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小弟初学allegro SI。现想仿真XILINX V5的GTP特性。请问如何给器件的某一确定引脚附加 电平模型?7 G" \5 t1 [0 S* Q& W
主要是有一点想不明白:器件上的引脚编号为A1,A2,A3……AW1,AW2……AW34;但xilinx提供的IBIS模型中的定义为:
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| Component VIRTEX-5
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|2 O; \: T7 V9 m
[Component] VIRTEX-52 w2 A8 e c! T; q
[Manufacturer] Xilinx Inc.
( V0 y" Q" S1 H% Y$ N[Package]
- k3 n) k3 r, B* y2 @* m2 x|FF1136) f' o: w% {' U! S& n" X- F3 X8 ]$ `( i
|variable typ min max
& d3 c7 w3 ~8 _1 qR_pkg 331.37m 22.22m 1036.83m
3 R1 P! v4 J# c; \) w2 k9 BL_pkg 3.70nH 0.52nH 10.16nH
& s# z2 L% c cC_pkg 2.22pF 0.91pF 5.00pF
! |) p/ x- M2 d% r2 T7 W# \ L4 X7 m& z' l2 @( a6 D6 u. o8 i, }7 \+ u
[Pin] signal_name model_name R_pin L_pin C_pin
- d( q: x$ R3 |$ d* A) A4 sPGND GND GND: C" S! f7 z T& |/ A. ?
VCCO VCCO POWER- P4 V0 n5 X9 t. p5 ]$ ^" B
| model selector- R* F1 v. I) p+ o+ c% E
1 GTL GTL
: Y( N/ b$ c2 I6 {% }, @2 GTLP GTLP D2 w j8 ~3 P6 |( u+ V! Q
3 HSTL_I_12 HSTL_I_12( A; o* \% H$ P
4 HSTL_I HSTL_I
$ ^$ |# e: c( }5 HSTL_I_18 HSTL_I_18+ C% I; }: m* V9 z5 U
6 HSTL_II HSTL_II 1 Y' P! S8 i) ]' I: \ z9 ?
7 HSTL_II_18 HSTL_II_18, |- n- D" k3 |7 ] x
8 HSTL_III HSTL_III6 W: r7 A T* c% H/ _
9 HSTL_III_18 HSTL_III_18
7 i1 i" p7 v; Z5 [9 t( `10 HSTL_IV HSTL_IV 0 ^6 l x( ^$ `2 Z) f/ l
11 HSTL_IV_18 HSTL_IV_18
0 u2 G! C) m4 K, m4 a% H- M% I12 SSTL18_I SSTL18_I
) l; l, v- Z* x$ X J13 SSTL2_I SSTL2_I , r$ r, W' j; g* c; p3 j, O6 \
14 SSTL18_II SSTL18_II
2 c) \1 E- U+ w/ v& @15 SSTL2_II SSTL2_II: Z+ t% ]% k* D$ @( w9 }
|2 c3 y8 ~8 E0 x
| Differential HSTL4 V) ?- d' n' n3 o
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16P DIFF_HSTL_I_P HSTL_I
4 p5 S+ {" s: L: P: X0 H8 R S16N DIFF_HSTL_I_N HSTL_I
3 T4 m# h1 v, b: n…………3 y2 N7 K4 k0 T. x' W' ~1 t
…………$ u6 {) ]5 n/ @' z
[Diff Pin] inv_pin vdiff tdelay_typ tdelay_min tdelay_max
2 \7 H* k7 R, E. i- Y|9 p; A$ ~: @, D4 {( z: Y* E
16P 16N 200mV 0 0 0
9 F3 X- A3 w6 D _* S17P 17N 200mV 0 0 01 p' X5 z; ?$ t* L, f. Z- j& b
18P 18N 200mV 0 0 0- D Q2 q1 {7 O" P, }
19P 19N 200mV 0 0 0
7 P# T8 Y' C1 I# x( E|
4 c; b! h$ t4 d! Z% M I20P 20N 250mV 0 0 0
% s! a3 g3 z3 `6 M3 C6 H- C21P 21N 250mV 0 0 0
$ I7 ?* h# X: A8 R22P 22N 310mV 0 0 0 n3 y2 x" R& z V
23P 23N 310mV 0 0 0
" j" `6 a( I$ B) ~, b|
- C$ e% G+ P6 I132P 132N 200mV 0 0 00 ?3 H/ _# f, S+ I: f1 q
133P 133N 200mV 0 0 03 d- d, Y2 @! A$ d. v& ^
134P 134N 200mV 0 0 0
$ \0 c; y. C: F5 F135P 135N 200mV 0 0 0 D0 F2 U7 f4 I" j. {: f; E
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