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请教一下：我需要实现：按下Key时，p0.6输入为0，输出enableP2.4=0,但实验室，按键输入没反映。为什么？？谢谢！' K$ n( Z' k% g5 }5 t: |9 i
. f0 S& ~/ ]$ s6 T! Z0 G+ c#define enable (1<<4) //p2.4 is enable motor.0X00000010/ ?: }) `/ l; M% i& f* S
#define key (1<<6) //p0.6 is connect key# F0 I# B( P' t+ {/ s+ h6 r( U" M
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int main (void) {
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# b4 I; y# j& \1 {7 F! F$ u2 |- Y int i;
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2 f9 Z( a- @& K- f PINSEL4 |=0x00000010; //set GPIO P2.4,(p2.2is PWM function)) \' m9 b+ E& V8 \! C
PINSEL0 |=0X00000000; //SET GPIO P0.6( U5 @9 c( H1 r
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FIO2DIR |=0x00000010; //pin p2.4 is an output. B0 C5 A, v2 G$ i
FIO0DIR =0; //PIN P0.6 IS INPUT
. v D8 b5 Z+ F# R z1 T, g if ((FIO0PIN & key)==0) FIO2CLR=enable; //set p2.4=0,motor stop,(when press key,p0.6=0)
/ ^" G8 Z5 N3 K" }" T else FIO2SET=enable; //set p2.4=1(when release key,p0.6=1)
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6 l1 E; }+ m q2 L! n pwm_init(); //initialize pwm* t2 J% u3 Z" C5 I& O
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PINSEL4 |= 0x10; //PWM outputs its signal at GPIO Port 2.2
4 J' j: y" V( G/ c5 [ pwm_setup(3, PWM_SINGLE);
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pwm_write(3,50);
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}
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发表于 2020-8-14 10:28
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淘帖
支持！
反对！