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我在学习matlab符号运算这一章时尝试把书本的例子输入，发现是有误的，以下是从发现到修改的过程。/ R H: Y8 d- o
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**在这里>> a = sym('a');
) O# E: V I( A2 `+ [7 P0 T2 i>> b = sym('b');8 \+ E9 C+ k3 k
>> x = sym('x');% _* J' O6 E0 f7 V* J0 m
>> y = sym('y');1 U: ^. y" ~- j f9 J4 r
>> [x,y] = solve('a*x-b*y=1','a*x+b*y=3','x','y')**) t& S+ m* f0 p0 j2 v' L
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Error using solve>getEqns (line 418)
; H' r `$ c, wList of equations must not be empty.' j- x6 [# L% F {
) v6 F8 A( E* b/ DError in solve (line 226)) V% D+ B$ ^6 Y
[eqns,vars,options] = getEqns(varargin{:});
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**>> [x,y] = solve('a*x-b*y=1''a*x+b*y=3','x','y')%第二次尝试修改**. t- q" g) Y w
9 w. Z6 r4 U# L# G; f5 g' QError using solve>getEqns (line 418)
! c. \* N2 y% k& KList of equations must not be empty.
% l% ~7 g) W3 h) ~! n) zError in solve (line 226)
( e- M8 A$ D$ L& j6 l5 w[eqns,vars,options] = getEqns(varargin{:});4 B# \3 F8 n$ a" H" ~4 z; m1 `
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>> [x,y] = solve(a*x-b*y=1,a*x+b*y=3,x,y) %第三次尝试修改2 ]) [7 }" q- n- K- {/ h
[x,y] = solve(a*x-b*y=1,a*x+b*y=3,x,y)- {2 o# h T, r
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↑
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Error: Incorrect use of ‘=’ operator. To assign a value to a variable, use ‘=’. To compare values for equality, use ‘==’.( f! Y0 C% ]. {
; R. j% W% n/ p( d( S" R: ?>> [x,y] = solve(a*x-b*y== 1,a*x+b*y==3,x,y)%最终成功
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. O$ T7 S, J% Tx =, M. c$ I; Y1 J/ Q
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发表于 2020-6-17 18:45
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支持！
反对！