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MATLAB基础教程之实例原文件 部分

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* a8 q( U' G* B( m' I>> str=['MATLAB 2006a']
# H0 P  S% K  W5 W
; F' t' f& p* z2 h' O>> str. u; p0 I( U: J! @; {. s; X' W
+ ?. B0 A+ {/ I" K6 C4 o: `8 y1 C
>> disp(str)7 m/ D$ O0 A1 y
/ o4 M9 L. y& X: y
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
0 k. V# c$ {! U+ ]6 B3 b) r+ @# n1 d
>> x=-2:0.2:2;
2 ~: V$ e. m) Q% V
. i8 g3 y2 B5 _; d1 v) O>> y=x.^2;7 l3 r0 X+ w; o# h/ g

9 Y4 {, T1 k0 |- D2 F+ r>> plot(x,y)
; h2 I: x% f  v$ J# i% K
3 t% U+ w1 a/ o% H- [  M>> str1 = num2str(min(x));0 s1 a/ X4 j7 C, t2 `
6 e+ z6 p; f" |- I! `. X
>> str2 = num2str(max(x));' e) ?3 ?: P  [8 J. T% e

1 X+ ?: y. e" D# L' c2 T( s>> out = ['Value of f from ' str1 ' to ' str2];( l, l* t9 ^' B' ?# c

; K1 W! ]; w4 b' O. X7 k+ _%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
& }1 ~, S3 A% |+ m/ [9 p. s5 b$ P- j! |: a  b% c/ r- t" `
>> A(1,1) = {[1 4 3; 0 5 8; 7 2 9]};
. Y3 s3 U6 W( |9 E' c. w" R7 B, u) E. m/ y4 Q2 O
>> A(1,2) = {'Anne Smith'};
* [0 {4 e. D- q7 L0 F( c0 `- W
4 k; `/ @: ^/ i) c2 G  }, l* X>> A(2,1) = {3+7i};! @$ C. z3 f# J9 s! F

9 P. H! S2 |" y1 s" a0 E1 T8 d>> A(2,2) = {-pi:pi/4:pi}2 J5 d5 E5 C$ u. k
; V% B1 z: z$ x( ?$ f! _: t
>> B=cell(2,2)4 d: C0 n) U# M3 V3 Y

) R0 w. f3 R6 K9 t>> B(1,1)=A(1,1)$ ^+ V. X! Y  D
>> celldisp(A)) E0 i# y1 d, i# o+ G2 g0 a6 D2 ]% N8 `
>> A{1,1}
4 n; H) h" |6 V# {. D4 a! A>> cellplot(A)
8 ]$ ^4 w% E7 K
! e2 j' ~4 `) B8 {6 O%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
+ h& x# q5 P" ~* o" L1 k& p
0 O7 U' G4 J+ i6 X- X6 }% L>> clear
' D) c7 i, V+ E7 q3 _/ kA=cell(3,3);. p6 U7 i6 R- Q2 H
for i=1:3' E! R0 i& Y3 F0 T5 Q7 y- Y
    for j=1:3
, {' D  z: x; ~$ g- F4 I$ z4 l+ G        A{i,j}=randn(i,j);9 r! D% P" t+ W6 o- l# w5 m$ _
    end( g2 r( B! y3 e0 _
end
1 ?$ J7 i, X9 I) T: u2 _% G  N>> subplot(2,1,1)  v2 ^, H# C9 d
>> cellplot(A)
) }4 k. R2 C8 c  E9 w6 Q>> A(2)=[];# B( e/ o6 d" b+ B) j: r
>> subplot(2,1,2)
6 F  a0 P) g/ n>> cellplot(A)5 {+ N( `! g7 P, \
>> clear! d5 g/ {  G  [& R
A=cell(3,3);
, f8 w, E: b% O2 R0 ofor i=1:3) H8 x2 ?# F9 p0 ]# y2 g
    for j=1:3' F1 {% `- O, B; H1 X
        A{i,j}=randn(i,j);% l2 W! R- f( c- Q* s$ k& C3 v" x. D
    end
1 b/ E6 _7 n  L: F6 K- B1 {  nend
; W2 q/ J0 R8 E: L# B  ~>> subplot(3,1,1)
- J9 C: w  e* X! Kcellplot(A): Q' t4 n. K' i9 N+ h
A(2)=[];5 n+ Z6 x; x4 Q. ~0 q  e# Y2 g9 p; i
subplot(3,1,2)* h/ ~; K8 p$ {; x
cellplot(A)4 B% \7 J9 ]  l4 N" W: P7 b
>> A(3:5)=[];& C1 B! x6 F: e3 g/ `, w% X
>> subplot(3,1,3)& F: T& A; L! w
cellplot(A)
6 _. ~/ }' R' h : U* Q. o) B% v8 R
" C3 k- a9 `9 ^
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
. E9 Y" x7 u" n& |  X! ~( W) D! a; y$ Q+ z# o
>> person.name='liuhuiying';
0 h) u" P4 j$ Y% }4 m>> person.height=162;
0 q' `& A. S1 n& N>> person.weight=51;. z' s, ~* H1 m8 `8 n0 N
>> person.hobby='swimming';/ Y  p/ d; t+ o/ c" E! h; n
>> person
* d; u9 A) Q9 q/ ]& k: ?, v5 U% P( S- Y' W; [
>> person(2).name='zhangqiang';% B5 J( M$ b& s- O
>> person(2).height=175;* U+ p% T1 ^4 y, m
>> person(2).weight=65;
  k- O1 W1 E9 A9 e$ c% v>> person(2).hobby='Game';: H5 D8 b) s% u- X. V
>> person
; ]2 C7 r5 o# H" P; w. X0 v& ]# g! C8 l: S& A$ N4 z, G  V
>> person(1)
/ ?! z" V% O* Q) P1 Z# G7 H
0 _9 J" n! m' F' z4 z1 \; o' |>> person(2)
: Y4 m1 Q" A2 ]" \, z5 h
/ R2 W$ ?  I9 o5 D+ _7 Qperson =
0 }6 }1 a/ o  B
2 n: K5 B- }- {! F6 d0 z      name: 'liuhuiying', ?! \: D3 u/ j6 C( w  N6 H& y
    height: 162
+ P) G% G1 L1 @# \0 p3 S    weight: 51
3 K: @) I, o& I: Z0 q     hobby: 'swimming', {9 Y4 ?# a) q' G6 d, H. e
& y: \2 F( R  @9 A6 F! L) q
, e0 |* c* t% g  i9 S5 s  E
person =( x% j3 q8 `" K2 L2 ?

& D7 _7 k1 ~* s% ^/ @1x2 struct array with fields:+ ]- P1 Z: L5 L/ W4 O1 A
    name
0 n) o. {0 g* Q0 c( ~    height. ~/ s" e7 d% n# v
    weight+ n. }$ ]9 h- ~) Q) _3 }7 A) ]
    hobby$ h. t, D0 e3 A, _1 l
( Q) z9 X, M( W9 C
9 a$ c: y3 L( A
ans =1 j3 w' G6 ?, n, G7 ?5 F

5 e0 t5 z1 `" ~0 X+ P7 V      name: 'liuhuiying'4 I6 T& H) o0 I: j% k  C
    height: 162; x0 r/ ?) |6 z2 v
    weight: 51: ^! }* i5 x* K) E# Y4 _# N
     hobby: 'swimming'
3 [6 h! {% D# D/ M+ k+ p2 {7 G4 s) ^$ [1 ^
1 R* _8 _! C+ ~' ^6 [
ans =- z, M; A. [2 m1 Y
$ o# F: @/ t# U$ g7 {3 ~2 V  k9 l- M
      name: 'zhangqiang'
  t* O- b' X! [  v( P/ o" j    height: 175
) Z7 U# s# I9 L2 S' i    weight: 65
2 W8 C  P# N8 V0 M4 S, x9 Z) ~$ r. `     hobby: 'Game'; _# o: z0 f9 `$ Y& v2 x# ^

# H% W' v8 ^# `) s: C; h%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
' |$ s  A1 P$ V7 Q1 g2 C  N$ x, p# B; `* O
>> person=struct('name','liuhuiying','height',162,'weight',51,'hobby','swimming')  y) n, X* Z; ?# L; d, V
) O( i) j5 G0 t) ?, \
person =1 ]2 a; G- n  J) h, }* E) P. C, V
, n% y, a, X) h% I
      name: 'liuhuiying'' _( b, v4 M" E% ?# L# K% E6 I2 i2 t5 L
    height: 162
5 P9 g/ p; Z5 @7 R! d    weight: 51
  a5 I  V/ g8 W4 ?3 M) T' Y, a% Q     hobby: 'swimming'$ U$ M* b: A- P
% \! m! }# t- F- W$ h4 }
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5 D2 n5 j& B0 y6 }, m& q1 `8 D

- b: k, n0 O5 o1 v' d4 i>> person=struct('name',{'liuhuiying','zhangqiang'},'height',{162,175},'weight',{51,65},'hobby',{'swimming','Game'})
9 ^  |7 ?; q* @: m9 L3 j) W5 ~: k! D5 n1 M5 L1 O% @3 T3 Q) E6 z$ h
>> person(1)
$ J* H2 G- m( m& \# C) N2 l5 N; W) N* B1 Z7 G
>> person(2)
5 m. ?; ], j' y- Q7 X8 I* m) M
/ s& ]7 ~  A9 x9 K2 B
# Q0 G: F) W4 e+ R4 \" P6 p2 M# m& i1 d: B' c* E  X

5 l  E8 u) Q# S5 }* mperson =
4 R9 c6 J; s/ d4 v8 H! @# H
0 \/ D! G- {9 Z9 @  Q# r1x2 struct array with fields:) u0 W7 f. x' J. n9 Q& A
    name  s9 j/ y) s' H3 b( N/ E- P. m. t* c
    height
+ \7 o8 J- Y0 \1 ^( G, N    weight1 v6 A" p0 v; s& B- v
    hobby5 M+ s3 F: Q, |5 B3 F4 U5 l# f
. i. a# H& J& [1 y- l3 p

' o8 |" p$ u  }ans =: f2 K8 Y9 {% c: v% A5 R: W

7 ^( l' k( ?9 S- V* Z( S  Y      name: 'liuhuiying'
( E: @' u" B: ^6 |    height: 162, v6 r3 _8 e- `
    weight: 51
4 }* W6 |  w5 K+ n3 g7 l     hobby: 'swimming'6 u! d5 _6 a) ~- Z/ t8 a

. a3 |% H% m3 b- S, Q. Q$ J. D, i; p
- z& I$ g& Y: ]; O3 I, S" Oans =
3 s7 ?' E/ j1 y6 @2 W4 t
( P! }- U* x+ c# _/ L      name: 'zhangqiang'  K! y: _( R5 S6 @4 s- Y
    height: 175
0 {2 E" u0 T+ o2 \4 z' s    weight: 650 l$ k8 i7 S& k0 m9 J
     hobby: 'Game'$ S$ Q  `" j! b

) {' ]! B: _" D/ D+ U%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5; x' h( I/ h3 ]  O' u
9 s& s6 b# u) ~* A1 p( }+ k- o" @
>> person(1).gender='female+ X) s/ B3 p; T

' Q+ C% C( q) @9 E; {" A$ f% m( R, N>>person(1)
" I- L% W& U" d9 g* x* s! {
& f) j- u+ R5 T, p>>person(2)* ^/ ]) Q0 g' {6 O& L
" e5 @. ^5 u* i: ]& d: @9 N) W
person =+ P8 `. v: X5 u5 o. G- a, z1 I  B

9 O" e8 x, h  ]. f; X; h1x2 struct array with fields:
6 [' |  K1 s* P. T9 [    name& P. o& [0 ~, m6 M
    height5 }% J% X3 j- U3 y# H7 F1 L2 h9 J+ Q
    weight$ z" f/ \: ]4 S/ i2 l" s" w; @/ T/ q
    hobby5 }. I  W* a! o# q% D4 t
    gender' o" n" f' j  K* V9 y! }

! p7 L( L0 N2 Z; M: L1 F
; u- r* P/ B# H. Yans =
* K- f) X# w1 z8 D
* e) }; ~# N& R) a9 M      name: 'liuhuiying'
1 B  E: Z. e# ^0 _    height: 162
0 K  s% }2 h9 U1 ^5 }2 s+ r9 U: j    weight: 51, K; Z9 [9 y% B& u" b0 O6 c
     hobby: 'swimming'6 s" O# r/ q! i& B/ r3 Z
    gender: 'female'# I0 I' f5 e. b/ h; |: R& U+ j

" o7 Z4 a8 R4 g0 T
& h7 e. G9 L; R5 Bans =# T8 ?& W0 ?' F1 x+ J

" t; |6 j9 d* Y# a9 }8 n$ o/ b  J      name: 'zhangqiang'
8 O3 z: C. ]* R# F  l) d    height: 175
" N  X" a% J7 `% R    weight: 659 m. F0 _! y# T5 r5 V7 p2 s
     hobby: 'Game'
: S$ g0 ?( f5 ?* K4 T: q. [    gender: []
: t& A' Z3 q: V/ O2 Z, L- g
. h$ u  L  y* i& |" j%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
, X% ?$ l3 c0 E' |$ n" w+ d
: m  p0 D0 |  r# }5 X>> person=rmfield(person,'hobby')) n2 b4 V1 _$ ]9 w: T3 ^: y" y
  ^" W- P# X  X, r6 z9 O' `* A; H  }
>> person(1)
; }+ V3 }. ~' `: _  f. D9 y
6 ^( {! E" H3 F/ R1 h8 I. [5 g>> person(2)
/ E( n5 I$ U$ g/ |7 r, z  c; s
8 P( J- T) P* @% X$ V& o7 e  j ( H+ V4 D$ _8 L% z

( t4 z+ W. y/ Q- `person =
- `: L3 A: |0 r5 j+ d  f4 d3 X( f9 o+ a  N2 ?2 G" {* i
1x2 struct array with fields:/ C5 l9 A7 ?- K- v6 z
    name
' M, y0 b* ?2 J+ ^    height! a7 a' h1 G& F7 H- S' R
    weight% R) }* _6 i6 u! p2 y, p: V
    gender
# |) |& g% y' O, }6 N: {0 J2 @
, f/ r6 T: v. d/ K+ u' O4 M- |! ]( n
: D- ?- w; f) g1 B' r3 Yans =* v6 b; g, a9 b; F7 x+ a

- i: S- ]/ C. \      name: 'liuhuiying'
) H, q& [. S3 |( H& R/ ~    height: 162
6 }" A- R% Z/ T6 J; I, o# N! T) ~    weight: 514 N$ T; t9 p6 F  |
    gender: 'female'
5 p4 v: t8 ?$ c0 y8 U2 p. d6 D& h! G( n  d) a; P1 x

/ S) g" S4 L+ X4 u/ i: Qans =
6 n  R# \7 e' n0 Z9 F3 V: L5 q# Z- @" X5 D& b( K, I. T
      name: 'zhangqiang'( E: z4 u% x3 D9 x
    height: 1753 ]' ~2 _2 [- y9 @  ^
    weight: 65
' Z2 Q' K7 u3 F4 @    gender: []; w1 f% }. F6 i- m; K; B
) G1 x5 M. J: G" \. j$ F- {
" D# E( Y/ l) L& f( A! P: O# _
8 U* P8 S' N' G0 M  e% H1 s% M
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
$ i3 V% |, Q& P; i; G8 }$ }
6 N0 l9 z! V2 C. {( f>> person(2).gender
. j1 d9 y7 w' v: V0 o% W0 o! i4 t& d/ t; D  O' S
>> person(2).gender='male';
5 E/ {% g5 i$ o0 Y% ]6 F6 `/ O( ~+ ?" j+ p! j1 p" s
>> person(2)8 C# F' v1 Y6 U! k8 O9 \
$ L, X4 i+ W8 N) z* X* B7 V2 a5 T

* Q4 T- S6 ~) M) q
- \' t+ B2 G- C* t# x5 g) E0 l, @ans =
" E4 _4 y: N0 K) l, h* G# T
- \# }4 H1 \5 {0 d: L     []. i- r7 e* L* j6 z) D* y" o

- H4 y) M6 ]6 m& F' L5 p, M" y! o& b* g
ans =7 |! {- n, E& ~/ ^& q

; g+ a# I# W* E" x: U* X* l+ L      name: 'zhangqiang'
; h; l, |$ |/ a+ x    height: 175
' m6 B* e! o1 x: x0 n    weight: 65. ^: G- f8 Y% ]) p: E# z$ r6 Y
    gender: 'male'
+ l$ ~4 v, h, ]* r( j2 o
/ u. G, [0 [, t* d  v ' `) T/ j- B% G! V, ^* ~
. M, j, Z- k, C- N' v# q) k
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5) C9 w, O, W6 B& |" Y3 F- h

6 u1 v5 a' c- ?4 d9 o  U7 Z>> A=[10 20 30 40 50]
$ u6 L( ~5 J! v6 E2 ]# C0 q
! O  z5 m, Z) M; p& [% M* M; V  U  T>> B=[10;20;30;40;50]
; t( p8 q& s3 K9 l- `" v5 _- a3 j1 J7 r  l4 u' d! G7 ^
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5. c9 G3 X3 O: M. i) @
* i& n) ?7 T! p
>> A=1:2:8
1 a/ o0 K( I5 A" @% z4 \
  s9 q. N" Y9 n! x>> A=linspace(0,12,4)
# H+ d% g8 J# N0 j0 E0 L# n6 Q  G8 J% l0 l! s* F/ c$ C+ {
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
- E$ _" m2 D$ b& ~% Z+ z; y1 M4 f% I& s& _0 Y
>> find((A>8)&(A<14))       %找出矩阵A中大于8并小于14的元素的单下标索引+ ~& C# Y* X2 w& C  {( Q( U

) b0 s6 h7 h* k( ]6 g& r>> A(find((A>8)&(A<14)))    %找出矩阵A中大于8并小于14的元素, w# Z; v. ?5 l4 }
% V) U$ H- `3 ?5 I( g( B% g) Q1 N
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5! ~" \8 s& f" E0 a' I1 ?( T

: Y7 V; |' V5 C. h>> A([1,3,6,8])
6 I) Z2 ?1 A0 P2 I/ U
9 f. r1 {$ w  [%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5% }& b: Q4 o1 h
2 }' j* }, f: F# f7 [& T
>> A=rand(3,3)/ S: P+ H" f0 G% r$ a

8 u9 N" m% v0 C5 M>> A(:,:,2)=randn(3,3)
9 N$ O8 z7 x4 Z5 A
/ R( b4 z# c9 R! R# d# L# F6 A2 n%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
; C+ o: B# X& h$ u* X8 \, f3 f2 W5 `4 v" U' X) k+ a: |
>> A = rand(5);& `! k" }* |# a
; Z+ e$ \! x; e( _4 b7 H
>> B = A > 0.5;
( Q2 Q" y; J6 h5 J" B' y
: U7 \5 c6 }' W" d( `>> A(B) = 03 Q( G6 {7 e8 L7 {
$ d7 ~3 w, b) J8 z, Q

+ o2 x; t* @+ `
$ S$ N8 a1 j: A/ e8 sA =- Q. t6 Z8 O% J$ _' l  ^* s- N
! E& I3 \( Y2 F- K% C1 v
    0.1450    0.4018    0.2400    0.4909    0.1112
; u2 \, h$ M, J. x( |         0    0.0760    0.4173    0.4893         06 ~1 q1 O" e8 B( O: S- c
         0    0.2399    0.0497    0.3377    0.3897
5 M- f  X) E$ }3 G$ q$ W1 c$ Z! n    0.3510    0.1233         0         0    0.2417
) w2 @" }- P2 j+ y0 r" z6 o# q         0    0.1839         0    0.3692    0.40393 z) S5 Q! D6 i2 z8 ?; _

1 P6 q# Q* C! K- R( g' J4 y! H%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
: w2 S6 g# V. k
, f) s" A; H6 T  p$ p8 H >> A = magic(4)/ @+ B' Q* |3 C* `& L$ w# H
/ a) }) l9 z* o# ~/ v. g
>> B = isprime(A)
" @  e+ W& A+ o& O. z( T* r. y" |; A1 \& l: A8 c
>> A(~B) = 05 }; E7 d: z/ r- H3 L! |" [' c5 d* M

+ \* R% o( p5 X
4 `8 b1 p. S0 G( A! f
/ k& `6 E1 E5 Z- C! t" S%%%%%%%%A =
) ~, g8 l/ F( Q9 j) z7 Q5 t. s  F/ m! z- _: i) a* M7 ?2 c
    16     2     3    13# o- t* q6 S4 T" C+ x$ N: N! B5 |
     5    11    10     86 t$ Z. ]2 Q, L( L$ @' b! b7 _4 n
     9     7     6    12* j" ^6 c( o- w$ n2 S2 k
     4    14    15     1
% H7 X. l- b8 J5 J  g& a, G- l  T& b
' g' k, w; h8 u& H
  v# H. o! C5 n! ZB =) @) w6 r# X' K7 F9 k2 h
& H! n$ ]( l9 [' n" F% C. d# |
     0     1     1     1
7 R# W' ~3 T! k     1     1     0     04 c3 u6 _' J) Z& P/ U: I/ z
     0     1     0     0+ h+ U5 a* x* ?( h8 g* {
     0     0     0     0
- ]8 w  a& f" e' H, h$ x3 N* B; r! j" y$ n6 J2 m' }7 o0 {& K
4 h9 h2 z: r+ x) N  r/ D
A =" N: L8 w+ U! Z9 y/ `. h9 C

; q) S$ I6 ?6 `/ E  G     0     2     3    13& s4 b) O' `' E. c  C4 o" ~
     5    11     0     0- r) l4 _" O, G, S4 o" o, ^& d
     0     7     0     0% q9 o3 n1 ]4 n7 ~  u
     0     0     0     0$ l4 B0 J: D& r

" p/ t! N/ N  i& Y& b1 ]- A6 l0 P%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%54 I7 }; e6 e( [$ g- f* v  q; }
( W: k; ]" r/ B/ x7 k( t4 J# B, q" ^
>> r=[1 3 5];5 Z3 o( v  }$ _5 w$ c, x1 ]
' B4 O- \/ L* y- o& ]
>> p=poly(r)/ a5 U; h8 e7 C, M- }
8 U: i7 Q" ^, z: Y, q# i, i9 M% X" W0 f
>> poly2sym(p)# C$ [+ \0 K$ j! S5 W! u/ @

. E- k) p9 `5 x# V- w) U>> roots(p)- L; m" M' Z# F% \4 B
5 e. Z+ e5 e' z4 |# s- V6 r% P
p =9 ~$ {3 y) Y* [! }9 m: V

# z1 c, V& m; t     1    -9    23   -15
8 h. r8 n# N5 u8 g- @3 L* u" t7 Q% C- _3 I/ j3 Y7 O+ G
1 G4 q: W. V7 P; M
ans =
8 b; p% I& G$ C5 I8 c8 B* d' R % I. M3 Y# w; e- L; q
x^3 - 9*x^2 + 23*x - 15
, n7 l/ W) P- Z$ S& o
( b5 L! U% ?$ R2 I% X1 f  H$ k: T9 J+ w  t4 l: [
ans =4 M5 b9 f* K" _, N" c4 A

' I# ?% n. P6 {7 E  J& a) d; \    5.0000' I/ P6 Q1 e6 b" [$ a+ _
    3.0000
" A/ O4 O! w+ Y$ c( ]( h! \4 S    1.00009 s5 w7 R3 Q1 q+ i7 G' {) ~
6 R: l: S, b  R7 ?" a" D
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
9 J0 t1 ^$ h4 g! v4 }
/ J9 J6 [$ \9 U* r- V$ s>> p=[4 3 2 1];7 u* n0 Z) x+ H1 D5 }- `
7 }) U' ~3 `5 D  }) o
>> polyval(p,4)
. W9 B& L  l6 Q% v( [  w& X' r. g0 v8 L  G6 z" @% Z# a
>> 4*4^3+3*4^2+2*4+13 ~7 ?9 J/ G8 _! Y6 I
: W  I+ s# i* t& p# h7 v7 b7 ^: P

/ D  M" O0 \- Bans =
/ f2 B( `' N3 e
% I' @3 b8 |' k( Q9 r6 C0 T   313
+ Z8 n, B4 w, B2 T  K  m
2 h+ u  a# P; j$ o( _# X" Q; Q" n: X
ans =
% q# l0 w2 l4 v0 }% z. Q9 D0 J; b/ Z# v* y, |# X! ^5 L7 E' O2 r
   313
* Z3 ^0 n: j* ]0 R2 ~# Z2 d9 W$ V
: s* p% p. b( H0 |6 u: c%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
- U9 l4 {% [. q/ n/ a; [
3 z) |/ d  ?# X1 I# }% fit sine between 0 and 2*pi using 3 order polyn0mial
9 I( A8 w$ z$ q/ u0 Fx = 0:pi/10:2*pi;9 O% y4 m+ V0 Q4 [/ {) M( N
y = sin(x);& @/ a5 R3 d7 F! N2 \
p = polyfit(x,y,3);5 r) V2 i& F, l+ C. X
plot(x,y,'r*');: a. ^  |2 _& w, C, I( V" T
hold on
  V* N4 C' ?  t' D5 S, B3 [3 df = poly2sym(p);
% L/ P. `# I+ j+ ?: @ezplot(f,[0,2*pi]);
2 ], o+ b. G) j; Y( ]4 R: I" o: r1 g# _
>> p1 h7 y' ~% I1 @. i1 w. r
. a/ [5 W* \) u9 B

: j0 q, M' ]4 |$ x& n4 t8 u! I1 X6 N1 T
) F8 S$ ]- Q0 _. R
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
4 T  F2 B) g9 u0 A) x7 r0 ~/ ]( D5 {
% Interpolation using the four methods5 H3 _3 e1 {5 L# [
x=[0 3 5 7 9 11 12 13 14 15];: X* ?9 q& A* U6 A9 m& U: a. @. d
y=[0 1.2 1.7 2.0 2.1 2.0 1.8 1.2 1.4 1.6];  m. |# k: r! @% \% D. \) V
length_of_x=length(x);, z' e8 L& s- C$ Z/ e9 b$ d( |2 r& X
scalar_x=[x(1):0.5:x(length_of_x)];
7 h. ^3 I% [4 l3 i0 {length_of_sx=length(scalar_x);
8 [0 s$ o5 [7 N1 I* ^' lfor i=1:length_of_sx3 ^* B6 y/ Q8 R5 \- B1 f
    y_nearest(i)=interp1(x,y,scalar_x(i),'nearest');# g# P  k! u* \5 A
    y_linear(i) =interp1(x,y,scalar_x(i),'linear');0 d+ z  V0 q8 o" P/ L7 h% Q0 d
    y_spline(i) =interp1(x,y,scalar_x(i),'spline');0 y# l/ C+ ]9 P( ]; W/ D
    y_cubic(i)  =interp1(x,y,scalar_x(i),'cubic');; Z' _6 ~" ~5 X$ F
end
' l2 K7 ^/ K* @7 @, tsubplot(2,2,1),plot(x,y,'*'),hold on,plot(scalar_x,y_nearest),title('method=nearest');7 D9 [  ?: ]% t0 `" q9 o2 R* C, w/ O
subplot(2,2,2),plot(x,y,'*'),hold on,plot(scalar_x,y_linear),title('method=linear');( C3 Y2 x  J" V! W+ R( \
subplot(2,2,3),plot(x,y,'*'),hold on,plot(scalar_x,y_spline),title('method=spline');1 \( p5 Q3 _' d
subplot(2,2,4),plot(x,y,'*'),hold on,plot(scalar_x,y_cubic),title('method=cubic');5 D/ x- X4 w+ ~5 r) U$ k1 t
) y! l2 _) V9 d0 \
. T4 M) V, v* e( V  z2 V5 s( |2 q
2 u5 m- v( i" Q. {5 X( ]4 b

* T6 m% p, E0 e+ r) \%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
% k5 F$ N6 y0 d; ?9 z* @" ?
" w. P7 i3 I7 C>> fh = @(x,y)y*sin(x)+x*cos(y);. l  C4 o9 ?2 n0 A; D* S
; u4 v! d8 ~/ ~( b% _
>> fh(pi,2*pi)
0 Q% m8 g0 a/ p
% c. s% V6 _' o( h3 V( \. e9 B( U%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5* L- P( g2 c& J5 F( \' M
. f$ O4 P) G( O3 Y/ `
fh = @humps;
) f* n8 G' H. d' m( u; U
0 e, J9 ]# d: r: ]4 `subplot(1,2,1),fplot(fh,[-3,3]);3 k% Y# P' C( g, a+ W

* M! G. X/ N" p5 t$ S8 `  Wsubplot(1,2,2),fplot(fh,[-3,3,-10,30]);4 ]& V* J/ T$ \, [3 T
6 W# P3 j1 g) G7 h* ~
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%54 r4 G5 B% p4 |! z
5 F5 q6 P% g, @9 P

9 b& @' d9 l% E+ W9 s5 f
) y8 d) }9 u& n& R% find the minimum of the function f(x)=x^3+a*x^2+b*x+c2 U2 P. a& E: Z: x! r
function [x0,y] = funmin(a,b,c,x1,x2)5 }) Z. v, {; N6 N/ X4 ^3 g+ [2 H% u
options = optimset('Display','off');$ A, g& i- T, G
[x0,y] = fminbnd(@poly3,x1,x2,options);
' s/ b, F. n+ H& M$ h    function y=poly3(x)        %the nested function
& u+ s) g  v' D# g+ k, }        y=x^3+a*x^2+b*x+c;+ z8 T$ b: T' E
    end: `' F$ g0 Z% ]. B  r; A+ _
% plot the function
+ e/ K' j! |9 N6 M; d: ?- s% @8 {3 o  |fplot(@poly3,[x1,x2]);
" {+ h8 @, }, E* y! Jhold on;' q" R7 X0 }( Q3 y
plot(x0,y,'.');
: l6 G1 ?) J" T7 g$ [, k, F/ zend( m2 C- U7 f( ^: M! i
4 a" \  m% Q' l" ^5 B- `6 J/ V
>> [x,y]=funmin(-1000,10,0,600,800)
+ }& p% v; i6 f, [9 [7 O4 j$ h8 t2 y) y1 ?# y
; F. r% c5 L# N& Y% {* a7 f
2 ^0 Q3 |$ x7 K! P( F9 R- v' X
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5 Q2 j! z" J- @& n. \
8 t$ H5 s% I! b* z; s
>> F = @(x,y)y*sin(x)+x*cos(y);0 z# P' M, j- B. j( y3 l

# O' \8 d" b1 T  z>> Q = dblquad(F,pi,2*pi,0,pi)4 n5 [4 V7 r8 r6 X2 \4 Z2 T% @0 V9 m

: {& H  U; D( T%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
! ]1 @4 l/ l5 A# C  c8 h: v/ R( c5 x
>> h_g=@(x,sigma2)exp(-x^2./(2.*(1:sigma2)))./sqrt(2*pi.*(1:sigma2));
, G" Y1 d9 }* d0 v) j( N' z& {0 V- y* r4 |# }' L8 B$ m
>> quadv(@(x)h_g(x,3),0,2)) J6 W( H2 q+ ~

9 i, J# m0 U) _ans =. S" z& R& l- K& W: F. s
6 S. E& _  J6 k
    0.4772    0.4214    0.37597 w! b9 f8 H& Q$ _3 F
# I. U- {9 ], }2 ]8 I
>> quadv(@(x)h_g(x,2),0,2)
* c0 e) R! [0 y8 O& Y
% t) O7 @) e# u; q3 yans =* s2 t6 A2 X' {! g, @1 k  d3 U( n% P
2 r' a1 a- B% ~# [! {4 ]' f
    0.4772    0.4214% h, P6 A7 O; _, F1 N  e6 ~

4 V5 M6 f+ ~. }( A( r# `3 x! x; k>> quadv(@(x)h_g(x,1),0,2)
9 Y) x; h, y# y% S9 T6 C: C; C8 n% G7 U" N' c( `
ans =3 R% q/ V" _5 O7 `7 ]. W" w3 h, R
! h4 K: {, h" |% c& W" q
    0.4772/ J: c1 {+ B$ |' `' M# n- J: ^5 A

* u$ M' G/ ~1 F+ R$ d* y: l, f$ J%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%4 P( U' c7 [& l6 V
; z: ^$ B8 l6 U9 D2 t% B
% the file to creat a function with parameters
, i+ y4 _( P4 U; J$ z( \function y = poly3_fun(x,a,b,c)
- O4 j( ~/ p5 I  L; Z" J3 z% Vy = x^3+a*x^2+b*x+c;
+ Z. ]  U. }% I$ ~
, M& v. ^& Q. v3 R( y4 e( i$ z
  J; J7 T: P$ `7 d% find the minimum of the function f(x)=x^3+a*x^2+b*x+c& \$ R- k! m. I3 X8 k
function [x0,y] = funmin_para(a,b,c,x1,x2)
" l- n; E- z' V1 n3 K  {options = optimset('Display','off');1 V4 s' R# O2 g1 O2 c4 L- f
[x0,y] = fminbnd(@(x)poly3_fun(x,a,b,c),x1,x2,options);6 @5 a7 z6 r, ~( S
% plot the function
! T' `2 [  F& d5 _4 K  z5 Eend
& {  K; x' a2 A
, o1 E  Y5 |- l* H5 u9 ^& r' p  ^5 k# ^0 B& B$ J) Q, b
>> [x,y]=funmin_para(-1000,10,0,600,800)
1 e# o9 n9 S, u- I  S
0 @% c; o5 |. A3 y4 j ! v# X1 u9 m' |9 X
( S5 I$ m) X0 y7 _1 F
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
. n# D* U# y) K% o, ^6 I7 I4 ~) x0 V# P, Y6 F

' A9 I9 ~1 |5 b. r8 ^
  @# M- E& v2 w' a% polynomial operation4 d* z' Q' |* Q2 m, Y! o
p1=[1 2 1];                         %定义多项式0 V/ w; W3 {( o/ P1 O( W  N$ l
p2=[1 1];
6 @3 ^7 z" ]! a, m1 P* [- Slength_of_p1=length(p1);+ ^8 `, @+ D$ p9 @( a' K  z
length_of_p2=length(p2);
& E( W+ E  m9 @. D- j" Bif length_of_p1 == length_of_p2     %判断两个多项式长度是否相等
6 H$ T( Q( W+ ~- B+ d6 P    p1_plus_p2 =p1+p2;              %多项式相加) y3 C- S; W3 ], o" X2 [
    p1_minus_p2=p1-p2;              %多项式相减
3 @* U2 T9 o4 |. y; _, eelseif length_of_p1 < length_of_p2
( w( q0 n; _/ D2 [* ?        temp_p1=[zeros(length_of_p2-length_of_p1) p1];4 y2 p  j0 ^# h4 q6 m6 i
        p1_plus_p2 =temp_p1+p2;
: U' L4 c( _2 a7 ~& F6 o        p1_minus_p2=temp_p1-p2;
& ]4 k6 W3 D1 Z  N8 q. _" Q( melse
; P: R# z$ B1 Y9 Z* X4 }: w+ S" B2 T    temp_p2=[zeros(length_of_p1-length_of_p2) p2];/ F  s2 N# H' K5 c0 \( e
    p1_plus_p2 =p1+temp_p2;
; Z$ H2 F! W/ G" |1 s) X    p1_minus_p2=p1-temp_p2;
* M* M- _, a  f3 w; D1 @end  m- p4 J! c' s+ H' ?
p1_multiply_p2=conv(p1,p2);         %多项式相乘
/ m6 ^9 f7 m6 _* }0 @, }p1_divide_p2  =deconv(p1,p2);       %多项式除法
8 G' h# O, V7 ~p1=poly2sym(p1)                     %显示多项式 p1
6 |2 H. ?0 @* A+ ip1=poly2sym(p2)                     %显示多项式 p2
; x# d  J4 T* z$ a% |% np1_plus_p2 =poly2sym(p1_plus_p2)* n3 M3 q1 P! i/ o7 ?+ O. w9 b
p1_minus_p2=poly2sym(p1_minus_p2)3 ?) u/ I* v# t, B+ ]
p1_multiply_p2=poly2sym(p1_multiply_p2)8 n) [, z/ p; ]8 b' q6 g7 X9 s. n
p1_divide_p2  =poly2sym(p1_divide_p2)
! ]5 L6 V7 e( T4 n$ c. y  |. V* a7 u1 w! Q& u( u
% Z, T) u0 D, Z; C3 J2 |

7 s. {7 K: ~7 E 9 {8 u4 @) W, Z9 s- _

6 u- F2 K& `' X( i4 f4 z " q" \& h* t6 t  r8 }9 v6 S
, ^' u8 c, c, c' Q5 m; l
p1 =: `3 ?3 Z6 F) z5 H5 C4 r6 N1 W
, d. _; N5 B$ J* u- [6 A6 j
x^2 + 2*x + 1; \* o9 I$ n9 V7 r% N: ?- O

2 t7 `7 T- P* y" h( K " e$ i7 E" v: C' T' \
p1 =0 r! q$ g: s* k" z: h
1 X3 h/ z% C: }2 D4 D- z2 p& _
x + 1
4 C7 j  W$ p. A$ v2 \2 i * X8 I+ {& ]/ `& @5 `5 Y
3 e5 Q+ s* t1 q# d& ^% j
p1_plus_p2 =# y" D: d. P8 w4 ~7 h0 o' t: H

" h2 Q  t0 Q# _8 G2 S* P) Fx^2 + 3*x + 2
# P3 j& J& t7 @' U& y " |. o1 s. q$ `0 H
6 w/ D" a% W* I, t
p1_minus_p2 =
8 u0 h( v- |5 N. N( t
7 Y. ~4 L" e0 Q1 y! ex^2 + x
9 b% J1 W; f5 z% I+ C+ ~- r# M5 O
. E6 ?* U. |$ k. G
# c* m# S- f/ W, Q, I8 Cp1_multiply_p2 =' U% v: [+ X9 W! ?- e

5 `, Y3 `7 ?0 |3 |x^3 + 3*x^2 + 3*x + 19 _* i# Y9 Q3 s+ A* C  b

4 c1 Z, k  B; W8 s/ ?
- N& c, ~+ C) W/ `! l- fp1_divide_p2 =6 t4 p( |. F8 t* L2 e
& Y5 }5 N+ I3 x- H' I. Z
x + 1
, Y3 ]) {! \* k0 F* s! V
' u" E. a3 S6 I' U; Z%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
# V; m& f% N  [+ I% B1 ~+ U; q# G5 |3 q' J" Y

! \; [  A) b) k8 W3 g
6 Y& N" @% w) D/ w. y2.编写一个脚本,判断输入字符串中每个单词的首字母是否为大写,若不是则将其修改为大写,其他字母为小写
  m/ `& G! {+ [; i4 |7 H. q
# ^3 Y) l- k  {9 `参考答案:) |+ O7 ?* S$ K8 b% [
; k( n1 Q" Y* d8 l$ G
脚本文件内容为:
. f0 w; K1 c  X6 j( t7 p6 k$ C
% r! R" ]" I! w8 r* tstr = 'this is the string to be converted';" Q  i9 V2 C, C- S  J
  l% b4 }# ?( {4 z& U& ]
nlength = length(str);' B& ~* Z5 _, F# J" O, N: G5 Z

* R/ s* v& T' ]1 Nfor k=1:nlength7 @5 o, ~7 F: W6 m3 T; G

+ G4 Q3 J$ p4 \1 g    if (k==1 || isspace(str(k-1))) && (str(k)<='z' && str(k)>='a')
( r1 r* T5 o6 p: M( i5 a9 h& k. U  a6 ^8 {0 C7 I+ _
        str(k) = char(double(str(k)) - 32);
) L1 P( G: W' n" I7 G
/ a. ]2 Y7 u' s; x4 C$ d    end5 X& `, G+ l  q6 w, y  ^
/ Q! \. i/ |, y7 j
end
2 ?" V, F( w0 {
9 V, s3 ~" ?; {- A& N3 P. c* ~disp(str);9 L2 x% I2 v! u2 o2 R5 {
$ T4 T/ t" X0 [! T6 X" Y5 b

9 R" `2 \- R+ E' B+ I9 N0 n- \' @" D) |; z4 E0 X" f& F) }
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%' V" f$ S+ o  l* q4 d
  D+ w. D4 T2 I8 i  ?3 p
4.创建一个结构体,用于统计学生的情况,包括学生的姓名、学号、各科成绩等。然后使用该结构体对一个班级的学生成绩进行管理,如计算总分、平均分、排列名次等。& P; C; W  \5 N# O. q4 v: g

/ p8 K) t" v9 Q! E参考答案:& q7 f) w& f( ?' I: r0 [
4 Q0 U7 _9 g/ x: A
>> structtest=struct('name',{},'number',{},'scores',{})" B$ q" }$ L0 d9 L0 ^! Z

6 ?3 F* Q# }9 ^0 q3 t! ]0 s
2 {! |. x+ V1 T  |/ f( `# u/ t/ H
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
: D. H% Q: b. ?2 K- `/ U$ y7 V5 D: m6 Y
1.创建符号表达式* m' e/ R  d. V4 D" Z* W

9 X' [7 Y3 j' D2 ?6 r参考答案:  M, c3 d; }+ C

5 X4 U1 E5 D9 \# D7 y7 n>> f = sym('sin(x)+x');; c0 N0 e/ `! x

- k2 Z( Y. y. _/ F2 ~* }4 W2.计算习题 1 中表达式在 、 、 处的值: B0 e' \- G" M* p4 [2 S
' G  D2 ]( u4 J3 q( `7 I  W
>> subs(f,x,0)
7 a7 h- U7 J4 v/ {! z# f5 N& @+ x- F
ans =
/ J" k0 P3 V6 b
8 D5 E  t, {) g( F     07 C/ B! j# Y  x6 o6 p; K
! u/ c* h2 u0 q- `3 G5 P
>> subs(f,x,pi/4)
: `; d' {4 e! c8 l0 ]' s5 Y: ^& D( H9 d2 B
ans =' }, _2 J0 H4 v) G# w
  L; B. _3 p* a# c$ w1 I
    1.4925
1 e' q- q$ F: A0 y, c
7 F; }: h6 f7 G* b5 n
! H. z& B1 j5 L2 O4 c7 @& f4 `: B- c, Q' H7 B$ i4 D/ p
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
1 I/ b* f/ g' W; a/ k& ]& R  ~6 _5 {
, H8 o( [5 |" e3 k/ d8 Oxth = 0;
4 ]: i4 F) n7 e0 i9 etic
$ |9 i( q  s' S- c7 _% X& cfor x = -10:0.5:10& M$ {" M  ?) _' {1 o& B$ v# ]
    xth = xth + 1;
$ _8 K# r& W+ \# Y, U    if x <0
" B; ^) i$ ^6 S        y(xth) = -x^3 + 5;9 X8 y! ^+ r3 S3 V" y
    else
1 f) C+ y& \3 Z3 L0 {  c        y(xth) = x^3 + 5;3 v; i& J; G3 P$ z1 k4 [. I
    end
. }/ v2 J( r# D5 z% D4 t5 Eend
6 l7 n, K" ~" e2 G% d9 O3 Z1 wtoc6 M% t  ?( _/ M
" ]$ x% z: ^+ V7 C
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
$ _% t  k- T9 z, x
! Q% `; r" {5 U/ f5 W& s& h5 Htic  ^7 D2 I! k" x1 C" v
x = -10:0.5:10;: t# p1 ?" }' c) N, r0 q# z
y = zeros(1,length(x));
, v  b" J* N1 ?1 Ex0 = find(x>0,1,'first');" M# Z/ i, c& H
y(1:x0-1) = -x(1:x0-1).^3 + 5;7 h/ E8 X- o; H- s2 t$ F1 ^4 j# A9 E
y(x0:end) = x(x0:end).^3 + 5;
& X$ i5 E% B! Ktoc
! ?/ X1 |8 x3 D! N& }4 I- T
) m1 m- g& K3 r %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
' `; }. ]( I. L  W, C' l5 q( Z$ Z- k4 @

+ Q, J* ~% w" c3 R* T0 P# I# N# ]9 |- Q" _# b
1. 在同一窗口中绘制函数在 之间的正弦曲线和余弦曲线,步长为 ,线宽为 4 个象素,正弦曲线设置为蓝色实线,余弦曲线颜色设置为红色虚线,两条曲线交点处,用红色星号标记
$ g' H6 p' U  I, x+ e3 i- E3 a' f4 T# F) _8 O
参考答案:( a% M# Q, [& P1 `
% Y1 m+ A. W: h9 N" }
>> x=0:pi/10:2*pi;! N! o7 R! F1 X/ G8 X- P- u0 z
, y/ `6 t7 x! b9 w$ h( I( A
>> sinx = sin(x);" {8 a; i% H6 j+ @5 X! }
( b" N# m5 h! ^6 {% g& M
>> cosx = cos(x);! t2 E& X* u, @3 K
. R& K4 G8 \, k, N) o2 O' i
>> figure,plot(x,sinx,'LineWidth',4)
) A4 {( O0 f! ]0 }: I& z
3 F# z" _4 g3 f1 u8 ]>> hold on,plot(x,cosx,'r:','LineWidth',4)
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) V$ j  W/ S, W0 G) M>> hold on,plot(x(find(cosx==sinx)),cosx(find(cosx==sinx)),'r*','LineWidth',4); L! h1 k/ ?) `# X6 Y
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1. 编写 MATLAB 程序,绘制下面的函数:
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,其中
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该程序在绘制图形之后等待用户的鼠标输入,每单击其中一条曲线,就随机修改该曲线的颜色,包括红色、绿色、蓝色、黑色和黄色。
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参考答案:7 y# A/ z# [: A  Q

9 P9 U1 ~! M6 a4 i! j! j, \t = -2:0.1:2;
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2 y; c6 {% ~7 S- yx = cos(t/pi);6 W. O6 k2 {, C+ D! Z# A: N# j& x

, D; i: T6 Z# L6 {/ G5 @; wy = 2*sin(t/(2*pi));
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* ?* t  h7 f0 W# G) \0 Vfigure,plot(t,x);
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# }' Q* R6 w! Q0 {& |hold on; plot(t,y);$ i% v8 p, ^& w( A/ w3 m3 z8 U5 v+ N
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%if waitforbuttonpress' G( s/ ?; g# H' F9 v: P+ \+ x

  W% F) M  V3 Z; @# bwhile(1)
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    if waitforbuttonpress==0
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        get(gcf,'CurrentObject');7 ]& R$ W5 }  j7 {9 y' d

0 W: e* k4 T2 e* P3 c  G        c = ceil((rand) * 5);$ e) ^1 P2 |+ a
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        switch c1 F( {& E/ i/ n; L& y4 y; U
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            case 1
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                set(get(gcf,'CurrentObject'),'Color', 'r');1 j& ~' j& O7 R3 l; w4 x4 W
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            case 2
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                set(get(gcf,'CurrentObject'),'Color', 'g');
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0 N4 p  S* k5 n, `            case 3
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8 `6 w  ?. c& ?8 E% W                set(get(gcf,'CurrentObject'),'Color', 'b');
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4 Z2 o4 L7 Q6 f1 ?            case 4
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                set(get(gcf,'CurrentObject'),'Color', 'k');
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            case 5: G# k) d8 f- I: p. d

7 `, T0 z" u" b- R  Z  l                set(get(gcf,'CurrentObject'),'Color', 'y');  S% f$ l" r8 L, P6 v2 T. g# d

. X3 |- `+ J1 _        end
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