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x
t = [1,2,3,4]; $ N" ~2 p0 f9 F2 D! u+ \
c = [1;2;3];
: N. i: H( ~6 x: c+ l6 D1 D- \r = [1,2,3,4];
# ^" G0 v$ a6 x! e5 [n = [1:12];
3 l- D8 u t: [# M8 S' T9 X0 F4 r" I5 @0 R0 d( j( g! G& O/ {
T = length(t); ( ^% T1 k y, l# }7 P( [& Z
C = length(c); % I7 `7 _4 p+ `- J. B5 q
R = length(r);
& C. P" s4 Z. C; O* S8 E( yN = length(n);0 O% z. c& v) B% A. k
" J/ C& p0 P3 ]$ @% o
X = binvar(N,R,C,T,'full');- T5 V7 a$ _# n' f
constraint = [];* H. C9 {% b3 @2 l( v7 L* S9 i
for h=1! w) J# i. t% N# D; X& X* A. G6 Y
for i = 1:N;$ S5 }5 ]0 T# X; d2 i$ W2 U+ W
conn = 0;
( p' [- d) W p% Z8 c2 f$ S for c = 1:C
& C) l- D7 p9 p% T& {) m for r = 1:R
2 Q2 c. M$ z- ~* o; F4 v3 U X_irch = value(X(i,r,c,h)) % 这个值为什么会是NaN
+ \9 {. o, B" T8 H if X_irch == 1
6 e0 x. T7 W0 y7 L" C! ~ P(r,c,h) = 1;: f; ~, q8 l5 L' M& R
end
9 |& g6 K- P1 v3 R6 F conn = conn + X(i,r,c,h);
6 ~/ Z: q. ?: Y2 S6 t. B# u, b- D end# R% r* O( N8 V8 x
end
# {" F2 F4 t6 K2 O: S& X: S6 t; F8 I constraint = constraint + [conn == 1];
7 e) a9 ?" \4 X; B' j end0 S H/ X2 U$ V1 m: N
end
) e% O# ~+ }2 x; w: @6 p
7 P# n6 M6 D% H; @5 Z0 J2 ?8 p有注释的那一行的值为什么会是NaN,不是应该取值为0或者1吗?请教大神!" m* s/ d$ x1 W" Z4 V) y9 `
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