someone 发表于 2022-9-28 16:29, K) n J9 K1 t6 S+ `) g" J
具体函数不太清楚,但是可以这样去掉:# [0 _% `# e9 k; e }) ]
A =[8 7 5 3 1 5 8 9 3];+ Z9 | r- |+ M( J) q" Q. K1 x/ U6 z+ P
A(A == 6 | A==5 | A==4) = [];
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