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MATLAB基础教程之实例原文件 部分

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发表于 2020-3-25 10:24 | 只看该作者 |只看大图 回帖奖励 |倒序浏览 |阅读模式

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- B8 I3 q2 A- d' k. L>> str=['MATLAB 2006a']
1 K' u' S# y( e  F% _
1 t5 p+ ^' O; v>> str
* K" V8 S9 R" m
# ~4 G  C7 _, z3 |: V$ ~>> disp(str)
+ v% X! K) }" n$ L1 z% E
% C9 b7 i1 `- Y$ L' K%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
- R0 |! n' U( A, K2 A3 V* @" C, B# \
>> x=-2:0.2:2;
' S1 l1 l+ C8 c; S) K" C7 s1 ^
  m4 i" l9 Q  _# j5 S. q>> y=x.^2;* ]) F+ W) }# ^; Z8 L
3 A& Y7 s: Z9 v' T9 d3 b
>> plot(x,y)! G6 z9 Z2 v! h8 [  Y' k
3 }: T+ @* P4 `5 }4 X
>> str1 = num2str(min(x));0 v8 U6 d+ {1 E2 Y. v

% F: d9 n5 _4 L+ @5 V>> str2 = num2str(max(x));2 A7 l; Q5 a) Y4 g

/ D, n7 T( L5 N7 |2 A>> out = ['Value of f from ' str1 ' to ' str2];* Z, ~" ]$ }) I9 y# Z' t: M

$ P+ U+ B& \# Q% a7 W%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5" S5 Y5 b; m3 B- J$ n7 U1 P5 y* C

7 T% l& L1 X6 C5 k% n. H+ S>> A(1,1) = {[1 4 3; 0 5 8; 7 2 9]};2 @1 L# s2 T- C3 o# ~8 K
5 ^( [! M$ T" Q- M$ {
>> A(1,2) = {'Anne Smith'};  E% Q* Y- t4 D

, k" I* r) x: h+ \, `$ w, H* u8 C( g>> A(2,1) = {3+7i};( n! Q5 a- w6 k3 B
1 I- _4 s3 J& S/ Q( l. Y1 k& p; \
>> A(2,2) = {-pi:pi/4:pi}7 y9 `, G, ]3 A# X6 p+ k
! V8 }! a* m! e. k6 m+ w
>> B=cell(2,2)4 f( N1 S, o3 @  u0 k) @
7 i3 R$ h# c2 f2 Z
>> B(1,1)=A(1,1)) }2 g* [6 N% P
>> celldisp(A)
; s* x" r# B- }$ R# u. S>> A{1,1}0 h5 Q, k  t, y* |* j! j
>> cellplot(A), d& \- q7 v# V7 `
9 J( M1 P) p; ~0 K2 S3 h0 U
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
7 A( r9 j* A- S. R% w: P
' \5 u! ^' y% J>> clear  `) h- `9 ]0 M3 v( D1 c3 J
A=cell(3,3);1 f0 T; {3 o- Z! v+ d% ]
for i=1:3
& d( K/ |5 f8 G7 x6 \! T    for j=1:3
; P, m# ?* x2 T1 O/ Y        A{i,j}=randn(i,j);
- R6 D7 u" I  p6 l  Y+ W: _0 J" [    end
2 z( [( M+ ^$ u0 Q( A3 V( V. n6 n3 ]end+ `3 K( {/ E8 F$ z
>> subplot(2,1,1)
4 _7 \9 M: c8 P- p>> cellplot(A)
! l! D: J# q5 y2 `, ]& T& m! U>> A(2)=[];
1 Q' v, h$ Y% m- Q$ l/ R- |; {0 r>> subplot(2,1,2)
% U: Y  W2 [/ k# W, x+ e>> cellplot(A)- U1 V( x, M( z; `6 L# o. M
>> clear
5 ^8 u# T8 D1 |% GA=cell(3,3);, O0 i5 J; K" D% {6 d
for i=1:3
7 [8 Q0 n  g$ @& N    for j=1:3
9 L; g' y: S6 ?+ P: b/ G- `        A{i,j}=randn(i,j);
, f. D4 ^  C# W7 B    end) v$ }/ t6 ?8 `; E) \9 X* W
end
. u, }' F3 p0 l  Y) Z>> subplot(3,1,1)( ?1 B0 J* c, U+ U5 R) A7 E
cellplot(A)
9 f/ Y1 c7 n# @4 n$ v; ZA(2)=[];/ V9 N2 Q9 l& {' p5 ?0 g* R! a
subplot(3,1,2)
& i+ O0 j. m/ P$ [5 Kcellplot(A)
1 `) q0 d; v8 H) u$ t& `! B5 j>> A(3:5)=[];$ [8 e9 ^" _/ E  v: M5 j
>> subplot(3,1,3)
/ N  u/ s8 `8 \9 J9 mcellplot(A)
6 q5 Q# }6 s9 ]% B  X- W# I# N3 f
0 I3 `) Q. G: Q5 ~; \; m$ R0 Z$ Y: b: s
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%/ |+ V0 d1 r  n' y

8 W. x+ {# c/ m4 N; p" ]>> person.name='liuhuiying';  A0 @% j1 ]6 N! ~* K  g1 ?
>> person.height=162;6 i4 k/ p% O& c9 V: Z
>> person.weight=51;
6 J% @  ]* P* X>> person.hobby='swimming';
9 ]1 I1 L$ Y7 B# ~1 N>> person
6 I$ E! S7 k+ Q0 G" W% W- i+ C/ V, g
>> person(2).name='zhangqiang';- M1 g7 J; t- b5 B6 M0 i1 W8 `
>> person(2).height=175;6 @. ]$ L6 R% E2 A2 F
>> person(2).weight=65;
3 `6 v# d5 A( N! E! {>> person(2).hobby='Game';& o5 d8 S* g7 d* S9 g. z; s9 {/ u
>> person
. x) t3 G1 q' F" s6 _$ d3 i- c. P, \& n9 ]: a+ {
>> person(1)1 ]0 o  k2 G9 \( O

- B! Z1 f4 G' e>> person(2)
* x! K+ v+ T, C: ^$ U) D4 l  h, g4 m. W" \) R, b/ n1 N6 L
person =6 d* V9 B  {% n: @: }2 r, l0 K

; Y, i1 e9 ~! r& f: q      name: 'liuhuiying'
! P- b. q) X+ [0 i! \; b    height: 162" M5 R/ ]1 ]9 o1 f1 U) {: P
    weight: 514 l1 {" |5 u4 Y1 o6 D+ Q
     hobby: 'swimming'
0 e! G' v; r- x/ J8 N) j" q4 F. M, [2 c8 j
! }2 P- P; K2 v: J8 J" h: `, @) o
person =2 ~! g+ V* M2 [

; }$ _, t% }/ |1x2 struct array with fields:+ e# b4 B! ~6 [' J; B
    name) H% R9 p3 u" z3 G; Z; l. `
    height# E  U- e/ W& |9 Y
    weight+ h) u& Y5 n/ r4 g: T( y& d. n
    hobby
; s9 l6 Z9 |: u5 W: `
3 M+ d& C0 k% h3 @3 i3 H
7 O, U9 \. e0 o+ q, h( J, hans =
" C& U  T# n9 I. w- C6 {6 v! l3 n- C% l
      name: 'liuhuiying'" Z7 I3 t2 z8 A+ t6 ^$ Z, I
    height: 162# k& I* H9 j8 t- @
    weight: 514 W! T; A, A  D& F
     hobby: 'swimming'* ?* S5 D! E0 c9 R

, R4 V0 B8 z. u9 ?6 M& D$ n- [7 ^: `, ^2 d) E" L0 H
ans =
& g6 |; O9 G' g% h+ j9 F2 v- n5 L" r. _
      name: 'zhangqiang'5 {& s1 P) s, N# z
    height: 175
" J* m+ `( ^2 t0 X    weight: 658 h0 l0 h% ?! \) n
     hobby: 'Game'
/ ^) l8 z, M" L6 S  g* n/ B0 a/ S
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
2 w$ v: [1 f9 P5 q: J# H) C) S, _, h1 \$ A: Q, K( ?2 N8 H6 m
>> person=struct('name','liuhuiying','height',162,'weight',51,'hobby','swimming')0 T: z# u: e. M; r
9 u1 Y  r+ W# C- [
person =
& F' H: N! X# N" U/ g$ W! k& q, w
      name: 'liuhuiying'
8 M! {! L$ W( Y5 Q+ w' y    height: 162! s( h1 p' V! R7 J
    weight: 513 b( v9 p, q6 U, ~1 d
     hobby: 'swimming'7 N1 N/ X# ~6 p( u- v+ Q7 k

; ^( U9 s. [0 d: g. w+ D6 z%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%; Z0 ?7 G; Q* G" y& o+ l, h% y
. x3 I1 N; t8 P
>> person=struct('name',{'liuhuiying','zhangqiang'},'height',{162,175},'weight',{51,65},'hobby',{'swimming','Game'})1 b* c. k8 ?% |; M5 P; A, S/ ^5 i
8 s# W9 d+ M4 l/ t
>> person(1)7 y4 ~$ k% {! L+ k$ A+ M! Z5 `! u

( D, K0 p1 Y' C$ @& y, b>> person(2)" c- j+ k7 r2 h2 w1 Q7 `8 |

: G% P$ P- J: k. x
  Z" Z2 P* Y$ s+ {2 s) ^! o# V4 F- ~  `3 Z8 K' j( q$ Z0 M
: i$ {2 p3 S; T( y0 |
person =
/ _+ m1 ~3 C9 C$ J7 G9 P' g6 I  i/ H; [5 R
1x2 struct array with fields:) R2 Z: [& L( l) c8 }+ E, m' g
    name
+ @3 y# F! U* h6 Z# v+ v5 Y    height
9 h5 v. ]; o! P' d    weight
! B2 D0 v7 m1 g$ N2 V4 E( g    hobby; a! m; X- B- }' H" U9 L5 _0 H

5 q4 f1 Q. `- p( w9 ^3 w" d% f: B' G3 f' s9 o
ans =* i! ~3 X$ v; T2 b
* X1 @. ]: E; m/ \4 w3 Q, g
      name: 'liuhuiying'6 Y. g7 ]1 m. r  o; J3 X) _3 r" j
    height: 162
6 V# M& u2 z# k# \, C4 e) g    weight: 51
$ A$ H6 l, N6 g4 x3 _- N0 S     hobby: 'swimming'% s0 j, F0 k, g& w; ?8 N+ t5 T1 r4 A
* D* M  ^6 L; ~( x$ U6 E
' H) v" @8 B9 r! L
ans =! \4 ^! e9 F4 V% A/ K; q+ r
! J9 I' c* W  J! B$ \
      name: 'zhangqiang'
( D4 Z# @2 B: f' t, _) @) @    height: 175
" I2 k$ g0 p% S2 E    weight: 65
6 C. k: q& b* \/ g7 T  v     hobby: 'Game'4 G8 i/ W+ h4 n, n7 Z0 D
, M( k2 q1 z" \2 {
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
5 ?: `7 d" _2 i, {
" ?( ^. v' q$ \; U>> person(1).gender='female
2 F" w. k! k) w5 x! E/ {, v0 ]3 [9 q
>>person(1)
: S1 M1 Q! X& @& k
) D2 @' y9 R5 G>>person(2)
6 {/ H! J/ F) F" R2 M, h8 u, R9 _$ x" c
person =
" d8 u) B7 c" M5 e8 F1 o& d7 O- p  g* S& u5 h: B/ O2 N# ]4 O+ O) \' e
1x2 struct array with fields:9 a2 v- F) ~8 P+ h0 W* E1 \, ?. L
    name
6 W+ }$ ]6 s- }! d; s# E$ E$ Z    height$ _8 |; K+ O9 v- e
    weight+ @$ ^3 Q0 B9 b8 N% d
    hobby1 G3 G: z7 S* [# f
    gender$ ], x( m3 i  s( u1 J9 B
. L; V9 h( w8 s" X7 l6 V" G% Y( U

  x5 O4 R. g' E! [( n. b+ Q8 F0 {ans =
- @- ~) O3 d+ z5 H' y; m# t# d2 p  u, V6 I) V7 W7 R% X! F8 D
      name: 'liuhuiying'# o. }# g7 {" u% [' r* ^$ }  [
    height: 162
. h" Q% D$ d+ x    weight: 51# i! l9 k' s9 h! g" Z4 x
     hobby: 'swimming'
. V) g9 B: s1 F) }  y    gender: 'female') I5 s/ l, @6 z1 ~1 U; M! b
7 g& s! D" G* E9 z- Q
0 U+ @9 N+ s& _) r
ans =
& M( ~% n& q5 F( P- H, f6 H: ^
, ]0 R( k- e8 p' ^# D) j      name: 'zhangqiang'
7 X  z5 |$ y: y' V/ T& X' g+ \: R    height: 175/ o9 n! L* t1 i6 ?, g
    weight: 65
8 n" P; T- F$ {; w5 b     hobby: 'Game'8 i5 A3 S) R" c# Y
    gender: []# R* O  M% d' w( R+ H6 _
6 ]1 `3 ?/ @+ R! g( e
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%, r6 y6 S; P& E6 j
& ]* {3 t$ U2 }7 R
>> person=rmfield(person,'hobby')
( V% D& D& U* m
1 N- X! U  t7 |) h; u+ T2 J4 U8 W0 @>> person(1)# ?$ \: Y7 ~3 ^/ `4 M. j
% O  M' [7 g# q' R; e( L! Q! O
>> person(2)
. H: P0 |  S( K" j6 w* W+ ~- u/ |# A4 E6 ~0 d7 B& c/ ~

/ i2 Y" b( ~% c6 `
% e2 Q+ d- a( ]1 o) _* q# iperson =% H, X7 ^% d8 ~2 m

& P+ g8 g3 ?# {" t0 d1x2 struct array with fields:
5 q& j: y  j. \5 i1 t! \    name: c1 m" u. {7 G0 M/ r8 |/ f5 \
    height
% Z5 {- Z! X/ \    weight
+ P2 D2 W: Y0 u' n    gender8 ~5 ?3 Z2 w9 b, O# _
. ~. T6 N1 f0 Q9 z2 }! y* }

8 @" U0 ?3 f+ F6 b  b, s3 v2 }4 Qans =
! L. X$ r9 u% P6 N6 V! {2 {  r& U/ e# @$ T4 t: x
      name: 'liuhuiying'4 W7 Y. d9 k' K& k7 f3 o
    height: 162, s0 m( ?5 u# t" t
    weight: 51/ o+ E7 R* T) W1 ~' g7 N' ?1 B# h
    gender: 'female'
4 H0 S; G" E# `, G( q
2 h* ]" R- Q0 R4 c: j0 d* L8 ^
# ^; f1 ]% j% i0 m0 W6 k6 k. r' [. Pans =
* ?! n# F4 A4 h: ^# t4 b
/ q9 q+ J4 j, x1 {) E/ n' o8 n      name: 'zhangqiang'7 d; N/ o, h# \! c, N- q9 f& m1 I- ]
    height: 175
4 P* T6 b5 }# r, k    weight: 65
* W3 x5 h. o6 M    gender: []. N8 s0 r6 f* p) U' [( U- v
, `2 M( [9 A. S% U# _( k# U- |0 Y

$ C6 X4 v  _" @7 J5 _
7 q) p  ~( x( H' j8 f1 U%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
! e3 J. t( [4 H2 @$ v8 i7 B2 E% E; {% U/ U; k7 B3 W$ @
>> person(2).gender# J0 y" J* z. N: t( ?8 K1 p
- L; U% o( h3 m2 c4 ~+ p- I
>> person(2).gender='male';
, A  Y) d' d/ E/ S6 Q2 I& G3 f$ ?/ }9 R3 ^! |
>> person(2)
( v, j' [6 |2 r/ O- Q/ w8 W
6 U8 J" F* F* `; S: {: I0 J
' ?* n5 U8 N7 f8 b
5 p. Z& G0 L# i8 w# |8 F/ Z# _7 \ans =6 b2 W5 I& c+ i  L3 N% `+ j
: m2 F& j, b1 O, c: G
     []
: F9 a& f8 Z& G; W4 N& s
3 `. O( n! W4 A- M7 U/ F' r
  l1 D! d7 ]$ H0 c6 s. |ans =5 W; m( e$ A" r6 I
" }$ n$ ~. K) ~  m. A% y. I
      name: 'zhangqiang'
3 x1 ]9 {) n9 q* ~% v! m    height: 175
9 G# y0 F2 n% t: |' q" ^, ~    weight: 65
8 y4 @' t  v8 ^! J  }$ ^* X    gender: 'male'
5 K3 g) e6 T# t- y+ s& ]# Q
2 @% @# |5 O+ w: ^* u& ^6 `$ q. Y
& T5 I" ~5 f1 j2 D8 P) u+ L8 @
) g$ t2 X/ d: X* ?6 \/ ^1 O%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5- g6 R$ H3 v) ?! g9 C$ Z# e, N" p  K
$ u0 x$ i; k% K1 N0 P0 H! q  A
>> A=[10 20 30 40 50]- b  }# r- h  o

6 Z3 G* V7 }" L0 p( c& V) s: U>> B=[10;20;30;40;50]+ c% X& k+ X0 R

6 `" ^' u2 v# Z# o) Z# T%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
4 w% Q: b- }9 U5 J8 V0 m
% O4 L5 p! S( c8 U1 Y>> A=1:2:8
6 f% X3 ]3 y$ r0 q* x( I% M0 U) x/ W$ n4 k9 E2 D9 [' i
>> A=linspace(0,12,4)
! a1 T* R, R* T' Z' `' U
9 `; B$ w. V' `: c%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
- ~& `, R8 ^( ~% o) e' K) f
* d5 O) l! A4 c8 ^- q% Q- r>> find((A>8)&(A<14))       %找出矩阵A中大于8并小于14的元素的单下标索引
5 \# U' {) v. ]  W6 V! V* i/ u/ X  K
/ h4 v; q/ c4 n# g' r>> A(find((A>8)&(A<14)))    %找出矩阵A中大于8并小于14的元素
% G, i; D4 c+ A* V8 {1 ^2 K; |
3 A; w3 r1 B% Y" d" ^%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%57 J, Z. u) _8 }% o8 t$ y
2 n* B4 a4 N& b8 J+ T7 Q
>> A([1,3,6,8])  z" u; G1 \8 r* z1 P
% A. J( a, \3 l* _
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
! a; Q  [3 y& A# B7 f! L% Z, X4 l& b4 t2 j' u" Z+ f
>> A=rand(3,3)% S# ?$ Z, `% r( H

+ c, B& h3 @; l" O. N8 n# l# b>> A(:,:,2)=randn(3,3)" F# E6 ^! ^1 ]0 F$ z
, H0 E4 m# n* |
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
3 s# D8 m% q8 v+ m0 x" u9 j3 l& X: C" s1 D6 S; @6 T
>> A = rand(5);
+ y- @1 o# w7 O
' g" D# X+ \% D. g9 k6 P# ]& P* z>> B = A > 0.5;
9 F% r5 X$ Q& b6 j9 e. s* {7 `% ~1 p
>> A(B) = 00 w" S2 f; e$ R
; g: m) \1 m; K
, i7 }( V/ n' W. B1 V

, X( R2 e' s; w. j+ _/ SA =
$ U% C% s8 v+ _
; }1 y9 w6 z( d2 e3 k    0.1450    0.4018    0.2400    0.4909    0.11129 O8 Q. u+ @; O1 }. U
         0    0.0760    0.4173    0.4893         0. r& |7 K( u. Y0 E0 |7 j/ e
         0    0.2399    0.0497    0.3377    0.38975 I, _2 \% l0 @* U5 h4 D, }! s
    0.3510    0.1233         0         0    0.2417
! {% {6 [6 A, x9 Y- Q         0    0.1839         0    0.3692    0.40390 h0 a0 D3 J6 b, t1 y7 R; A
$ _* E9 h  I4 F! Y$ t0 p: F
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5/ n1 N  R' @* ?, t7 ^  D

: I2 i$ j/ o  ~4 ^: o  q/ h% X2 | >> A = magic(4)$ P- _% t( Y# m' g: j
- Q, J% \+ A+ O" E/ r0 t1 v
>> B = isprime(A). g( C% d' |! F. Z  x) j

8 H' Y9 V. v$ `' b7 e7 _( K2 L6 T>> A(~B) = 0
4 w. [# q- `" E! _2 v* E2 Q' |8 v3 x0 y5 }
& t% ^. p8 F* I$ v, G; q; g

- w$ ~7 }$ Q: z, b6 D; s4 F%%%%%%%%A =" r  U. t6 g5 y5 K. J
5 q( W7 K9 x* d: t- x
    16     2     3    13- G* e! V0 r3 v2 A) ?
     5    11    10     8
. Y, B5 o' R. g; X3 F! M     9     7     6    12, X# s5 [" d0 O
     4    14    15     1& x3 m. ]: O9 u7 H+ F# L, y
$ P9 ]: t8 R* \; V) l: B- ]2 @% o, H
' j: a* n8 f+ T# z1 N4 i! U1 U
B =* v3 P& s" E/ U' J; n% S/ p. |
* w2 p9 T: W" w9 J( ?  q: V5 I
     0     1     1     1
% S/ a# O; V+ Y) C- _     1     1     0     0
% Z5 j5 k' V5 ~) `2 m6 ]- ^     0     1     0     0! B5 I2 h! ^+ y) m6 T
     0     0     0     0
) u% m1 F; ^5 s; d8 {
! }) h% i- y; B6 a+ t
5 F& _" ~( v7 e1 O- O. V* eA =4 K% L' ~  K, c8 h2 [, C. ?

6 N7 i9 p) X7 x" |     0     2     3    13
- W& a# ]4 S- H+ Q1 h5 {     5    11     0     0
2 N* r% \. x, w8 W: P) |     0     7     0     0: o! |4 w0 U9 I
     0     0     0     0
1 J4 R$ {& l/ z3 [1 U$ D8 u" r6 X1 a" k
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
' _, v' @- r3 x: Q2 s! w9 A8 X
* ^* m0 P5 r% m% h. b >> r=[1 3 5];
3 _  `$ R; s* M  R% c: j
1 O' o- b, Y1 X>> p=poly(r)4 o8 c7 T) n6 v9 q# f+ \
* @/ d6 h7 _" i; ~# [
>> poly2sym(p)
/ F; X4 h; ~1 G( X/ a8 S, k$ [
' n' o7 e/ R0 a7 T1 a>> roots(p)
) C: }3 t$ @  f# B: a$ H  u2 K2 J
. B: N3 }( u/ Gp =, E8 w: J1 t" g

) r0 f6 u1 V3 Z) H$ P8 E     1    -9    23   -15
6 x' `# \* |. e* H6 T
: |8 p' m$ h5 @ " U3 f0 X$ {2 x5 g% `; V1 c) O
ans =1 w  K4 b- _; f) D8 g' s; N8 K
! ~& @- N: U- }; o
x^3 - 9*x^2 + 23*x - 15* s* N/ x, [$ Y! ^

) A& E# H" x* Q  b2 e' l, O4 D- L! q. C; E) U" c
ans =
* f# ^* @# g4 @5 y& F5 L' D$ F. I( ]2 B( T9 g2 ?# Z
    5.0000( w  W9 c1 W$ c$ O
    3.00008 Y7 ?, {7 `4 r  P' C8 Z/ m) S
    1.0000# o9 g' U2 N$ F% |2 T$ M7 I4 G
& Z. ]# p0 u) j7 N7 q* G
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%54 M* s9 {) [; p& D

$ N. j9 E4 C8 I8 C>> p=[4 3 2 1];& U) y; A6 F, Y" b2 u

4 g# S3 \  F5 I- `>> polyval(p,4)3 B" i# x: t5 ]7 A& H( p& \

# O! H4 \% c) \. [$ v4 W9 C8 N& A# {>> 4*4^3+3*4^2+2*4+1
. C: M) {' d' o/ C+ c6 u
/ O  w+ {5 ^! x6 c2 G
; e: a& X8 S' u/ z6 c; wans =
& y4 H8 U: x# P$ ]) D3 t+ [, V1 J9 J) G4 s6 n/ e, O
   313, m$ n2 X( k( i( b  j; R2 d
; i7 @7 n% R7 n% Z9 U! `

4 M& J) S; Y7 J4 A. ~4 c4 z$ t# @ans =
$ W8 k+ L1 E8 T/ ~% O) m# U) @: L  |5 q: ^- o6 }9 A+ I
   313
) F, n% K; {9 H. S% N/ K5 t, A, s# U$ K& i6 N$ C
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%59 J' J" Z, g4 F

) g: i# P# P, z. ]  M% fit sine between 0 and 2*pi using 3 order polyn0mial
; s( G% ~. s1 o4 \x = 0:pi/10:2*pi;
# y8 C# q/ ~; A2 G/ r0 e' I: By = sin(x);/ W( e# p7 t6 g, C: e
p = polyfit(x,y,3);
7 G* n, {0 a1 O9 k7 q% Splot(x,y,'r*');
0 t" b) F$ Z' R" L, Nhold on
3 Z1 H% [- W2 w5 b; {% ^f = poly2sym(p);) W' U* F, U# g: N% u: b5 s* o
ezplot(f,[0,2*pi]);8 b! J2 ~( M# J; k8 y( y* O

: m& b$ u4 G9 h% z( _>> p
$ y" G1 e% @5 m  S
1 m0 l/ Q5 b4 Y+ Q# T2 `) g . L7 _* _$ ]+ }* ?0 |: q8 n1 @' [/ T
7 E0 F- m0 P# M9 l( G

3 I7 V: o% h5 ?8 x; P5 U%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5! F3 U4 L& v7 E$ Q" p; x6 `
1 `4 X; _! g) G/ W4 Q
% Interpolation using the four methods, c, ?. U! L$ l
x=[0 3 5 7 9 11 12 13 14 15];- G2 g6 H1 x) {- c, u: [
y=[0 1.2 1.7 2.0 2.1 2.0 1.8 1.2 1.4 1.6];
6 Z  A; }  F6 S0 r0 N) ~0 Glength_of_x=length(x);
! M6 _4 G' `1 e& g1 ^1 N+ Gscalar_x=[x(1):0.5:x(length_of_x)];
& o% V) S  n+ L8 `* c: ?, \# jlength_of_sx=length(scalar_x);
; z: I3 F, r4 K- [$ lfor i=1:length_of_sx
9 W( C' ?; l) l2 Y' S& @) S( l    y_nearest(i)=interp1(x,y,scalar_x(i),'nearest');
0 c% [  g+ h, |, _4 a    y_linear(i) =interp1(x,y,scalar_x(i),'linear');& L6 }" o4 _7 X" p
    y_spline(i) =interp1(x,y,scalar_x(i),'spline');
# |; ?  g) ^; }  v; n    y_cubic(i)  =interp1(x,y,scalar_x(i),'cubic');
: v9 b+ o/ T6 j; [- j8 dend
0 y$ u3 o9 }* z7 B5 Zsubplot(2,2,1),plot(x,y,'*'),hold on,plot(scalar_x,y_nearest),title('method=nearest');, h5 L9 M  C. F7 j3 ?. k
subplot(2,2,2),plot(x,y,'*'),hold on,plot(scalar_x,y_linear),title('method=linear');
- K5 r" j9 T/ }6 t5 B3 M% Psubplot(2,2,3),plot(x,y,'*'),hold on,plot(scalar_x,y_spline),title('method=spline');
1 ?1 P7 K7 R: }subplot(2,2,4),plot(x,y,'*'),hold on,plot(scalar_x,y_cubic),title('method=cubic');% E) P3 t4 m1 q- ?, ?

- |; E3 g5 C& v# N+ S 7 L8 J' T% Q" N# y: r0 M$ X
' j+ f+ a2 D6 D, G3 i% P  y

) g  d, y4 l) Y! s%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5: z% }- K+ p9 n! H
, O  R/ V) t9 B6 S; D
>> fh = @(x,y)y*sin(x)+x*cos(y);
  L( {7 `% F* t  S  A: w* w  _; a! c* M) A
>> fh(pi,2*pi)+ y+ G7 t" ?5 _8 c

. @4 M5 m9 [+ f. y; T! D" N3 y%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
: T& z& y& }7 I' ?* k7 C! H; Y, T
9 ]: h/ _% y) f9 x( o fh = @humps;& T6 G+ {% b) W. o$ U
5 j2 o, X# |8 d+ Z& e
subplot(1,2,1),fplot(fh,[-3,3]);+ I% P5 L; }1 Z/ b: _$ y* l, @
: ^7 }; `  k1 ], j2 h; o0 Q; O6 l# C
subplot(1,2,2),fplot(fh,[-3,3,-10,30]);" ?8 U8 d/ A" ~5 w

" w. d0 f' E7 X$ m1 G' N0 q, n%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
, v" M5 P+ p, i6 m6 U& a0 S
$ ^$ x# M; D, Y0 } ! q6 W# K  \' v  t
+ s/ g; ~1 ^* f" K( s
% find the minimum of the function f(x)=x^3+a*x^2+b*x+c# x3 d: A/ m' I. B5 a  G, \5 d5 b1 L
function [x0,y] = funmin(a,b,c,x1,x2); G9 j- y4 K& x6 f; V8 G! U9 i
options = optimset('Display','off');! Q3 @3 j0 v+ g. T6 I3 {
[x0,y] = fminbnd(@poly3,x1,x2,options);! ~! R9 f& J2 l" c6 Q! _
    function y=poly3(x)        %the nested function
' d3 s* l/ R5 Z3 O, a        y=x^3+a*x^2+b*x+c;) Y# N; u( E$ A' I
    end2 T! q8 U; y' m
% plot the function6 T+ k) F" ^! ]; X% P) D: w
fplot(@poly3,[x1,x2]);/ }* n) J1 D( W9 X
hold on;3 g! ~: y* [; O8 i
plot(x0,y,'.');
% n( M6 j* M5 a7 L) \, {end
( ?7 M# \. ^9 q& v5 X  F6 t
3 I2 ~+ q$ t1 Q$ q3 q0 {>> [x,y]=funmin(-1000,10,0,600,800)% E, r- z: ~- L7 l
! G+ X/ Q" N/ `3 C+ A

" g0 f3 I. ^' i5 R) l$ N. e. Q! [, O/ U# I1 `# j
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%, M) H% S. d/ U3 i. j& V
8 r$ \+ F. W* X/ K& E9 M1 g
>> F = @(x,y)y*sin(x)+x*cos(y);% G& O4 _* Z1 q( u/ [9 {5 }$ S

- `$ |8 H0 z6 X2 M1 ?  }>> Q = dblquad(F,pi,2*pi,0,pi)
' A9 y. m7 D* O, Z6 X. W
! C8 C" V( F" v* h. s6 r%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
) `; y" p3 h, M) I& d$ c: F: W' O2 I3 h8 t; ~9 y7 c
>> h_g=@(x,sigma2)exp(-x^2./(2.*(1:sigma2)))./sqrt(2*pi.*(1:sigma2));, Z( L$ i8 X  q; V2 v- R& f1 `. j
2 ?' D% F( I3 o' S  k$ k4 C
>> quadv(@(x)h_g(x,3),0,2)
: c0 X- Y% J' r( W$ _! L$ _( \' c4 W" C
ans =) n, }" o0 c6 I$ S% M% q

% @; B/ K5 Q1 D6 R$ R" u5 _    0.4772    0.4214    0.3759! Y3 H' [" O- O  U" w2 d
) z/ I) L" m% C; v
>> quadv(@(x)h_g(x,2),0,2)
' Q5 @5 c* }/ U: Q
. b/ }3 ]5 e" p% l7 y2 P: ~ans =
  `6 R9 @3 I# M- s! U! g/ v: {: h/ Q, w! {) X+ g6 H$ y+ a
    0.4772    0.4214
" X4 k/ U0 q' s% }1 [, _4 @% W: f. `
>> quadv(@(x)h_g(x,1),0,2)
; g) I# W3 V" }' g0 c0 |: l1 ?: T5 }3 g- ?# F& e) w& O
ans =
  R1 e" n8 e9 U! D) z1 \# K1 [3 {1 g! W* |8 y* q
    0.4772
+ l& f6 z/ z4 s) n
" F9 m$ \7 F% U+ Y: f%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
. B7 v; S$ [$ l/ |& N
( ]+ c* E# G* @3 m- H" Y3 @% the file to creat a function with parameters. T( |4 s7 d8 M( b. q
function y = poly3_fun(x,a,b,c)4 b5 E  }% z: J+ a% |4 W
y = x^3+a*x^2+b*x+c;/ ~9 }5 Y1 |1 Y/ g7 z5 Q. t% m
& Q  N& U9 a" ?& g

  L* H- L3 g. c4 t9 M% find the minimum of the function f(x)=x^3+a*x^2+b*x+c
" Q0 d) W) N& L9 U/ Wfunction [x0,y] = funmin_para(a,b,c,x1,x2)
( G. X9 \/ A1 t- {8 x* ^options = optimset('Display','off');$ Q  M! S" C# I6 w+ `& Q
[x0,y] = fminbnd(@(x)poly3_fun(x,a,b,c),x1,x2,options);
: P3 D9 e6 a( m: M% plot the function2 c% `) T8 X( }4 L" b+ P
end
$ _/ i, I- W# z9 l
) c3 Q9 J2 i9 a* v2 O( p+ p" E! K6 a* l7 k& }
>> [x,y]=funmin_para(-1000,10,0,600,800)
/ s1 ~* U* |5 ~0 @9 M+ }
* M7 _3 B( j4 u2 t+ Y& [ 1 @0 f) {6 y6 W/ P: s, d

  I0 P7 B( d% @7 z1 e%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
1 d  \" l5 a8 P- Q7 v5 @# k
/ e/ C& C2 g+ u2 l+ I# H
/ |0 _+ E! O6 S. B4 B4 M5 m* s4 D/ U" i8 b' f
% polynomial operation
/ ^! \* A" C1 V8 bp1=[1 2 1];                         %定义多项式' C# _* A  n: U9 P  p5 ^  U& d
p2=[1 1];
+ j! d* H' E+ u& h: ]9 e5 [length_of_p1=length(p1);
. |9 y% F# H: z# elength_of_p2=length(p2);
& z/ S, x0 {3 L  w' D4 h2 c" lif length_of_p1 == length_of_p2     %判断两个多项式长度是否相等& q0 I7 r6 ?5 U, B$ i" o2 ?
    p1_plus_p2 =p1+p2;              %多项式相加- G8 G- Z. T3 d2 U& n
    p1_minus_p2=p1-p2;              %多项式相减
  t$ _2 r! ]$ X$ t8 w- g$ l& p) selseif length_of_p1 < length_of_p2
4 O4 [- y& ~+ f; V& Z        temp_p1=[zeros(length_of_p2-length_of_p1) p1];/ q. J3 E# H% M9 d: I
        p1_plus_p2 =temp_p1+p2;
' a3 J9 d3 e7 Q- T        p1_minus_p2=temp_p1-p2;; X; M: X+ u4 I; X$ B% m
else8 {- B1 c* f8 |- y: O$ ^: H' [
    temp_p2=[zeros(length_of_p1-length_of_p2) p2];
/ x. m& N3 M! [" M% q    p1_plus_p2 =p1+temp_p2;1 p) G" S, W, `  j0 m% Y  j
    p1_minus_p2=p1-temp_p2;
" A; j* |+ g8 d7 jend% V9 G: d# ?) H8 ~+ X9 U6 }
p1_multiply_p2=conv(p1,p2);         %多项式相乘% x1 j  Q5 p7 O
p1_divide_p2  =deconv(p1,p2);       %多项式除法+ T) z9 S5 }0 N; U
p1=poly2sym(p1)                     %显示多项式 p1; v' B5 v) c0 o: R; ?/ }% n0 k
p1=poly2sym(p2)                     %显示多项式 p2
4 J( N; M; }& k) T2 R4 ap1_plus_p2 =poly2sym(p1_plus_p2): b1 i7 |6 Q% U1 T
p1_minus_p2=poly2sym(p1_minus_p2)
# a0 y3 [* \" m# T; ~$ Wp1_multiply_p2=poly2sym(p1_multiply_p2)
/ v* h1 H6 _( G0 Y5 C# {0 Ep1_divide_p2  =poly2sym(p1_divide_p2)
9 U0 D5 H- H: E* c: p% @3 z1 x. H+ l: Y

  d3 f5 \4 t( h# T3 h; z( C9 X: m# U

5 ^* Q3 a. d! ]% K+ h; Y* ]7 N* W( \' r
7 z) G" V& g1 y& Q
! c+ C  A+ G1 L# [5 p/ }5 }, \8 b2 s0 x
p1 =
, ^1 K: ]& K: v* ]6 @, l
+ E+ E5 i. ^6 r/ F; M# R7 N4 _x^2 + 2*x + 1' B* l0 I6 l5 f$ a+ e: H

; y( s# Z$ T* Y: q
! B- {- F+ h' E9 n8 jp1 =( z9 i4 @, X+ R' u

# ^, m( V0 d( O$ j3 C+ N/ @x + 1
" V6 }5 [: G9 a/ u 6 U/ i+ I* Y( W" Q/ L+ |6 m$ w2 W
) x* _: F5 y; w, W6 b& I
p1_plus_p2 =
8 F/ p* N0 D$ S  m- T3 E$ Y$ O
$ l0 I1 Q" s' Ex^2 + 3*x + 2  X' H+ }: A0 o% Y" Z0 x
1 v) e2 n* J  f9 _$ ]( K
+ h2 q3 x; P8 D3 C
p1_minus_p2 =
3 j0 T$ a5 m. |7 o9 i" D! h7 N: a4 l
% a. d% `+ o* _- P& G# Ix^2 + x
- N( z7 Q2 q: o* R" T2 n4 z2 m: g
' r4 T1 a( j4 d5 K6 E: u' o 1 {/ u% f" y& v$ S- t' s
p1_multiply_p2 =
2 J) C" B8 d  {) b7 f- X
1 h. Q5 T& I: n9 Y8 W: g, |x^3 + 3*x^2 + 3*x + 1
# |# h- \2 t7 @4 A- W3 v& g# f! I 6 t* V( ^/ Y8 e1 @
3 d. J; K% G/ x0 x
p1_divide_p2 =
: V- T# O5 d8 F5 Z
: F3 [5 N. g& d! Gx + 1
5 R6 T( v: u9 T+ j' J3 g3 I. e7 z: m" Y
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%) Z2 |7 j' E' d+ Z

5 H9 u" s( ~( T5 q) B0 [
! g' _7 q+ V9 x, n' I  R( y' I1 O; N0 h9 L; R: I. e
2.编写一个脚本,判断输入字符串中每个单词的首字母是否为大写,若不是则将其修改为大写,其他字母为小写
+ h! [2 z  T% h( T# Z; V/ m
0 C! a3 h! s9 v# N7 k! X参考答案:4 P$ g0 ?$ h, P& |' _; U3 r: S

& P6 S" W" w8 `8 q- G+ i! v脚本文件内容为:, M: d- S' I- I- R1 o9 l1 M$ n

, m& e5 Q/ g8 w1 Mstr = 'this is the string to be converted';
* R# i7 v" ]2 {6 j" O
8 {# T, Z2 ?5 S( X8 G- Tnlength = length(str);
( L! Q! }( Y) [# M% V2 V* z. L/ a# ]: C2 P7 o6 O
for k=1:nlength% X4 v  y3 B, l4 t+ D5 S4 @6 V$ Y
: t4 {' a9 z' v  q  d
    if (k==1 || isspace(str(k-1))) && (str(k)<='z' && str(k)>='a')# y7 R3 o! X0 j

0 d) i- K, I1 L( o) c) L        str(k) = char(double(str(k)) - 32);/ ]8 o& K4 i5 z6 b/ Z8 F5 y
: X6 j4 H) s" `3 }; F
    end
1 X( D5 ?% \. V  V! K, \
+ X' d& ?1 J/ k' k. {" B/ x9 hend
6 D/ i7 n  i# i2 _5 V" g/ I7 i) n# L& P1 ^4 M' O
disp(str);
; N9 o) d7 Z/ q) s
5 i* v/ L% `! z, Q/ b0 Q1 a. K+ a5 q
2 W; H. S8 o: B5 m
/ T0 u9 o6 L7 O+ K  r$ }1 A$ @; z& D%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5 @5 V+ T6 w# R5 u" Z+ m$ P# p
0 G7 c1 U" T% ?" M: Y
4.创建一个结构体,用于统计学生的情况,包括学生的姓名、学号、各科成绩等。然后使用该结构体对一个班级的学生成绩进行管理,如计算总分、平均分、排列名次等。
9 S0 [! g6 G1 C7 l; p2 @
7 ^2 F$ W. p$ N% \3 R6 }. k参考答案:' d2 \/ r+ k/ h4 H8 K) p; @

( [" y1 i( P9 m! c; w5 j>> structtest=struct('name',{},'number',{},'scores',{}); g! y1 X- Z: F9 R/ Q# N+ \

; _: T6 w; V# R! a8 }: L9 ?
% Y! K0 ]! r5 N) K" `
6 a* n/ {, c' f3 k. ^! n%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
* a2 }: D" Y3 Z4 W+ _1 g7 M3 h$ I4 w* ?. ~
1.创建符号表达式, A) C; D& t, N, X& \$ E* U2 T
8 m* Z5 Q/ h5 t$ m/ {% w; v
参考答案:
) S, _- ?8 N0 w: U
6 T. p' Z' q- c# f& A>> f = sym('sin(x)+x');
0 z+ j( l1 M8 y; \6 @( f. w* b+ Q2 ]8 N+ ~( p3 ~" V! n
2.计算习题 1 中表达式在 、 、 处的值
1 f* m' `( [3 Q5 K, c# R+ ^  w4 f" C
>> subs(f,x,0)
5 v6 S3 l7 o" |1 \4 N) Z  H3 b7 \" s" U; e1 l) K# K
ans =- m& s7 y0 L7 I! [3 E
# m, T7 V1 W: _( F7 z
     0
# Y% r6 ~6 Q" f$ [# |1 j) S) e/ ~  F, J5 d; m4 O$ V3 K! f$ n
>> subs(f,x,pi/4)+ H$ x6 h# q- j& d- ?, Y. r

1 x" T: A- a2 T) }/ Zans =4 h3 P: Q7 p8 y

6 n# n! g' B& _) p    1.4925! C0 Y: K3 g9 }( y8 V- F; \

4 _. F( }6 v7 o9 `# t / k: L- X  v- S* t- k
, }! K# H, Z( D, F+ s0 j/ ?
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
* P7 K. k/ e* j6 `( s0 E2 R6 L1 f0 v6 `6 }  h8 v
xth = 0;
) T8 |, [0 _; b; I) u% e! Ttic
8 m( q1 X$ j% G, |' Gfor x = -10:0.5:10) B' o' y9 h+ @, P+ O
    xth = xth + 1;
2 ^, s: ?7 K5 }1 V) c2 z    if x <0
1 A" x! v7 R) e0 t        y(xth) = -x^3 + 5;5 c: N1 ]/ \3 R, d% p
    else$ f. G/ Z( O- j1 z+ x( p
        y(xth) = x^3 + 5;" Q4 @1 B( L' S
    end; Q$ x1 p; V1 k) b0 T3 p
end# `, ^4 v6 k- o7 `# u  ]0 N- l
toc/ m. q2 H: Q: k& e. z- i
' t. {0 D9 @# A; k5 M* O, j" `
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
+ i, u9 r& ~/ O. n+ ], ^% b1 @! F3 \9 t
tic
" b4 B6 S( g4 ?  R3 j- yx = -10:0.5:10;
7 n8 b! e4 T8 J& F! {y = zeros(1,length(x));  i7 k7 ]/ ?" E9 d' Q" z
x0 = find(x>0,1,'first');
4 _! k6 O6 J7 [' ~# n- n* ay(1:x0-1) = -x(1:x0-1).^3 + 5;
' |/ T+ A+ _0 F8 H& Q8 gy(x0:end) = x(x0:end).^3 + 5;- {7 F( G8 D9 w1 }. @& G! h" D
toc: E1 }" C3 ?  _, F5 r
2 u3 I2 D8 J  N- ~) R4 J
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
& x( D* a& }7 r! [0 h! h) ~6 A$ b- l
  S* Y0 ~  \6 z2 _
6 w- n8 z* _& Q$ N2 @) E
1. 在同一窗口中绘制函数在 之间的正弦曲线和余弦曲线,步长为 ,线宽为 4 个象素,正弦曲线设置为蓝色实线,余弦曲线颜色设置为红色虚线,两条曲线交点处,用红色星号标记, R, ~2 Y- R9 O9 q& G, W  T
! ^/ C" ]( @7 F: T. e# p
参考答案:" |, |4 b" |  ?: P, E- n2 ^
6 d& F( y! g+ L  P: {$ z9 Z$ j
>> x=0:pi/10:2*pi;* U6 Q- T- z% Y  U
1 M  R' n3 v* _" J
>> sinx = sin(x);6 ^0 k1 s5 v% E
# f/ @# Z, z! U
>> cosx = cos(x);( P5 O. ]3 E. I  f: U0 ^6 N" T' U
5 a* E2 X0 u8 V+ l8 g
>> figure,plot(x,sinx,'LineWidth',4)1 A7 u( C+ O: D* i, G

# q1 Q6 L6 V# C' i2 ^) l>> hold on,plot(x,cosx,'r:','LineWidth',4)
0 f; l* n* u- }7 E: n3 J* `+ ?  O+ t( v2 f# J6 \* X7 z$ ~# u  v
>> hold on,plot(x(find(cosx==sinx)),cosx(find(cosx==sinx)),'r*','LineWidth',4)5 P" D4 |! |% A! f9 I) d
1 d7 L$ \" W& `# k) g" G- ]0 ^

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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%6 U' q+ ^1 l. t" K4 G/ D

' v( ^5 n; b+ V1 y% P1. 编写 MATLAB 程序,绘制下面的函数:+ R9 _& F& z3 m: T1 \5 w. _
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,其中7 d; f4 u) y8 l: G8 K; g" d. u

# _% s; W  o  g- b  f" s& T8 k该程序在绘制图形之后等待用户的鼠标输入,每单击其中一条曲线,就随机修改该曲线的颜色,包括红色、绿色、蓝色、黑色和黄色。: f" _! [* k& y2 `4 y$ C

8 \3 r- |8 ?2 R9 I1 g& m+ ^参考答案:
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t = -2:0.1:2;
' J' ^) _" I, L1 I: p  [) C7 s: V6 E1 h
+ [  j2 b, b) n0 nx = cos(t/pi);
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y = 2*sin(t/(2*pi));
+ |* x$ L) z3 R5 W" c. ^
  a8 r* G2 E* F7 p+ }7 j# ~/ Qfigure,plot(t,x);
' _9 e* _: j, C2 q! `0 W8 k: u3 m" U( w1 N% Y3 j6 E
hold on; plot(t,y);
6 H  N% X4 V  ~  ~; G
8 y* k9 E# d. b. G%if waitforbuttonpress- Q! e8 b8 B9 \& T) ?# k/ x2 c. }

. h# S. C3 v3 g" Q9 C2 {; Mwhile(1)( F; k. e1 ~0 W

1 ]$ u1 k$ x3 j2 I    if waitforbuttonpress==0! t7 v' ?0 v+ m

" ]( S& g7 X& ]" G5 N        get(gcf,'CurrentObject');' O' e; w, c0 d% P8 w2 x6 B/ h! H
) \  z* ~5 G: A: }
        c = ceil((rand) * 5);
. U: s. M" g! n6 d: D- K+ C! e
* c5 B0 b7 Y- l9 d$ q1 @& h        switch c* j  q" D0 t3 A& }

# w9 d1 @1 p* i0 `            case 1
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. Y1 ]( d# S& @1 t  J                set(get(gcf,'CurrentObject'),'Color', 'r');  R! [  K0 N3 M& {. S7 D

$ E, x8 l7 ~/ O2 j2 R            case 27 f1 _8 k$ a- B' x5 M( w

& `, O. S/ j/ u0 V                set(get(gcf,'CurrentObject'),'Color', 'g');7 |5 F2 b4 \+ j$ ?# z

- s! y2 d; S% r0 P) a            case 3* }+ Z2 U8 Z! R9 E1 b  @8 ?

: K0 l( \5 c' K& Y2 p6 V                set(get(gcf,'CurrentObject'),'Color', 'b');" a! |+ H0 @, \! O5 u# d% v: O  ^+ y
6 U7 f5 R2 p; T  e/ N6 L) _3 I$ m
            case 4  I! J$ a: K8 k& Y5 Z4 t. G

2 @# A3 A0 {; M$ J                set(get(gcf,'CurrentObject'),'Color', 'k');0 w2 \! s7 r( b; T

: G1 r7 V  ~7 ?' t( ?            case 5+ S) V4 T5 N' @* y- }  c
1 V" v' `0 n5 Q$ l  P: K
                set(get(gcf,'CurrentObject'),'Color', 'y');6 N1 F* k/ t" j

: x1 o& l/ d5 c4 {% b        end# }% k$ O! Y. t/ h+ O
9 I+ O- v+ _; U; U
    end  U- h( |# \3 f

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