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MATLAB基础教程之实例原文件 部分

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x
. T: ^* K4 [* J3 h* o3 t
>> str=['MATLAB 2006a']
9 ^5 q! h) s) G5 d4 |! [6 N2 p$ u$ r
" s+ |9 O5 L1 D% U: k3 [( n+ P1 Y>> str
6 c3 g& ]8 a/ v$ f' Z, i' ^
% Y& \2 d& K% ]2 I2 l* W>> disp(str)) u& M1 j! j4 e3 ^/ W8 ~& i* U1 k7 i" _8 }
6 ?: l) Q. e5 r; O! j. P2 w& F
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
6 E$ ]& Q5 J  {- R
$ a. O8 A: X1 `- u( D! Q% q>> x=-2:0.2:2;$ @+ n( g$ z0 t' y2 V

" N) h# `  u! [8 J>> y=x.^2;
: P' l* W/ z& v" u9 X+ t3 I8 ]
+ {( A1 g* U2 v( N2 x>> plot(x,y)
* S7 X  B" ~) \7 ]  R$ j4 [3 A- c& c" @7 I  o6 V
>> str1 = num2str(min(x));! J/ X, y( [+ N. _+ S" d* }1 R
; ]7 q" u0 Y6 E$ g9 Z; _( h& a5 H
>> str2 = num2str(max(x));
% J2 x. z- m8 g4 Y$ ]7 M% Y  h8 f, }: O
>> out = ['Value of f from ' str1 ' to ' str2];3 |( G  i4 G  U# v* v  D

) z  e3 E$ q" L& a%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
8 l/ P9 B9 K. q0 w! |+ R
* u, I, ]1 ^/ [>> A(1,1) = {[1 4 3; 0 5 8; 7 2 9]};
7 O& N! F- Y' H6 J. W$ A' z9 g7 Q; F3 ?" [) q/ H6 J" h
>> A(1,2) = {'Anne Smith'};
7 v2 p; V$ L. y  q$ ]9 b0 w9 b8 M+ l8 P; a3 d
>> A(2,1) = {3+7i};0 L2 v2 u& s2 q0 H* ~( f
1 }, x3 g9 Q( @
>> A(2,2) = {-pi:pi/4:pi}2 e  _8 `# A4 b* g/ Q. m! n. B
5 h* x' w: G  @% R+ Y  i7 [/ C& h
>> B=cell(2,2)
8 L, Y% x8 d* X2 n( g6 w$ C8 x# D2 l0 ?8 x3 }
>> B(1,1)=A(1,1)
8 M5 `; h, D( f3 a! V# j  Z1 n' H>> celldisp(A)- q$ e9 \+ K5 {) v
>> A{1,1}# S; i7 m. K; Y4 |, `& U
>> cellplot(A); @# D" \8 ?- Y/ V, c/ i/ ^% u
% Q' \$ P, ^" o, f% w
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
& d- G  R( s1 s
4 H3 j0 W/ n7 e" T* A>> clear# w- n9 ^- _* Z
A=cell(3,3);
/ P0 W3 {% s, K* j& a/ w' Zfor i=1:3
: V- V6 N0 @* i3 H- Z    for j=1:3. P2 P& m. n0 W
        A{i,j}=randn(i,j);
( I* }! z5 `& r" w    end
0 Z0 }# q& i) h1 oend5 v: v; D  Q- B7 L
>> subplot(2,1,1)( ^( f2 }$ B( n0 b/ b$ e: X
>> cellplot(A)' [& P5 A  N8 D; Q9 A0 B
>> A(2)=[];% O/ r+ m. G% ~' n* Q0 B
>> subplot(2,1,2)5 @7 P* W3 V3 w: K
>> cellplot(A)
' l- o, g3 R+ g>> clear
- p& X7 K5 Y- @4 W0 [A=cell(3,3);
( S) q7 w9 R7 v7 Y9 tfor i=1:34 w3 k- w$ C  B+ U
    for j=1:3
/ J: L6 h& V5 ?        A{i,j}=randn(i,j);
6 h# m+ n. [5 [    end
. g3 Y4 C- l- ?+ T  qend( w, S! Q/ ?  L/ o
>> subplot(3,1,1)% p+ V* f7 r$ {% s( d
cellplot(A)4 O& V7 v! k7 B) R. F  c7 }
A(2)=[];# T) e9 n& u4 @1 U1 D5 L" m
subplot(3,1,2)
3 X2 `9 K8 u  L1 d4 C( B) `- ycellplot(A)9 `- s* R, h3 o; I# I& H
>> A(3:5)=[];; X2 V9 n+ @# ^1 Q
>> subplot(3,1,3)
- `) a& ]; w0 ?; l- c/ n; g  _cellplot(A)2 g! m& B6 f' h/ T! w  n8 R: I

5 f- X, n9 j# ?) L! q9 i
! @3 q0 p$ b$ ^& G9 p+ I%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%0 D6 m" `8 j/ J% Y5 z/ t7 U9 m

! }5 _4 T. }( V% k7 i4 Z. O% s>> person.name='liuhuiying';
* @+ j2 T! _& r+ g, `>> person.height=162;3 c7 x( q3 W8 V
>> person.weight=51;
) e+ f/ X7 p, E$ B( X4 a& R  P>> person.hobby='swimming';
3 w- \* A4 Y7 E, |) W3 P$ y8 o>> person: ^7 Q, M% F) ]0 V
: e" d8 v9 N  ?1 c9 b1 L
>> person(2).name='zhangqiang';
( G" _& \7 \5 p9 Y' o7 w7 x2 a>> person(2).height=175;
3 l7 h8 B9 T7 z* K. R: d( g  f0 m>> person(2).weight=65;0 h4 d/ Q0 F) h: x5 X
>> person(2).hobby='Game';
) u5 Y# `* [3 U3 R/ c' \>> person
' ]& _! X$ I3 O. K+ f# l" n. b5 R/ |0 i* ~1 }. i
>> person(1)
4 P5 ]# L5 {! E1 u0 v
( a% x3 p, Z2 L( K! K5 v>> person(2)# E4 g, ]7 E8 b4 ^9 i8 m

1 N2 n: H6 I" E, J  E7 _  h" [7 l' F5 A: Y1 vperson =; }, P1 R# D) }! @* d0 _% k6 U
$ f& X' E0 o5 ~7 R
      name: 'liuhuiying'
! W  s' q! s* [- B$ i# f1 q7 \; }    height: 162
+ |: X/ O/ P% z, F    weight: 51
  L7 m/ T1 |" A9 v* B( Z- r     hobby: 'swimming'
4 b5 P9 f" h, ?" b
# U; e* _- h4 J  D) [5 A
4 ?' D! B* F4 h0 B8 T; G7 jperson =1 w  n; R/ c6 b# H! M
: j/ t; k) l8 i* s+ K; ^5 h# D# ?
1x2 struct array with fields:
) `2 \! [* Z6 e( e) v    name
/ i6 x, V: N0 P2 @; i( t' B+ n% @/ i    height
- d3 l8 |: P1 h! Y4 K- ?* p9 v    weight
# `. T- n3 ^2 M2 q, u4 X5 J    hobby
. W8 m/ U+ O" n$ |7 A% v: {% D5 a- ]
* J. g; D: b: u) H' j$ P0 {) o+ L. B) Y; ]
ans =
* |) _1 n) ~& ?- O+ ?' R: v2 i. t! w
      name: 'liuhuiying'' \: @9 R0 H5 q" c6 W" t  d: z& K6 J* Y
    height: 162
4 d% \9 y' m- r! l# |+ g, v    weight: 51
- p7 f# v: w! \) z0 P: D0 [% n     hobby: 'swimming'7 W4 p4 Z: g9 t% L, X. I4 Q( W
# d8 S4 m3 H" M/ W
1 w' F( b' ]: b2 k
ans =
/ ]( T0 g) L' {- K5 j0 A
5 ^  _2 l+ y! r# ?3 H2 f5 |5 E      name: 'zhangqiang'1 U+ D) U9 Q" a% |  R
    height: 175
2 H2 l% d. F7 Y; @  l    weight: 65
) H5 t# V6 Z0 v) O9 _     hobby: 'Game'
  u' e; l( j: {1 L) ]- D  {0 U" ?* ]0 S' s! ~: `
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
, \( t* `; v4 V1 _  _; `5 {
" P4 @9 P# |. {0 k6 e; m" c6 u>> person=struct('name','liuhuiying','height',162,'weight',51,'hobby','swimming')
8 M+ O7 o! j3 u! q' \5 ?5 c% b! |6 e2 M; E$ I' Z
person =
# O+ E' Y8 A: G% }2 m$ U3 t$ m- E" f* `4 Z, b  H; }1 Y& `
      name: 'liuhuiying'- _1 P& @, R$ n# M/ t
    height: 162
; |0 p( ^4 [, r+ v- J    weight: 51( z+ M6 i2 E4 X
     hobby: 'swimming'
1 c9 W9 o3 Z, l0 x! }9 O" Y8 [2 H) B* b- y
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%& T; d6 c- W, S& N$ ^8 ]

5 N) m* A0 V8 y$ e2 `7 C>> person=struct('name',{'liuhuiying','zhangqiang'},'height',{162,175},'weight',{51,65},'hobby',{'swimming','Game'}). }1 \3 u2 ~+ ^) z

. E3 b! J: X  o& J>> person(1)$ Y( e9 \. z. s# g
' G" ?& N9 t, X. D  \. g3 N+ n
>> person(2)
* @1 c7 u3 X5 l; @# L. X
. _# g- G# S3 Y. [ 6 G9 {; P% ^$ d9 R3 h
* ?* m4 N1 C* n+ r
/ h3 x" X: h) Y9 A
person =' x8 A: m4 u9 S( s) q- {- y% Y

2 b7 z; r/ Z3 x  u( S1x2 struct array with fields:% B* b2 v7 q! [
    name
& x2 f; |( R" W+ L- F    height
, _- j( ]9 j: K7 u    weight
$ I/ {, S! R; d" v+ p    hobby
( s4 |1 p; v/ q0 I( m
% P3 X0 k3 C* @" B6 J) K* i
6 p$ ]  R* Y3 u6 U- S: E5 J; Cans =$ {; k' i! Q$ `! U" z4 w

6 R- ?, U9 y7 P! m. \, Z      name: 'liuhuiying'
9 G1 H8 g3 B. t% {    height: 162* L2 J2 S2 P* U- l; M( y2 |
    weight: 51; m: T% M1 }1 _) w- o3 r/ }- ^5 Y
     hobby: 'swimming'8 S& ^6 E! b$ Y5 w5 w% Z

: S* N+ Z+ {+ B9 T
( b1 {" v8 X- M* Q8 fans =8 P$ }( O6 i6 n+ s$ s; T# s
8 N( I6 r  P6 {8 p$ i& r8 c1 N
      name: 'zhangqiang'
: [0 [& e& c9 M" G" D" Q  N* d    height: 175
0 z6 D+ K8 [; k" A5 C  _    weight: 65) z+ M0 b9 b: q, g
     hobby: 'Game') F- r! C+ U+ B& y& C
0 d. d0 ?& L0 E/ d7 X' K$ a! g
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
9 l  B- ?' p9 V0 Y5 h6 g; G" v
( j' B% f; r. X) l>> person(1).gender='female
% s# S0 P4 e8 x9 P( q* S5 n  P3 h5 {! u" ~% B# b$ ?& y
>>person(1)
. [. ~: }& R* R2 X0 g# D
2 w2 R( p; }" @8 R1 U$ D; `>>person(2)1 F' `. p0 @, A, @

7 p$ J0 E, N* |+ C0 W' B) N2 yperson =( l0 w1 c$ N0 F, J
' L1 w. d# a& w4 Q
1x2 struct array with fields:3 `% S0 q% }2 f2 T# d
    name3 |/ V& L2 s0 c$ Z' z
    height6 i8 r6 u# W- _% K) X' T9 t
    weight
. h( f3 M! }" y* `; B4 W' `6 X$ Z; A3 d    hobby9 p) j: u9 B! t) Z' T
    gender
' C: f2 T9 x% b6 K7 Q* u. Y
4 ~0 ~$ f7 X4 h% D$ S
- W; u9 ~3 k7 h/ S8 s! Eans =
% `# [% \# q4 P4 |9 D& O
! U) I: U$ S* R, @8 Q7 C      name: 'liuhuiying'
9 H, y' O1 u7 G+ t$ E# y6 B3 v    height: 162) v) Z- M9 Y1 o1 B( a* N7 _
    weight: 51
& }% J. x( {2 ]0 R( c1 Z# P     hobby: 'swimming'4 Q- I8 ?+ Q5 \% V1 T: U( C
    gender: 'female'
8 A; E" d/ ]6 j! c2 k. M3 p1 I# x

7 b7 b+ R$ d+ ^1 P2 aans =
& V' J: h. g. H0 W; w$ i4 ^2 u; e, ~0 g' B( a2 n7 L
      name: 'zhangqiang'
) @' B) a( f4 l7 e4 r% J- |) c/ t    height: 175- b2 T: H. z: p& F  A0 p& P. G- ]
    weight: 654 v$ `/ v/ B! F
     hobby: 'Game'
4 ^2 ^5 K  K. d) P  o( G0 ?, m    gender: []7 k* x" e4 y# j( c$ P* |) n0 E% G, k
3 i, |6 V- N" ~  u; ]1 q5 Y
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%/ j3 {; M9 j3 G

1 K+ _- s& Y8 z>> person=rmfield(person,'hobby')
2 q$ P* W) _( ?, f7 Z0 D5 k: P; x# n1 I  Z4 H
>> person(1)' c& g5 m9 D& T! v& I6 D+ j, y

* x$ y  @3 D1 u' s! [>> person(2), i8 z3 ^( L+ d$ L! Q$ q$ o; D

* m* k/ V3 K: k: ^
% i* a" ?1 D" x7 r& }. Y
) J* \6 z7 I* bperson =
3 @. P: m4 x8 w. x
1 j; h7 R* h9 e4 h( r1x2 struct array with fields:) q5 `! X  U! U. _( s5 }9 R, x
    name, |( s% e8 h) A2 E9 {
    height9 C* p3 ^* o$ S) O
    weight
: Q, h9 `6 P! F" ]! H) s& \, Z    gender2 r2 v' e- ?' ?6 c1 S

; \0 P$ j% B4 x( I0 k
( R2 J- E! J4 k# X2 ]/ c4 Lans =
! Z0 e* W3 P7 q/ ^! C& w
: I4 h$ P, a* C2 r; a  ~6 b$ W      name: 'liuhuiying'
7 w6 _1 X. ?3 Z( F    height: 162
1 M: `- [& V! {6 ]( {3 I  ~5 S    weight: 51! U' J2 o( q& ]1 y
    gender: 'female'% t8 u$ D' R/ |3 B& o0 P$ M8 u

8 H2 {1 B7 d  D; C8 |  l6 |% J7 B, G# J7 Z) [# G
ans =
; S% e, `( ]' ?8 w* H& r8 Z) _$ K/ S, Y. B; r  b
      name: 'zhangqiang'
6 v7 q* ]7 i. }: v    height: 175
8 D/ Y* V1 X7 j1 q& d: p1 w+ {    weight: 65, p$ K) h, Z- A; E6 U' o, t8 Q
    gender: []# U$ n5 l- V" I

6 y* o* |! R- D& A& a- j
7 U. d# D" D1 o, G6 p6 D4 q. V: L+ y' d/ L& E* T% P) ]! a8 w: }
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5. z! |/ [# i+ \

* F8 D# t1 w3 q4 N6 s, v>> person(2).gender8 x6 G, v- M# B% ]4 ^. z

/ Z  n1 Z) w" M8 A6 I8 Y; D>> person(2).gender='male';0 d9 `! q* n& f) w6 p

+ _3 P% v' R1 N! r1 r  n2 F# O! p>> person(2)
0 G# E9 C0 Q1 e  E3 X9 X; B/ ]7 Z6 `) `0 p! R- j; j

* K$ m% S  x  k# R) s& _
% O  m( l1 ]1 Cans =
) d/ D. [& |  f# b( U3 H
! Y/ |% s& b5 S     []
9 B& l% q; m* A% G
7 D- E) U8 x6 F& F0 C1 B! Q$ l4 J6 e6 K
" j8 d6 }) m" v% vans =
' q+ A' E, {2 q$ i" a1 x- H) B3 C; R% D' S! A' ^( c- v2 B
      name: 'zhangqiang'9 ^& u- ]; ~$ Y- o$ x: {
    height: 175
2 N0 N7 E$ J: R' c$ g5 D3 h# J    weight: 655 a% K. X  Y$ {. n* P
    gender: 'male'& Z' E5 \4 ]3 ?
6 @; X1 a5 F4 q% N

# q5 X/ E1 \: U  }! {9 {% ^1 |- l) i  d5 W8 R1 a
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
; F/ A+ ]/ g/ n* S2 B2 _7 K- }( f* r  j9 ^
>> A=[10 20 30 40 50]7 O$ ?( _: U4 Z0 \# u
2 A5 Z  r9 m& I0 F
>> B=[10;20;30;40;50]7 p. A3 d5 p- I7 _
5 Y6 A) }; B/ h9 b# O5 p: \
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%52 C7 u$ f( O  B, n. h0 }$ f+ \) v. l. p

3 N' c+ W* u3 y( _& N6 T>> A=1:2:82 E$ W/ Y6 M) E6 u! `( t

% G# E1 n; }0 R( Q8 K) w! |>> A=linspace(0,12,4)
5 h$ m6 V$ h6 t" j, x3 n& H+ X1 e# E( x. [; u
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5) P- w- @2 u7 I' Q3 w3 s
9 [, h7 m/ D1 \6 s. }# c) q: t
>> find((A>8)&(A<14))       %找出矩阵A中大于8并小于14的元素的单下标索引
6 E& t; y' d; q. v1 M4 A
2 x; P6 T- z! ?! h7 ^, A>> A(find((A>8)&(A<14)))    %找出矩阵A中大于8并小于14的元素
) x3 [0 ^, Q5 J; D0 |
$ R9 }  j; N! \( q%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
$ t! F$ n( p6 h/ ~3 i( {4 O  z4 Z% A+ w5 x. P+ p3 s
>> A([1,3,6,8])1 o6 ]) f# {( f" A

# E' ]2 v1 j$ k; L+ a% g4 ?%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
2 L. Q. ^: o( j  {$ J8 S3 t+ p( \
4 f: w% j/ Y" ~0 l- v- L% e>> A=rand(3,3)" J6 I) @+ ?1 `

  _! p+ j% V! N0 r>> A(:,:,2)=randn(3,3)
% |+ o2 D7 n9 H4 K$ Z$ u/ L" F7 x% r! L9 y' A
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
% \1 E% W; K- i3 b" r0 q5 R- [4 n+ O2 P' Z: V! n( Z
>> A = rand(5);
6 g3 Z7 s" M1 y! d$ q
! l0 L5 c9 R' S$ n>> B = A > 0.5;3 {* `+ P) ]7 N

( \  i: F+ u9 y- @' V6 o: _- c>> A(B) = 07 `0 Q, {& ?0 Z& `# y. o

; v9 w' \6 t; u, U6 o/ ~/ B ' d# l: A, Y* M3 a  T! a9 o

& h" p% }9 X* }0 I/ ?A =+ L: K7 S4 z( @& `

# ^9 l8 |0 ^2 ], q! \    0.1450    0.4018    0.2400    0.4909    0.1112+ Y/ R* k2 Z) ^  b; m
         0    0.0760    0.4173    0.4893         0  V* f- ^" v+ j# F; m
         0    0.2399    0.0497    0.3377    0.3897
6 f7 G1 X5 K7 F7 X    0.3510    0.1233         0         0    0.2417% n1 d8 i% g3 C$ i: J) s
         0    0.1839         0    0.3692    0.4039
/ b- g1 K3 {& ]( c
6 _6 q2 |' g' Z8 j%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5" b3 U. e5 A4 v; \

! ^3 {& t3 ^$ Z, ^+ U* r  _* ^2 N >> A = magic(4)1 J) n& o, p  M. T% k& H
" J8 X. h9 T+ T4 |
>> B = isprime(A)
" _6 |; N9 f4 f) m/ o6 ?2 g
3 ]9 ~! X( |, w* X! t>> A(~B) = 09 L5 z3 r1 l- U/ J( q9 o

) ^* g8 l% L% Y: G
/ p, j+ J% G% M) I
6 ^4 ]* {+ @! H%%%%%%%%A =4 I) N% Q6 u+ e# s( h2 _5 b
' w5 K. g/ D, L5 P3 T5 P  ^
    16     2     3    13+ I5 u6 Z# K$ s5 S' v
     5    11    10     8
* ^7 A' s: I" y% G& `2 R. Q! a     9     7     6    12* H* |: S' b, `$ ^6 e
     4    14    15     1
. L' \, Z7 E  n- W7 r& N; g0 ^* V! @2 r

: N* u$ Z- r; Y4 `B =4 ?8 j' M; d, v5 m& |6 P
! M9 T/ B. ~* ]4 C6 g
     0     1     1     1
' }* a" p" F$ c5 D     1     1     0     0
# O0 ^* {$ j0 F' I. G3 |     0     1     0     0
1 @- F6 H6 C; s4 e     0     0     0     0
/ y& d/ q  q3 C$ n2 A3 ]1 Q8 l( U3 F+ F7 S4 X8 D

' E- g" }) }2 ?. s( v% W, F3 tA =5 s* f4 N$ }3 U$ e& t; M$ Z( Q
$ a9 _: N1 [$ z- p. O, M9 h
     0     2     3    13' a; u  |: o" y! a4 V, N# w9 W
     5    11     0     02 {& k9 ^5 T' D, }& {% h2 a
     0     7     0     05 G- C, k1 C0 e* X. _
     0     0     0     02 {7 c2 [% A2 n: _

! L7 d. ?6 g" O2 M- D( J%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%58 }- r6 G) I, _

. }4 a% j; F5 T1 B0 j" P >> r=[1 3 5];; P  y; \" b- J/ M
/ _1 |) K% x+ m- M3 j& J2 W! B
>> p=poly(r)6 X9 F' ?! l$ z0 |; y: z. G* ?

  N; ?. F+ Z! |* G, A6 q1 c, X0 L* U' P>> poly2sym(p)
3 h$ D" L; C, v" O4 `7 G0 \8 x8 {8 e' L+ |4 `
>> roots(p)8 F( W( X$ D9 ], y6 ?
1 q' g' X; w  E# i
p =
+ d; Q/ R) |5 N. ^2 a1 R* X' p' e/ @( O' ~& V5 d! y& X/ N3 X, @
     1    -9    23   -15' ~6 k- K' K9 I1 ]
* X0 `$ A* s& t3 u

, x' A5 \0 _' @ans =( g8 h. b3 O6 H6 d

: K2 V; V1 D& A+ ]4 r3 {- Sx^3 - 9*x^2 + 23*x - 15# Q2 R4 P5 a. u8 G4 N0 O5 s
& ?( a! j3 X! {! u" E

5 W. [; Q& P+ i. K" x3 }ans =* U6 D  l$ B& F

0 b) _" i$ \" w) o. c    5.0000
8 D* S. S3 Z; V" x5 b    3.0000, Z6 Y; ?2 {3 z+ B/ Q
    1.0000) d8 ?  }9 {( w+ ~6 i* Z
! g! {6 n/ U/ e1 X4 J/ H3 |
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
3 @5 U* A8 _6 I* ?4 a3 l
4 g/ i- M2 I0 ?4 F/ D5 \>> p=[4 3 2 1];
/ J! ^; v1 X% Q8 |" T# ~5 H; u# c3 h: X+ p/ Y6 k4 V$ j
>> polyval(p,4)
# L0 @* H; X9 k7 P
. \6 F& N" r  Q( h' @7 P>> 4*4^3+3*4^2+2*4+1
) N) p) W+ R0 E. _' Y/ |; ?- ?$ W
' D( o5 T1 w! `$ b
ans =# l" T0 a/ b5 c9 h4 K0 h8 y
- ^, s' \0 K6 |' r" V, H
   313+ O& S" K7 y) l3 A+ ]3 G2 h! E. k

. v  O7 k$ O5 i6 T% a# p4 D8 [6 T- ?
ans =0 a4 S% C$ Q+ R9 d$ |) i/ N7 f

% B- X% \) ^7 s: g: K   313
$ q0 m( p! j3 L+ S7 P" h* i9 v) e) ^8 K3 x% z
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
% d# _+ l6 ?* ~: d! b" {2 c' Q! X* i$ s0 U+ W
% fit sine between 0 and 2*pi using 3 order polyn0mial4 T( I' v! e$ _* W
x = 0:pi/10:2*pi;
; C& ?* ~/ d& z' ]# Qy = sin(x);
; z# J# N" Q, Tp = polyfit(x,y,3);
! h  Y, L6 q; n1 q% @0 N/ k1 w2 `; `plot(x,y,'r*');, z1 Q, }4 _) s6 P, Q  w
hold on3 c( p8 p- q# q& M, I: N3 H6 d2 |0 q
f = poly2sym(p);
, A# O+ c: i9 v6 I3 \+ I8 y6 sezplot(f,[0,2*pi]);
* D  S7 W; K' D& ~
  b, ]9 Y- V' D3 W! p1 {>> p8 S8 n. Q4 q2 ~" v! l' ?* Y" z1 C
! C  Q; N. d6 b% ?9 d0 @
& t7 x6 W5 {& k' \. i( D3 O
. |1 g! Q9 O! P: D% F* g. a
1 n3 o+ [: C4 E* z
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
0 v8 `% l6 p! h$ I8 _4 \4 ^0 f
" `& E9 X/ Z) y8 E% Interpolation using the four methods0 h/ {6 `( r) k1 N: j$ X
x=[0 3 5 7 9 11 12 13 14 15];
9 U9 b: w9 g( h$ O% h7 _4 Hy=[0 1.2 1.7 2.0 2.1 2.0 1.8 1.2 1.4 1.6];- |, }$ J8 u- D6 H2 _. h2 b3 M
length_of_x=length(x);2 f! Z4 v0 ~* ?1 _: L* z
scalar_x=[x(1):0.5:x(length_of_x)];
8 z2 s: Z  a, B5 J1 |0 Slength_of_sx=length(scalar_x);- l8 r! I9 |1 P  ]0 ]& Q* ~
for i=1:length_of_sx# n' a- u: J' A+ t
    y_nearest(i)=interp1(x,y,scalar_x(i),'nearest');' n. Z8 h) d# a" i8 d" u
    y_linear(i) =interp1(x,y,scalar_x(i),'linear');
% M1 @) }$ }1 s    y_spline(i) =interp1(x,y,scalar_x(i),'spline');  {0 K4 y$ m7 \: i9 X" x5 x4 [
    y_cubic(i)  =interp1(x,y,scalar_x(i),'cubic');+ n: J+ n- j) }. T
end
1 v# p7 a: l+ R; p0 b- S- F& psubplot(2,2,1),plot(x,y,'*'),hold on,plot(scalar_x,y_nearest),title('method=nearest');8 b* m& ^+ I3 N
subplot(2,2,2),plot(x,y,'*'),hold on,plot(scalar_x,y_linear),title('method=linear');. |) l5 U% H% z; t$ ~* A
subplot(2,2,3),plot(x,y,'*'),hold on,plot(scalar_x,y_spline),title('method=spline');1 w7 G$ K( e9 D  ?3 T
subplot(2,2,4),plot(x,y,'*'),hold on,plot(scalar_x,y_cubic),title('method=cubic');
1 ?0 {+ F0 T8 _# L& a, f/ U& c
# Q& a, I9 R! p
1 p9 Y! x# u5 G4 E% V& H  W$ r" p* C* L8 e6 g! o. ]
/ z: G  _4 x5 }1 S
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
( K& N# r4 u; H7 K; C, J8 _& ~2 M$ \
>> fh = @(x,y)y*sin(x)+x*cos(y);
: t# a2 T+ c5 P4 Q6 O+ _1 I
: g7 N+ |/ O5 c>> fh(pi,2*pi)
9 S  x" H7 @/ i- ]
" K- p) l' T: {2 X) v+ ^%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%52 U" v/ f6 l1 K4 }
6 w& ^0 k  N" C  R! f. E1 x
fh = @humps;
0 [: f  G) q7 C8 }1 }2 z# n/ l; r! S
/ Z, y, c; u, }. G# u- I1 _4 |& Psubplot(1,2,1),fplot(fh,[-3,3]);
# [; C. ^- ]0 Y' O
6 w1 \  h, a5 Vsubplot(1,2,2),fplot(fh,[-3,3,-10,30]);
3 @1 a3 E' y# G3 ?" _
. O7 Q' R7 V! U( B%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%59 a8 i/ \  F' S/ I0 y) _9 `* X" V
( _0 H/ D9 k) T# H* ^
) ]9 G, P. R5 _- a7 j
' X' U/ B* N$ m
% find the minimum of the function f(x)=x^3+a*x^2+b*x+c+ W+ D  @. n- w& ]8 I
function [x0,y] = funmin(a,b,c,x1,x2)
- b9 g& W% E6 [# n- `# a* Ioptions = optimset('Display','off');
/ B7 @" `2 K! W$ e* P% O" q[x0,y] = fminbnd(@poly3,x1,x2,options);
) {. ^  b, s" L  ^4 I6 ~: Y    function y=poly3(x)        %the nested function  b+ K8 {* b/ C- V- x/ z/ n6 `$ N+ T
        y=x^3+a*x^2+b*x+c;
' M6 M; H$ ]# i+ s' J, D    end$ h% ]* j1 e2 O: Y
% plot the function1 }# b# ]' [% `
fplot(@poly3,[x1,x2]);! W: o: }: w$ l2 m9 j. Q
hold on;* `- S8 v/ i7 n! |7 K
plot(x0,y,'.');! t* c' Q0 G# y5 A
end
1 d( b2 E! p, ^: l6 F$ w9 f# ~9 c2 `
>> [x,y]=funmin(-1000,10,0,600,800), u2 O  q( s) H$ J! w  t# n
- ^9 f% d  \. ]" a3 `( s

, m* V$ M9 U( L* I; L" q; L: G+ m& u* _/ A
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%' f; R3 W+ F# c/ f( ?+ R
7 j3 ]5 ~7 t8 _$ m$ n
>> F = @(x,y)y*sin(x)+x*cos(y);8 {" j$ j  ^) B7 t
# `0 n+ T/ W& ?3 B0 ^# q8 Y3 {
>> Q = dblquad(F,pi,2*pi,0,pi), _1 f" `- d+ b% u* R# w3 v
: K9 {) q) _  K$ ]- i1 X! z& \) r
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
  q) ~% E1 O: C$ N' ~* R
- |( B; C. {: E% m% V; y>> h_g=@(x,sigma2)exp(-x^2./(2.*(1:sigma2)))./sqrt(2*pi.*(1:sigma2));
+ y( g: I7 g4 ~7 o( d- h6 u/ G: s( x  M' P$ C6 y, e
>> quadv(@(x)h_g(x,3),0,2)4 @* ^% Q/ B! O
/ ?% |  N  [& S/ {3 ]3 G" ?! P
ans =
& d+ G; Z; l( J- |8 n3 S$ J, H9 L! d7 |+ |
    0.4772    0.4214    0.37590 I1 Z* {& ]8 _

/ f3 [5 O; ?' X" K>> quadv(@(x)h_g(x,2),0,2)
' O9 v2 m( F/ r9 u/ u% ]0 ~/ [6 ]* _6 y3 A. z5 m/ K
ans =
  I! O  E9 ^6 _) \0 q  ~
8 K) V8 O/ I  Q) e6 J# @  d6 c    0.4772    0.4214: L: G* P5 x$ t% i6 O# s" D5 B

* Z8 v' X9 M7 T$ P>> quadv(@(x)h_g(x,1),0,2)
, {1 M, d2 ?2 {/ z9 f8 _  k" V# \' ], k
ans =
  h. _) I$ d% R7 v- W) O4 ?  D  {4 T/ z
    0.4772# d2 \: O4 S4 G% G) S, O

. W" \1 }0 q0 s% N8 D%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%6 u& T/ Q: ]9 y  u1 X0 ^# N$ i$ E! W
* J: {& {* c. a; q
% the file to creat a function with parameters
% T& o% W6 R4 H0 _7 tfunction y = poly3_fun(x,a,b,c)
# S7 g7 O- B0 y! z3 D0 ky = x^3+a*x^2+b*x+c;7 B5 ~) t! ]9 c7 o" t" i+ i7 n8 b2 n
8 `# ^! O) v- V9 V% Y
. A0 F/ A0 G- k0 S3 z
% find the minimum of the function f(x)=x^3+a*x^2+b*x+c
0 e' a$ H, S8 O) l% S5 wfunction [x0,y] = funmin_para(a,b,c,x1,x2)
9 r2 y1 @/ s$ L7 C  boptions = optimset('Display','off');
+ {% R- \2 J9 J, C* s[x0,y] = fminbnd(@(x)poly3_fun(x,a,b,c),x1,x2,options);
. a3 t) y! ^) m' w3 I. e% plot the function
3 Q1 H* g# d- V8 D: F# t8 rend
" o8 I3 D; {2 B: ^- K
% p& l3 k# t) \- E# p; V, B% Q# k
>> [x,y]=funmin_para(-1000,10,0,600,800)( F8 d6 f$ t0 N3 l8 V- N

, \* {, l, K! E4 H/ L
0 B+ `! ]7 N7 L) R6 c1 [
2 e0 y( c- r0 K$ r9 w/ E/ o%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%  U$ o6 f8 h' A. j' U

, A$ j6 d  a" k# R: ^( ?. @) \! @
9 f% X) n, K+ n- B" n
9 U$ |3 C. k" g% v" j% polynomial operation
. [- f) R7 z1 Sp1=[1 2 1];                         %定义多项式! p. r  t0 F& E4 u
p2=[1 1];
* a6 z) m+ J; m5 t% r+ Olength_of_p1=length(p1);
- r, P2 k6 z: ~1 f5 j/ x' }length_of_p2=length(p2);
# h8 Q( W3 o4 z/ v/ n# mif length_of_p1 == length_of_p2     %判断两个多项式长度是否相等
& K/ [3 W) m" T) Y( C- _    p1_plus_p2 =p1+p2;              %多项式相加- i/ r* G1 R" X; E: b* w+ V$ D
    p1_minus_p2=p1-p2;              %多项式相减
/ T4 [+ j+ }( S* `9 C1 S, `8 yelseif length_of_p1 < length_of_p2
& k: z" g- J; d/ ?2 h$ V        temp_p1=[zeros(length_of_p2-length_of_p1) p1];
6 \. E5 B- U0 G8 v6 \& H7 g        p1_plus_p2 =temp_p1+p2;" e2 L2 f0 k* x- f
        p1_minus_p2=temp_p1-p2;4 B: P% I2 w- _6 i& \! d) Y
else
9 R  c8 F: _9 b$ Z    temp_p2=[zeros(length_of_p1-length_of_p2) p2];
7 Y; v6 G7 N2 }# [8 Y$ a    p1_plus_p2 =p1+temp_p2;( d4 W4 b+ F! G/ k# u% T" M- x
    p1_minus_p2=p1-temp_p2;
2 u4 V( |# n) U/ F" U" B; m4 ?% t1 uend
. Z: A% o; W% b. J+ I$ x$ o. zp1_multiply_p2=conv(p1,p2);         %多项式相乘1 @- q& A1 j( d" r
p1_divide_p2  =deconv(p1,p2);       %多项式除法: \- e( f& D( `4 e4 E: j, I
p1=poly2sym(p1)                     %显示多项式 p1
2 O+ ~" |/ i* o% |. f2 S2 ep1=poly2sym(p2)                     %显示多项式 p2/ v9 ~( w# \8 E0 j; _
p1_plus_p2 =poly2sym(p1_plus_p2)
1 J" v. e4 r, y4 E, U( i2 ]p1_minus_p2=poly2sym(p1_minus_p2)
4 v& ]8 l2 J* R" P" Zp1_multiply_p2=poly2sym(p1_multiply_p2)& o* w6 M5 X2 Q1 c+ w0 K( h2 Z
p1_divide_p2  =poly2sym(p1_divide_p2)1 E# V) g5 [' s. L) z) n

. c4 u4 R3 g6 W$ d  s& v) Z   i% d, G! d* c1 l# z6 V# l
9 _' @  x$ B( A: M
4 \* ~& C" x( r* S( t9 f5 A! u1 R9 t

1 a2 W" h0 n3 G9 F " V3 Z& v3 e0 M$ p2 ~0 @4 Y" U
6 t. G0 ~7 A) W: d  e9 a
p1 =* {# J1 o* |) }* c4 e0 |9 ^

0 i. o- f$ {3 }. {: ox^2 + 2*x + 1
3 `4 o1 ]6 e  f' t& M6 |5 F
% g& E2 U/ @7 f6 P$ v
# W8 [& W# O0 c8 |9 B: W) Pp1 =
: v% W9 q8 M0 _9 k! [
$ Y6 p& w1 S0 @8 ^x + 1
' U, Y3 I# N  S+ g/ b8 ?% R3 Q
4 i1 W+ n4 f6 N0 p" N* }! M 0 y) f" E/ Q. ?4 k
p1_plus_p2 =1 {' n& b; ]: c0 p% f4 j& }
) Z  J. \9 b& @0 b' M
x^2 + 3*x + 2) P9 _4 t0 b. Y5 S/ y

; K  K* ]4 f/ }- L* N1 j) E
: {. Q( {3 M* B$ op1_minus_p2 =
( f- G4 M. A5 N
9 l' \8 }1 ]9 n2 ~x^2 + x% S; P( m! K. {7 `% a

0 g+ _# D! M! G# O8 ~: r1 u 2 y9 D2 \' e! X& N
p1_multiply_p2 =
; B! [. K% B2 S( m6 b; S
( G5 U0 s* Y1 W2 F' Sx^3 + 3*x^2 + 3*x + 1
+ M0 f" J8 F$ g * @- t9 k$ I: Y, h- z- a
  }* p  l7 s$ V1 I8 c4 I% s/ p
p1_divide_p2 =2 f% u5 f! i2 _* y

% j' {2 n- r$ d/ }: Zx + 1- E+ _$ w5 j) b5 j( g$ ~
( e( Y: e/ H: S, }
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
, ^- a6 ^" N* _4 [' G$ w
  [+ y7 j! @9 a% i) G& L5 n* ~3 O7 z
% C' e! K* O$ m, m
* L- W& \9 ?, {# D4 R: b2.编写一个脚本,判断输入字符串中每个单词的首字母是否为大写,若不是则将其修改为大写,其他字母为小写
8 T7 |2 s% P& n' \
0 ]7 W, X- Q3 `4 T% L6 k参考答案:( x" o) v1 P: \- G# j- c- e! @

9 V: [# ~' W, z- X脚本文件内容为:
9 a+ [1 P+ L0 }3 Q& Z# E
- o; C, l9 }& g% S& t6 lstr = 'this is the string to be converted';
0 N) y. Z# k  X
0 ^; |8 X5 V! T3 @nlength = length(str);- o0 Y. |- w! p
1 i2 Z' l- m0 t$ R' B% P
for k=1:nlength2 u  ?3 s2 w% U* e* Z

* t+ U" }2 K0 X7 O1 D    if (k==1 || isspace(str(k-1))) && (str(k)<='z' && str(k)>='a')& p  c% Q3 F+ T9 `' }% _1 N2 q; I5 S
) e0 v) d' x* P- p7 c
        str(k) = char(double(str(k)) - 32);
. D' T# U0 i8 X, ?
# O# K4 ?- S$ |; f. S' x    end% Z. H. D# k" ]( m2 N

9 ^6 U+ k* u# G9 R' x+ }/ `end
9 K' n! j9 p* ~* I2 _4 @
) n( R; e& T2 xdisp(str);
1 J- W4 M! I& L. _  V$ [6 ]: F/ x
# v7 ^" o& g1 _% P- E% | ( Q# A" n$ j( Q' U2 i+ B
1 L9 B6 @  B: v% u0 U$ G
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%8 o. b' \3 a: N2 v+ V
; m0 H) J; C- D, R
4.创建一个结构体,用于统计学生的情况,包括学生的姓名、学号、各科成绩等。然后使用该结构体对一个班级的学生成绩进行管理,如计算总分、平均分、排列名次等。. u0 p% E' Y  h) S

- W0 b8 K* f* i) X3 k3 ?4 A6 [. \- j参考答案:. y8 V& Q3 m/ O, ^9 C
, g( A* V/ E* \1 G5 @% _
>> structtest=struct('name',{},'number',{},'scores',{})
0 T0 h$ J# P1 @, c8 Y6 q0 W' _$ A: e2 L' e

# a' n  l' @7 Q8 U2 C, D+ I
4 p& ?& \9 n1 U# N; l( M. J  R+ q- @%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%. E& P- y" G  j2 O
, l3 @' q7 q8 M& N
1.创建符号表达式
' W! ]7 y" n4 b! U5 X$ H1 w7 z/ h5 q$ K$ Z: J) b
参考答案:
3 D+ I, X& d1 x* c& V
" l7 R8 L, X  P$ X) g>> f = sym('sin(x)+x');; x" n9 z  @9 T
8 k) r8 T1 G* }6 a
2.计算习题 1 中表达式在 、 、 处的值9 w- e$ F* p( _/ ?" {" C9 ^6 E

8 O$ f) I  E" b1 F& [. {>> subs(f,x,0)
% u% b! N: X6 J# \4 F. B; q
. ~0 _* P. a. P- u4 s+ pans =
& y2 R$ L6 J7 A7 i* x: M% T+ R$ R! u& D+ v' f# u
     05 Z0 f  _8 K  J* z+ [- L
; C1 d! |$ O" O; P: w0 t. g
>> subs(f,x,pi/4)
* f) Q0 _  c, v0 ?" @- U4 j
0 v0 c! ]; ~/ i6 M0 l; {ans =# h) {. d3 o. k0 \5 o

) N7 a+ p  a$ f8 x7 D    1.4925, B! g$ g" ?& C- G
6 w3 ?4 K( F: d6 t7 Q

( k8 v0 x1 _' `; H* f  i% o( f+ M& L  k' X5 K1 M
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%' z" Z7 o5 o- o
7 Z  C( `5 x0 r
xth = 0;* ^2 a+ k7 ]: {3 m7 R1 ~$ v
tic, [0 z) H7 L) r# ^
for x = -10:0.5:10
4 U/ D, N( [0 [" ?* @' A    xth = xth + 1;
, c6 L3 v& h' X. O" {1 K    if x <0$ e; L: ]% I; \9 \* M5 a" n& ^
        y(xth) = -x^3 + 5;
# i3 d3 ~- {) k! \4 M+ }    else5 w' o& G5 x% N! E
        y(xth) = x^3 + 5;! x/ G0 U1 x" F
    end
  l  y9 s6 _+ f) Nend
( K) b- j* c" ]+ x4 Ktoc
6 u" i/ g5 ]& l) a9 Z  V
  Y& f3 `3 r0 Z& s' b2 X%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
, X. N: k! }5 H1 Q1 N# H: s  l! ?$ z  n( F. k3 G% J$ u
tic
9 \0 C) t5 z1 r- T) wx = -10:0.5:10;( F: p6 d; J. j8 Y5 A! p* X
y = zeros(1,length(x));. p8 U% a) H& X: L& A
x0 = find(x>0,1,'first');4 N( l8 m" q! E# d+ d0 M
y(1:x0-1) = -x(1:x0-1).^3 + 5;/ f. P& F  C: W& L% K
y(x0:end) = x(x0:end).^3 + 5;+ Y* @. w( ]- b  |
toc% V! }& ]( d) R% d. B; w
* o1 I0 B! \7 h3 z$ E$ g4 Q
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%$ ~3 ^+ ?8 J3 A. [( p
0 n" q' z( I9 |+ z1 Y
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6 N* b- z8 z6 d: y* K# @; ~: ~# m
1. 在同一窗口中绘制函数在 之间的正弦曲线和余弦曲线,步长为 ,线宽为 4 个象素,正弦曲线设置为蓝色实线,余弦曲线颜色设置为红色虚线,两条曲线交点处,用红色星号标记
6 l" d; E1 {. X" |2 S* A
0 x% v. n$ e$ S- q参考答案:6 i9 y: I6 ?( u' {

4 z9 }+ {8 ]. n# D>> x=0:pi/10:2*pi;
8 ^7 S7 \3 m0 l% T8 J3 o! ^
: X( \' d* L- Q1 M# d>> sinx = sin(x);0 l7 N1 E" e2 l& x8 j9 ^4 N
4 p, h( u% d) d
>> cosx = cos(x);  X, _) Q8 g' ^0 c

: v* Q9 [7 G6 t& e0 U>> figure,plot(x,sinx,'LineWidth',4)$ `4 R8 V0 k% }; V& B7 G0 {* ]

" H  G/ ]0 K  }) v0 k7 Q>> hold on,plot(x,cosx,'r:','LineWidth',4); d  {9 l0 l, C' @
1 G! w- h. v7 e& G
>> hold on,plot(x(find(cosx==sinx)),cosx(find(cosx==sinx)),'r*','LineWidth',4)) I5 I: n1 j2 [0 d8 `2 h$ c$ x
( u2 d: r, H* ]2 f7 H" d' E9 S2 T
) I' _- X. U1 p+ [
6 y7 U! i# q* L5 @
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1. 编写 MATLAB 程序,绘制下面的函数:* j- A/ A+ S8 Z

- |+ [; s( q; Q+ p,其中
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5 X# b- a( }7 a$ a$ J# U该程序在绘制图形之后等待用户的鼠标输入,每单击其中一条曲线,就随机修改该曲线的颜色,包括红色、绿色、蓝色、黑色和黄色。
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: F/ D; H3 t- ]' P& e5 _+ e参考答案:
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t = -2:0.1:2;
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8 g* A9 z- k3 ?% @x = cos(t/pi);
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y = 2*sin(t/(2*pi));% q& y9 B$ I6 n5 E3 N. a; f

9 l- Q: N7 U: [9 Rfigure,plot(t,x);
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hold on; plot(t,y);& w  X* _1 V% K. Q1 {

! G1 M5 u$ `* M/ S8 r%if waitforbuttonpress
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7 W% \$ P3 h; [" ^0 S7 }1 fwhile(1)
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    if waitforbuttonpress==0; q. \5 q1 N# U

5 ^8 j- k- f: x5 b0 B        get(gcf,'CurrentObject');
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& ~: A$ g/ j7 d& f6 O1 n( \: b        c = ceil((rand) * 5);; u* {/ c2 _# F# b. I4 m# A' i) v

; u3 \% l7 A) ]$ I7 m9 x        switch c* ?: A3 b6 d& X" C6 M

0 l& H& G. b6 u. l            case 16 L) j! h* Y0 ?8 i8 m6 `7 m
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                set(get(gcf,'CurrentObject'),'Color', 'r');
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+ {0 y" x! d) t4 k# Q% [            case 2
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( `* z. m- Y# p                set(get(gcf,'CurrentObject'),'Color', 'g');6 R- X6 B3 m. j  ~
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            case 3
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& |6 P  U1 Y& R3 X1 ~1 X: W+ b                set(get(gcf,'CurrentObject'),'Color', 'b');! p. p0 g# e& m1 f
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            case 44 t9 I) I0 e* t$ U  c0 x+ I8 m3 H

9 S6 e7 H7 n1 A& J! O% [5 }; y                set(get(gcf,'CurrentObject'),'Color', 'k');  v8 R4 _% S0 C% d2 O* z# q8 d: P% z
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            case 55 Z) ]( `# L- H3 Y2 ^& h& ?
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                set(get(gcf,'CurrentObject'),'Color', 'y');# E! P- ?+ z/ @; c( T2 Q/ y
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        end" K* Z: K8 Q, M/ _/ Z
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    end
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end1 e* }( g: B2 |4 x4 F; }

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