx,'r:','LineWidth',4)
1 V9 o! L  u" c6 N% n  S
8 r# q# x- ~! V7 |( [- m9 L$ e>> hold on,plot(x(find(cosx==sinx)),cosx(find(cosx==sinx)),'r*','LineWidth',4)
, |6 |% r$ K6 x3 [
9 J7 N* p4 Y7 s0 d# ^ # {* e& g$ V+ P9 ]
0 F9 k; m3 C; b; a, m
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
2 ^* n% g1 k, z0 F, \( Q3 i5 k3 A9 n" [% _4 [
1. 编写 MATLAB 程序,绘制下面的函数:7 u% @6 P/ Y" |

9 J' @6 T. a3 H* U. I,其中- ?9 d* ?6 l9 o( r, g4 S
2 V! N- s' _0 ^
该程序在绘制图形之后等待用户的鼠标输入,每单击其中一条曲线,就随机修改该曲线的颜色,包括红色、绿色、蓝色、黑色和黄色。
9 A8 C1 h) H  V2 w- M! ^" B1 d( b* q9 k' D! R) d0 E
参考答案:9 M; t2 N5 F. z9 k# _) n5 R8 K

1 C# W7 R' A5 L! }4 Ut = -2:0.1:2;. W0 D- ~' g2 e8 u: v! m( W5 x
/ s8 a0 _% b& T1 I& [$ X
x = cos(t/pi);
. o' u, H4 D9 }* Z
  J0 U1 Q) ~0 i4 t9 c0 J( by = 2*sin(t/(2*pi));9 E. l  \1 A3 ?  \

5 N  c  ~2 t8 M( p8 {8 A- @" Nfigure,plot(t,x);
, n# J' m- i4 C$ K- F; Q$ Y
& b( I3 d* e# r2 h1 G5 f; t: zhold on; plot(t,y);3 P6 U' R4 V# T& ~, @, B
0 @' y' V8 \% D+ X
%if waitforbuttonpress
8 m$ o# ^* }$ h) A  o) i
+ J4 _* L! I7 ~  N5 ]while(1)" Q6 T6 P6 b( a
/ ]' @' Q( D9 o/ n7 @: h
    if waitforbuttonpress==09 d( e# Y5 K$ H

& m! p1 J; ]- j2 z) }0 K3 h2 m; a( |        get(gcf,'CurrentObject');# J$ r7 r5 m) ~$ v. p# ?3 h+ H

! |) N# T, t! I: ^% J& J! [9 J, b        c = ceil((rand) * 5);" _$ T( ]0 j) u

' e( r0 X6 X( }        switch c
+ _  r; t+ G+ C3 y$ Z$ B8 D* V1 u
# q6 ?4 F, |1 F- d- b7 a8 w            case 12 [& L# H% n2 k

8 l8 P; v" B: c, J- Y# Q                set(get(gcf,'CurrentObject'),'Color', 'r');
7 ~; Q& H5 t4 a! N
0 q' q0 f' {" T            case 2
9 g4 m# t$ y9 k3 W# \2 I
- ]9 v2 l5 U, m. ]                set(get(gcf,'CurrentObject'),'Color', 'g');
. ]/ F- d6 n. C* S! ?, g5 F& d8 f6 U* h) r9 @; Z. e
            case 3
6 p& U/ n0 P7 G9 C* d* Q8 _- o* x; T/ L( C7 X, L
                set(get(gcf,'CurrentObject'),'Color', 'b');
- X! i$ a! x6 {& \2 H% k) R( K7 V4 M* ^$ o
            case 4
9 L5 j4 v# {5 `0 c3 k' e7 |3 F# v5 k. P7 a: M& o  v9 e1 R
                set(get(gcf,'CurrentObject'),'Color', 'k');8 w5 n+ w& e* D# i
4 L: |6 w) \( c* \6 I. B5 a
            case 5
8 n3 s1 c# N: Q' y  L9 f( {* W! L3 q& [3 ~" z3 S1 w/ u
                set(get(gcf,'CurrentObject'),'Color', 'y');  i* y$ i9 Z: k5 P& T7 L, h8 G

8 _% M- g. ]6 F. l: T        end
7 N4 |! C4 z) E* L0 ^( W# J1 M! Q+ a1 w) O
    end0 ]) D3 E; f8 j, M7 Y1 y1 ~( i

0 a' x: Z5 Q. C9 K. iend! x3 c; u9 w6 b/ O7 r  c# t* N$ [3 Y

& o% e2 G6 p$ N( n) _
: v6 Y* c& N. V: c
* w8 s* t7 t8 Y, f$ F. f3 a& K2 |. x, h1 K: b# V. B
5 ]9 x7 `, E9 _" _3 y  ^" p

该用户从未签到

2#
发表于 2020-3-25 17:56 | 只看该作者
MATLAB基础教程之实例原文件 部分
您需要登录后才可以回帖 登录 | 注册

本版积分规则

关闭

推荐内容上一条 /1 下一条

EDA365公众号

关于我们|手机版|EDA365电子论坛网 ( 粤ICP备18020198号-1 )

GMT+8, 2025-11-24 09:03 , Processed in 0.187500 second(s), 26 queries , Gzip On.

深圳市墨知创新科技有限公司

地址:深圳市南山区科技生态园2栋A座805 电话:19926409050

快速回复 返回顶部 返回列表