请问，lsqcurvefit拟合后如何显示相关系数R^2？

limopcb

请问，lsqcurvefit拟合后如何显示相关系数R^2，感谢！
0 K8 q, \& l) ?6 m, k, Qclear;clc;
T=[293.15        298.15        303.15        308.15        313.15];
" [, Q' N$ ]! G1 b, @$ J/ D0 Pc=[0.000378156        0.000425433        0.000562474        0.000684178        0.000981096];
TT=T';
cc=c';
) y7 r5 m; [- c" |4 B' s+ o9 i, zx=[TT,cc];
Hm=33509;
7 P. [- `' l1 m$ e( `Tm=408.65;
a=0.3;
fun=@(q,x)(-Hm.*(x(:,1)./Tm-1)./(8.314.*x(:,1))+log(x(:,2))+(1-x(:,2)).^2.*((q(1)./(8.314.*x(:,1))).*(exp(-a.*q(1)./(8.314.*x(:,1)))./(x(:,2)+(1-x(:,2)).*exp(-a.*q(1)./(8.314.*x(:,1))))).^2+(q(2)./(8.314.*x(:,1))).*exp(-a.*q(2)./(8.314.*x(:,1)))./(1-x(:,2)+x(:,2).*exp(-a.*q(2)./(8.314.*x(:,1)))).^2));
q0=[0,0];
q=lsqcurvefit(fun,q0,x,zeros(size(x,1),1))
plot(x(:,1),x(:,2),'r^');hold on;
) v% C# L2 v" J/ e6 Tezplot(@(x,c)fun(q,[x,c]),[290,314,0.0003,0.001]);
h=ezplot(@(x,c)fun(q,[x,c]),[290,314,0.0003,0.001]);
$ F+ A) ~! k1 j+ \" ~% k

Allevi

非线性拟合，R2没有意义的
% e9 T3 h2 u9 B- M, K参考
) k) `0 B0 ^' v1 z' i1 `statisticsbyjim.com/regression/r-squared-invalid-nonlinear-regression
blog.minitab.com/blog/adventures-in-statistics-2/why-is-there-no-r-squared-for-nonlinear-regression