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标题: MATLAB基础教程之实例原文件 部分 [打印本页]

作者: ulppknot    时间: 2020-3-25 10:24
标题: MATLAB基础教程之实例原文件 部分

7 f( D% h2 M( D8 D1 I+ w9 I>> str=['MATLAB 2006a']
4 [+ |. m% x0 a% P
. x4 r) N: H+ O5 b2 T+ E  p7 |>> str
  S9 f, J5 O$ d3 W' ^/ `+ \3 [/ a5 m: k) Q9 ]' J# H# p4 y: E
>> disp(str)' D7 q0 H4 N, R9 ~( X! |

$ m" {6 R2 {. I, h! B%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
3 W7 Q. n) @9 e- o8 [+ E( i5 k& q/ Q/ a* q. ~( Z. e
>> x=-2:0.2:2;
1 ]) j( x4 V& e6 B
8 J. Q1 `+ }2 g6 y* k, T+ U>> y=x.^2;3 o  V* }2 p! H0 W% q4 I: D

2 \1 ?7 g8 d9 T, D3 ^4 s+ |>> plot(x,y)( Z, @# y: e! }" @5 E2 T
0 J. o0 w1 n3 @% f, T
>> str1 = num2str(min(x));
# B- `8 q; d, x; [
9 k( h+ O& K. g4 ]# l>> str2 = num2str(max(x));
0 h2 v. M: _3 P; g* Q5 h- u! U+ r' l; s; d- O0 Q
>> out = ['Value of f from ' str1 ' to ' str2];, K3 t5 N) j$ w

- C' J0 K- z  f- n: G%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5- X7 P1 ?+ ?; D9 Z
" _: I& i( i* e7 u
>> A(1,1) = {[1 4 3; 0 5 8; 7 2 9]};" D# @/ l1 i$ O
; L# C8 _: m+ U4 B# b
>> A(1,2) = {'Anne Smith'};
5 Z7 ^9 Q' e: U; c6 _) T+ a# w- z  k4 n9 E
>> A(2,1) = {3+7i};
" q: m6 m3 Z& G  t6 A/ Z: ^. _: S3 A- J  _
>> A(2,2) = {-pi:pi/4:pi}
' v' L' T# K) Z. C1 z3 z: F9 p6 X6 p" f' \
>> B=cell(2,2)
1 ]# ^: u, w& \" Z& n: b! H( Z( h9 L0 }  |* U
>> B(1,1)=A(1,1)
1 Z& a9 Q- W) r6 ], w( \2 i>> celldisp(A)
$ u% a3 c$ Z# X" J3 ?! c>> A{1,1}* S# m- U. q* ?/ M, l" s' M
>> cellplot(A)
3 j$ [( b+ C0 z- K
: H# z. V) F3 v: S- Q1 k2 Y9 y0 v4 V%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5! T, g1 L0 E6 ]+ E9 l% z5 W, f) `& Z
6 m% U/ Z5 V9 W4 M! x( o0 u
>> clear
/ ]  f# P' X# p9 R7 kA=cell(3,3);8 p) B( o3 _4 A; l: m
for i=1:30 ?, @" `' z1 H6 Y' t/ R
    for j=1:3
. i4 j; K- o9 m) ?. w7 v! y2 s        A{i,j}=randn(i,j);" G1 _! {0 u- _: r3 {
    end
9 P+ `; d7 J$ l6 _) Z3 bend: N6 `6 R) P. j( p# W. s
>> subplot(2,1,1)( _, S$ A) G" I8 ~6 v
>> cellplot(A)5 p+ ~  l1 S; o! x( L5 |
>> A(2)=[];* V3 M; k$ z6 A3 f6 A" v
>> subplot(2,1,2)
' q% `/ y* d  r9 `2 x2 R>> cellplot(A)& O% D% F6 c# d+ B* _$ U2 [% T
>> clear
: N1 q2 t+ U. F/ QA=cell(3,3);
* H( D1 n5 A- B0 ^% B/ B% ?for i=1:3
, E  @# |% I5 u- o7 f3 o8 r    for j=1:3
3 r0 f( ~4 _; f( z4 h: P( ]/ F. U        A{i,j}=randn(i,j);
( l' }1 h- s1 p. V5 q    end0 A2 Z+ Q; j$ H& k- l
end
# T' J; V3 N+ w8 O# d% K>> subplot(3,1,1)3 E2 W8 ~, s. `2 Q
cellplot(A)
$ C' ^- h+ c6 Y5 {7 FA(2)=[];) m5 q- j% ^$ M0 v6 k, m
subplot(3,1,2)
# \4 x- W, i; A2 t+ ]! Fcellplot(A)
  v* y2 G2 V4 Z. k7 R>> A(3:5)=[];
7 X& K+ s1 y7 K8 {% P>> subplot(3,1,3); U: _1 x  w: N$ w
cellplot(A)
0 }' X9 {. @% T4 S/ d) Z 0 T2 S  F& f( Q( Z' v$ _0 w

) Q6 U9 R# q0 d4 X: @* B" p) ~%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%; @  t  \! p9 ^. p. s) m5 b  z

# ^, H+ K# y& x$ I5 K, k>> person.name='liuhuiying';' g" _/ Z7 ]* O0 N, ~3 I  |# t
>> person.height=162;
; l9 Z+ f. M) ]; x3 u>> person.weight=51;
3 e$ x" C% O0 x7 {! }>> person.hobby='swimming';
9 S2 i! j, f& y( p8 B>> person
" p. K$ `& Z& t* f- {
0 d+ J; c4 q9 n>> person(2).name='zhangqiang';+ A  a$ U7 f" J( l- @; c
>> person(2).height=175;5 r* Q: ?1 {; z) m1 l6 o
>> person(2).weight=65;" p0 o! J; `; r1 a6 {& H+ R8 u( g
>> person(2).hobby='Game';+ W2 X0 }. F7 V7 w
>> person) J8 G2 [; X/ i- D. J7 f
9 A2 a+ i( }& y; _. {2 l
>> person(1). Z* ^$ s/ d9 ?) F

6 ~" n- W0 @2 K+ j8 @. o+ o: T& \>> person(2)3 x4 P9 W  A6 R+ Y0 g  z

% v; t! l2 o, i1 L- x- Eperson =
' L0 j' @) l& p7 C) A: o% K
. E' R  w1 l6 Q      name: 'liuhuiying'6 i' Z! j+ s, t; o- i
    height: 162
% ?* Q. Q$ o4 |* q" B8 j: _    weight: 51, \; a6 A; \" Q
     hobby: 'swimming'/ m1 ~4 Q+ z4 I' g/ W0 v- L; G( [
& v# [9 @. L3 ~# |3 Y. j9 H
+ D5 |/ z% u1 N. h% V, i4 r% _; d$ Y
person =
- A0 y) f4 _: T4 F+ M+ T  Z3 M/ j8 j( m' g
1x2 struct array with fields:, }- e5 h; [: b& i! u
    name
( t/ k) c$ z. U% r5 R* ^( y* b    height
# ]# ]( \9 G! j9 V0 t& Q! K1 q7 x    weight
6 A0 o3 s7 V! W4 J) `( z8 j' L5 q    hobby) _" y" X$ I) ?

- w8 X& }/ o' z* m8 X& A. y- X, y7 b6 f" Y( E* J2 A" F
ans =
* p3 M7 {  z2 a3 ^4 ?& n. N' W6 M+ Y' B# M# `2 f
      name: 'liuhuiying'- C/ l' @( Q6 f8 z0 {
    height: 1626 D" z' Z4 F5 V7 W2 f; I
    weight: 51: s" _8 }, O  E3 I# \3 |9 d
     hobby: 'swimming'2 t+ S2 e0 |6 ]

5 r5 q9 \$ B& ~6 u
" n' x2 @! J2 u1 @) S6 _3 ?8 D, tans =
$ l& u+ Q2 ~& Y# G# k3 w' h5 ~- e1 b4 n( h, G6 N8 K$ W
      name: 'zhangqiang'8 Q# o9 k0 c+ c, r, g, g
    height: 175
% Z. ^! V& {8 T5 A/ e    weight: 65) C  B; J9 S" t) e7 i' d; Q
     hobby: 'Game'
, z( Y) \7 f3 Z5 s: S" T0 x& p, D) n8 Q4 ~5 e0 {2 }
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
" K0 K2 ?9 P  `1 f0 Q8 S2 E7 m
5 {3 X8 _0 A! ?$ d% b  K>> person=struct('name','liuhuiying','height',162,'weight',51,'hobby','swimming')  [0 J- b5 v7 P" c' N! o5 x

$ W0 `3 O7 r8 r7 Z0 J0 Yperson =
% `! p* k% `& f! p) o- P0 [& A5 H3 y9 `$ \( L
      name: 'liuhuiying'- x6 U" k% ^( @: p, Z" n0 k. j( p9 i2 N
    height: 1622 e* x( I% U! @% m& Q" k# D
    weight: 51
# Q! I5 e: }6 I% u4 E* R) J' q7 r. a     hobby: 'swimming'& k: N5 e( j5 j! h2 E* ~* \  P
8 T3 |% |& b7 [6 w
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%& @1 R- w+ ?3 v

" \/ I5 x3 L. N7 ], T! m3 K! f8 R>> person=struct('name',{'liuhuiying','zhangqiang'},'height',{162,175},'weight',{51,65},'hobby',{'swimming','Game'})
$ }! G/ w3 D3 h
9 O4 |$ j* s; B' x2 `, w7 a>> person(1)
' k& Y& U$ G  A* P& l) w  @
7 }3 Q# Y* a% L4 C>> person(2)8 ~5 P, R0 O" B8 x
% z% ~2 w3 _: ~2 o

# Z. ]* _( K' @$ g- K5 D% H- K3 u- A4 f. |3 ^) V& }) U

5 O$ A: x$ J1 X& cperson =
3 i5 B/ L1 F6 K3 `- }& Y7 V% O4 @- |9 Y3 K2 j; t8 W
1x2 struct array with fields:& H# `" n9 {1 _+ ~+ q
    name
6 T7 S8 i/ |8 @) o9 T. H/ _    height
; G) |2 o7 r  W1 o0 [+ S    weight
4 x- G+ W& T$ c% r4 l. O5 H    hobby# v9 H- t/ ?7 p, \9 Q
0 d. W$ f# c2 v8 ^% z0 ~% J( e

9 M( i8 `4 O, ]ans =
0 A# R) Q9 b3 w$ i/ S, M
+ M9 w! Y% {! I6 @8 K# Z1 Z      name: 'liuhuiying'# ~+ `5 t$ v# t8 q- w6 U: b# g
    height: 162; a, y: Q4 g9 b  V' m# O, V
    weight: 51
8 R) j; m/ H. a* f; j, X  Y& o" l     hobby: 'swimming'7 ~* K: ^/ {- ]/ {* g4 K

: ]& p8 l  j) u2 u5 E, U/ e" W$ O8 Q2 H& ^# L& I9 Z, F
ans =
  n' u* U+ B3 K* D1 Q9 b7 o' N) m5 D  U  }+ H3 i1 R* G! V& b, X% D
      name: 'zhangqiang'
" O; o. W5 H8 B' I% Z& T) y- S    height: 175' G( p( S' o9 ?1 E- ^6 W
    weight: 65
2 W5 X; X( D% |. `: \5 v+ q- T# O  C     hobby: 'Game'  h5 E5 g# h! t
$ _4 |" i$ Q. K9 `
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5, C! G( m: G( a5 l1 x

# R% j6 T- C* f, x5 y7 P>> person(1).gender='female
$ Y- U7 \7 Y; ?7 i( C4 t! y" \7 D! g+ x" p* q
>>person(1)# t8 W! E: o* N3 v4 g
1 i' e' l  q- ?$ j9 p
>>person(2)" O+ G) M# U9 w  m
8 A2 U  U) m& e- K( C) U+ P
person =, b" F* u* u6 f2 Q# t/ E7 \

, V$ _% r) _* }& m+ f- C5 P, y1x2 struct array with fields:
7 |4 u8 m- w8 G    name) H2 O, |8 n, O, F* `+ @& C
    height4 Q9 G  P1 w0 o3 o: m
    weight
0 P5 v& \; q1 j  p7 T  Q    hobby+ w# q/ c- J/ z
    gender0 o& Q; r+ p3 c  N6 a% N

0 C% G2 u4 B7 l; Q4 R4 z' x
' \" F% o. X' x2 E9 Pans =
0 F% D; o* y2 @9 x" ?- J, v" c6 R" C* `, p" \' C6 i* W; n
      name: 'liuhuiying'
0 s" ^/ b6 n8 q2 P4 g    height: 1620 n7 q% u! Y" t, X3 g- V3 O
    weight: 51+ f) S2 p: m+ k2 V8 `) i8 M
     hobby: 'swimming'
1 ]3 }/ C9 k! X  R8 t    gender: 'female'* ~+ R7 w9 Q9 N$ L0 n( a' ?

9 z: |- u3 H% B6 }; I
. {* T; I8 L5 S# D; T) F3 Oans =0 `" w+ {( I3 w  @3 O$ ~; @, _
5 X; \: d+ r7 `( t/ H, t7 _: b2 \
      name: 'zhangqiang'9 W6 ], e, l  T! B
    height: 175: J9 S0 D' {0 x  R5 z
    weight: 65
$ D3 f" ~4 D- h* F3 M     hobby: 'Game'
* k4 J! q/ r$ ^  Z- l2 u    gender: []; c* ^! r- G/ p$ d0 o

- J! S8 q8 z5 R%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%. u! I) t5 l% F

) _9 K. t  c4 ~: i  A# w% ?8 Z/ u>> person=rmfield(person,'hobby')
% r  o; n% ~! f/ Q) s) K* Y5 p# r1 g$ {; B+ p
>> person(1)$ u( B% s$ W9 ~

3 `4 ~* \+ T7 R8 _' L>> person(2)
0 p2 \0 B) N7 [8 f+ Z5 a
4 c  c  v, {' u. h8 R6 U : f. Y) t4 Y. R5 X- ?
0 n( ^: S" M8 P" N$ H$ b7 _7 k0 V' }
person =( _* g' [9 H- g+ E2 Z/ v  p8 J
5 C, M) n6 o' c  q" n; Z- _
1x2 struct array with fields:! o- k" ^( Q6 k6 z( X
    name
3 y+ n2 y) g* B$ @    height$ q& ?0 f# L; z' g
    weight1 Q) N5 l8 s5 A( r1 X0 }, P9 |
    gender2 p# Y2 \: f" W$ H- _. Z) ]% ^

; P7 ~+ H& A1 w& x: B) Y3 i1 o) z
* W* i+ F5 J4 f/ Lans =, I8 v# n/ ~5 ^, q

! }+ _% o5 c+ W  T& B, `1 K0 O      name: 'liuhuiying'
4 `, s% }4 w% A6 O    height: 162
! W5 [# N5 F, [3 q) ]( g7 l# ?    weight: 51! Q2 }4 F  ?5 f2 |0 x" ~# h
    gender: 'female'
; {# j# ~5 @  S
# o1 t6 ], p4 O! k6 [2 z4 N1 g
$ w# |! z2 \. @# c) sans =8 B! i( T. j1 }
( N2 o* ~1 A" K+ j. o3 H9 j: ~, l
      name: 'zhangqiang'% z2 [& l: J0 d# D
    height: 175& C; S+ X, E* k: J
    weight: 658 o+ q) W, K; q* _9 ~3 _
    gender: []
/ @# _0 E" R- K& l3 q/ R0 {$ ~8 P: C  C  Z/ R
$ [1 H* _0 T# {( j7 ~+ B: h

4 X7 E6 {0 U, @/ c9 l4 o& v; n' d%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
4 T6 v6 I: x) [) I( {" H. C3 i# ^8 U
# p6 x1 p* M8 n% o6 \9 p8 P>> person(2).gender
0 x' j( \: S, q( q
( s+ {# Q4 Z' G+ S# b% f>> person(2).gender='male';: o/ e- c: R# [4 b% K& {4 w
' g" y9 p. g  |% D
>> person(2)
' Q/ r. c" }. R- R9 U4 `* Q, x$ q+ z* \7 W/ n5 K' O

: Y4 d: k! h* E7 H9 f# {, `0 E. j8 u& d- x
ans =
$ [5 i, q# O  N; \
3 F5 }% {; ~" e     []9 q0 {  }9 j5 K) H3 k

# Q0 W3 R5 f5 q  Z: e% I0 R/ k5 f7 S9 b* s* n. s6 h
ans =+ S( I8 F# l( b4 O' o

3 r3 ?! N% F2 ^+ z( @      name: 'zhangqiang'
  _7 k6 R  x6 G. p% ~8 g    height: 175$ g; O2 O3 o6 {* U+ D6 R7 T
    weight: 651 ]+ |- c/ D3 u% `
    gender: 'male'
% p/ Z. P# n2 t9 B1 L
. J: ~$ G5 D4 Z5 y0 R + F2 w, C/ d8 K8 Q! K# R9 s
. d; {0 y# V5 f9 H5 c
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5/ F' q$ [) ~7 m  {

; Z  P& ~; g' U4 _2 }>> A=[10 20 30 40 50]  t% z% O1 J+ _, c# C

! S7 C/ P) H4 c# q- Q1 C' M$ ^; w>> B=[10;20;30;40;50]
1 S7 a" @2 ~0 j  q9 Y" ^7 V9 S4 _! a5 a( z; c
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5/ [- t4 M& S7 H

/ C" ~% ?# S( _" {6 R>> A=1:2:8
9 q* |' _. k. y; z, ~( \6 v! a9 G. ?" |, n* l5 G% k* F
>> A=linspace(0,12,4)' j2 \+ c4 E% S* A9 [. _

+ C, f1 Z" q, e3 o0 P: u%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%53 T6 L& s, [: m# D6 @# D& V5 _6 G
" |" j. H  T. x6 C  Y# z5 ]
>> find((A>8)&(A<14))       %找出矩阵A中大于8并小于14的元素的单下标索引' _. @3 M* p# {7 m) K. N
, D5 d3 i) N% ?* A. Q* _8 B
>> A(find((A>8)&(A<14)))    %找出矩阵A中大于8并小于14的元素. H6 B7 u% d  B7 I

! x. \4 g! s9 T2 z/ Y%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%50 b$ s" ^! _* c7 N2 R  }
. `) c2 g! E8 H4 V
>> A([1,3,6,8])
8 N/ u% s; F" \1 L3 e( j
0 D3 d9 N1 h4 L- P: @0 j%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
0 r- ~3 }( b  M* K6 `; w+ j
& y& a* Y' Q$ X* [6 {+ ^>> A=rand(3,3)
  k# P* h5 L# o/ B% ~7 J7 _( a, f. W; e8 g+ A
>> A(:,:,2)=randn(3,3)
; s; T# A7 W6 m* q4 M# k
9 z: [8 q/ H% i3 P! {3 w! D9 A( \. r%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
0 H8 Q7 y$ S2 U0 Z! O, a4 y& J9 {; a+ l9 A
>> A = rand(5);7 w8 {% z- d( e9 t7 |- z% @4 l
7 F6 g: h( Y4 S  R" x! j
>> B = A > 0.5;
  v2 ], T2 Z; M5 V6 j
$ `; g9 @! F% h- ?>> A(B) = 0$ s& [2 A) }) j* O

0 ~  t! K% K; q 3 I5 c# M) T4 G* e0 v4 x% o5 d
. [, K( G4 }1 C4 ~  g- C' y
A =
3 ~! \$ b" [- r1 Z  Q6 D: t( L2 M/ p  M4 S  h3 `
    0.1450    0.4018    0.2400    0.4909    0.1112
* K, H7 l( L$ W5 d, V. n( x         0    0.0760    0.4173    0.4893         0
0 _  ^8 E) z/ Y0 [* p5 g) E# ~( w$ s         0    0.2399    0.0497    0.3377    0.3897
, g' Y, J+ {, ^* @# \9 w  H    0.3510    0.1233         0         0    0.2417+ E! Q8 @3 u4 p% p4 D
         0    0.1839         0    0.3692    0.4039
# r8 B# @6 v4 E* O4 E- X/ E$ d, ~; Z5 C, _2 Z8 |
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5$ ^& m( H. ~  @8 R* e6 n

" l" c! a2 C$ H >> A = magic(4)
2 f' w$ Q1 W  B2 }5 P# N0 p4 n- d& x9 H9 H+ f7 H+ P- s
>> B = isprime(A)7 ?1 c2 O6 j$ [) p' [+ @+ q
2 ]# e0 q$ L; c4 D
>> A(~B) = 0
9 L5 ?5 J8 h; L$ M% j+ q. Z4 Z+ j6 A2 x, j  l) |

& U7 V- @; Y: {% ?0 e2 Z/ m: ~8 p% g5 H% l
%%%%%%%%A =! G& N6 q+ J( y& p( I; X

: S3 a. M- P) w1 F& X    16     2     3    13
; f) e0 Z7 t2 V9 C1 R7 f     5    11    10     8
7 }  h8 M6 K' G, t5 h8 K( L     9     7     6    12
( K1 q3 C1 S+ D9 Z) m) V     4    14    15     1
5 z5 m1 K# g+ G8 [0 `; D: m- i4 X+ i
5 b0 J% Q# {6 D; c( L0 X& @( f8 n  l% h( U- P$ `8 V# u
B =
& O* R6 W0 s5 P. f$ ^1 [" C0 g  Y: |3 r
     0     1     1     1  @( P* P! I3 P% R1 t. E; j
     1     1     0     0
1 C: P/ D3 T# V9 I6 X# L     0     1     0     0
4 D7 P6 V& I4 Z! T     0     0     0     0
8 L! K0 @$ l/ T6 L! x. ?  H3 v  V2 F3 U

5 g) ]" ~/ E; s- u5 }A =
- v3 Q5 {8 l* d
* k4 h" {, y3 z* ^3 X0 t     0     2     3    132 H+ e  N% ]9 w8 _8 e+ |7 X( u
     5    11     0     0; P5 I) ~6 H4 }9 v6 y
     0     7     0     04 n3 j+ V5 f% c; L# `) {- |
     0     0     0     0, ~+ V7 ^5 k! Y: d

/ T2 u! x, g- S1 J; p  [%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%50 `( H! j$ w9 c, |5 j
7 M* G0 d2 U6 z2 `" R; x& {
>> r=[1 3 5];$ b0 @4 h2 Z* V; o2 A9 c5 b

9 U+ U' _  g2 a% p. S4 N>> p=poly(r)
. g6 u! r. Q: S
7 Y/ j( X" S/ N' s>> poly2sym(p)
, \$ o8 m; \. k% }# s0 M6 y  N+ `8 y( F: s+ C9 C/ `% p
>> roots(p)' l: Z1 U& Y; F) O# S& m
9 n1 |( p* I. n1 h1 m
p =! r% W4 h( G& {* B
( Z% A( M% v( G6 _! l0 _* B
     1    -9    23   -158 p) j( Y- L/ t! p7 d2 X
( q/ v5 l/ `# B' f' u- m- z

3 G! Z- [" M1 l1 d* p" c! _8 t4 gans =2 i' K, a8 d- z

( L5 }; V* R/ p9 ]' b; @* E9 w( lx^3 - 9*x^2 + 23*x - 15% T$ t% k& m4 H/ m8 o. M

- P5 [1 P- C- p0 k
+ B4 J* x0 c/ A; v' C7 i: {, K8 l. cans =4 x3 s- k, q0 e6 K$ R0 K$ }* R0 G

  ~; }- u/ z7 |2 X0 ~$ o) \! P1 e    5.0000$ I* e$ g8 y  A
    3.0000
5 s4 a0 t2 m2 K$ l    1.0000
) w. d. M3 {; t0 i, C& e9 p+ N4 X5 p2 G# V- w2 \- S( l9 o
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%57 T6 J8 P% X: A

9 |2 a; P0 {/ S+ G>> p=[4 3 2 1];
+ @4 e; D" z- D0 y: \) }% r& @
. }9 b2 _8 {6 o; P% ~% B5 t>> polyval(p,4)  W# P( Y7 ?- I1 V; y6 t! J

0 R# W8 M( T# ~+ m0 [>> 4*4^3+3*4^2+2*4+1
: F. ~. C8 h: X: j% I9 x* G( J* e

8 s+ P3 f  k; bans =* O2 l& r4 l1 O3 ?/ n

; l- v# y% \5 l! U- [3 _+ I1 A1 b   313
7 N! I: p' @. f2 I- }
: o) W/ z5 Y+ B% j" ?6 p& n* R+ z' a4 X
ans =6 e: x3 s1 `. v" I; `8 X( m/ _
( b9 l& e: R3 H+ @6 G; a% I
   3132 A9 l7 j( _4 ?5 A2 l. f
8 {' o' p; y4 u
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5: H) Z4 r" N: r. K7 [( b7 w* U

& q- J$ U3 [% g7 E# ^  r% fit sine between 0 and 2*pi using 3 order polyn0mial
! Q* A3 P- }" r1 }+ z2 B2 g, _x = 0:pi/10:2*pi;" z/ r8 @% L( G* D9 z
y = sin(x);
" v" m4 ~+ p* T: @: xp = polyfit(x,y,3);( j* Z! O6 Q8 H/ v, N; J/ R% g% l
plot(x,y,'r*');
4 b8 M9 ?+ Q0 Mhold on6 C, @0 X$ i7 c+ r% O( h( y
f = poly2sym(p);3 n' @" m+ V! Q7 C& m
ezplot(f,[0,2*pi]);
1 p( V+ x6 j  H) Z$ y/ I8 C; l- E
>> p
7 W' D7 [% B2 n8 J1 \) ?3 V. D! r* @. ?* ~- n' C0 r

+ d3 z+ {+ h, p. |' Q% N8 q/ C% ], z0 @3 f* U

/ Q% k$ ^2 k( d- g%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
7 B" i6 N' q, B1 M2 L+ K' p/ d+ ~2 C! Q( U
% Interpolation using the four methods
7 W% }% j$ X# D0 @6 {, w+ w# ?/ y9 wx=[0 3 5 7 9 11 12 13 14 15];
6 r: w: N9 {, ~( j* `% ey=[0 1.2 1.7 2.0 2.1 2.0 1.8 1.2 1.4 1.6];
9 y* f( `& P: ^9 d$ M4 F! }length_of_x=length(x);
" T- D7 v2 c0 H3 [scalar_x=[x(1):0.5:x(length_of_x)];" o4 e; G) U& x) E& _
length_of_sx=length(scalar_x);
2 z, O3 W9 s  [for i=1:length_of_sx
# v: U: O4 x5 U5 n+ B3 z8 `    y_nearest(i)=interp1(x,y,scalar_x(i),'nearest');. L" x9 w3 N1 R+ q
    y_linear(i) =interp1(x,y,scalar_x(i),'linear');
% Z  v- {6 @5 h/ ]5 `    y_spline(i) =interp1(x,y,scalar_x(i),'spline');
* w0 B1 X4 m  Q: z  z, \    y_cubic(i)  =interp1(x,y,scalar_x(i),'cubic');1 V1 [/ H, Q% v% K
end) ?+ u7 o3 O  }, d% i9 O
subplot(2,2,1),plot(x,y,'*'),hold on,plot(scalar_x,y_nearest),title('method=nearest');+ y8 z+ x2 D5 {
subplot(2,2,2),plot(x,y,'*'),hold on,plot(scalar_x,y_linear),title('method=linear');# t! U6 h- S; X2 b: N) x; i2 b
subplot(2,2,3),plot(x,y,'*'),hold on,plot(scalar_x,y_spline),title('method=spline');  G) @, `9 o3 A, |
subplot(2,2,4),plot(x,y,'*'),hold on,plot(scalar_x,y_cubic),title('method=cubic');
& P7 o8 y9 j$ ]
& j' e& T4 v! _  C1 i* k8 K3 X1 e5 z 0 F) p1 }3 h' A, Z
* Q/ W7 {; m, M) j' f; g

/ m9 `( p2 U; ~% {6 Y" B%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
# g5 U/ A( i5 z4 W
6 A) V& r, l8 S2 ^>> fh = @(x,y)y*sin(x)+x*cos(y);& h/ _/ _# @; Q5 `" a/ q
) ~; O- S& c2 m$ s) G
>> fh(pi,2*pi)  F5 X1 x* l! R( w/ |  h

: \. e# G' K! f, S" b%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5) R! ]% k& A! m' X  F6 S0 E2 d

% t: ?! G; V, h6 C7 ^ fh = @humps;8 L6 @$ y( M+ Z! u: v$ ?
2 I. e5 ?0 U0 X2 F$ N
subplot(1,2,1),fplot(fh,[-3,3]);
* c; F3 i& [% b3 W7 I+ Y. }2 R: l5 Z% {3 b8 _
subplot(1,2,2),fplot(fh,[-3,3,-10,30]);
4 ~- I9 W" W- U# W1 L1 ?
* \' u; k4 B# Q2 ~# s%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
' s6 |8 |) t9 z# `, G. J" {. ^
6 M! ]! z4 u" y; K6 R
4 j' N) K% b4 V; n# w% m& X7 D( E/ [3 Q
% find the minimum of the function f(x)=x^3+a*x^2+b*x+c
5 k, G5 K) G, S8 sfunction [x0,y] = funmin(a,b,c,x1,x2)
4 R) \$ f& v+ H2 D( _5 I1 Moptions = optimset('Display','off');: u2 W* ~" t, H+ v& l# C
[x0,y] = fminbnd(@poly3,x1,x2,options);
1 O: x& l) e9 u    function y=poly3(x)        %the nested function
8 N! P, p" E* W' D, N0 ?$ J  m! ^        y=x^3+a*x^2+b*x+c;. H# v, j1 [$ y2 V' m. X" ~9 o
    end/ d* K' @( N$ r: V8 t' c* E
% plot the function
% K( _8 B. H3 `) c2 i7 \" t* \fplot(@poly3,[x1,x2]);
" O  Q6 w) ]4 Khold on;& ^4 @  ~0 _' p5 D- y
plot(x0,y,'.');
. `: K: J: d& h0 Dend
* \+ d, w9 p4 R; {) r6 l* e* s
) ?+ u' C9 V: X& \>> [x,y]=funmin(-1000,10,0,600,800)) t% O4 @/ {$ l  E  ^/ x2 ^$ T9 ^

3 Y+ c3 e1 ?7 @% ~+ k3 j
( N8 |  w! `* P& K3 {+ n7 h0 u& t0 T" R1 B& i0 z& Y
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
  V# B4 Y8 N9 J- I" ]( B  x, I9 J* R/ b. Y7 q' T: }
>> F = @(x,y)y*sin(x)+x*cos(y);- B, e, u3 E/ w/ o) c2 A

5 E9 u% V& w& f>> Q = dblquad(F,pi,2*pi,0,pi). p0 k! G4 Y6 J2 B& W7 h. J

) R( h, q3 h! M' W%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%/ U; w; k& C7 W7 R+ U1 {7 ^

7 r; B4 b- ?, f" ^>> h_g=@(x,sigma2)exp(-x^2./(2.*(1:sigma2)))./sqrt(2*pi.*(1:sigma2));
4 I- a% X- C, V5 @3 g
+ o) \2 B, p9 f0 z>> quadv(@(x)h_g(x,3),0,2)
" b" e2 N, m3 ?/ W9 z- Y3 H
$ ?+ G- E% `! ^1 V6 Z8 [ans =
, p& u0 B' H' ?- o; Q
% d$ l' w! y! D    0.4772    0.4214    0.3759- U! N5 C. I! Y: B9 k3 L; g+ a8 B

# H  u8 d0 a' L7 I7 @>> quadv(@(x)h_g(x,2),0,2); k3 O1 ~: q5 p: w9 R) I3 k4 H

4 F* f/ B( _7 {9 ~) k% k5 s2 L4 \ans =
2 p: y0 g4 U8 L1 c2 P6 h
$ @) f9 R* K+ r7 q' D! E& l    0.4772    0.4214
/ P9 P% Q/ ?+ Z# O, e. }9 K, p  f$ U  o7 j; b, S
>> quadv(@(x)h_g(x,1),0,2)- \% ~% @6 f" |9 M) r6 t$ }+ p

* |( c8 J+ H" Yans =2 z" D, }  D. |

4 b  p7 j4 u$ K    0.4772
6 ]3 Z! n" _( B* ]7 I8 ]
& [7 `0 l* u: _2 z  |%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%3 r+ P4 ?1 A) q$ E

; C( n9 v& J( U* R% the file to creat a function with parameters
1 Z) `# J9 M( n. mfunction y = poly3_fun(x,a,b,c)( s2 K2 Z2 N, p2 Z- ~
y = x^3+a*x^2+b*x+c;
, m. r" Y- T, R4 x6 M. F. z, p% }: y; r

, K/ V$ D# e4 T$ Z  x; P; A3 f% find the minimum of the function f(x)=x^3+a*x^2+b*x+c1 [* g2 O. E9 A2 @
function [x0,y] = funmin_para(a,b,c,x1,x2)
8 |+ s( v) I% G, l# toptions = optimset('Display','off');) Y  A1 y2 R, W% |" p
[x0,y] = fminbnd(@(x)poly3_fun(x,a,b,c),x1,x2,options);8 x7 [$ O2 _& j
% plot the function
) _& [/ E8 m0 X, `. M+ e7 Qend
. n8 b: O! S& ~& _! }8 k
1 v2 t  t/ t. Q- T, B% A% X! O; _: W2 z/ e0 \0 |
>> [x,y]=funmin_para(-1000,10,0,600,800)/ {" Y% {# y. Y6 n9 e6 ]* y( H
% ~7 e; \  t! F7 C$ }' I
! ]5 {+ Q7 o1 x9 p1 u# a% Q
' n% o6 X. x7 j4 D" [: g. p* q$ v6 w  X
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%8 h% K- y$ \9 x9 J  b4 `( f
& `: N3 Y! r+ |0 g

0 h/ `1 Q" O- T5 b8 a
& e0 T* u& m7 r% polynomial operation- v" s* A1 R6 y/ Q0 A5 R- R' o
p1=[1 2 1];                         %定义多项式
4 f* s8 d- o7 }  m2 H1 t4 V1 `p2=[1 1];4 H, Y% U1 @* F" u- n: W' E2 D) T" x
length_of_p1=length(p1);% X) c# ]( C2 U" e) ^0 i) X
length_of_p2=length(p2);
1 I8 V* Q5 c1 Z& R: r$ b& ]9 H1 W, eif length_of_p1 == length_of_p2     %判断两个多项式长度是否相等8 g! o" \% M! z' Z
    p1_plus_p2 =p1+p2;              %多项式相加' L& W) j$ v) Q3 ]4 y7 e2 n& I$ S
    p1_minus_p2=p1-p2;              %多项式相减
% E8 b5 o, W! [) y9 N2 Oelseif length_of_p1 < length_of_p27 A+ g) c! G: y% H
        temp_p1=[zeros(length_of_p2-length_of_p1) p1];$ C1 ^  M2 J, U+ e8 H# ?% B
        p1_plus_p2 =temp_p1+p2;
" S% C% f& t4 ?) K! q! s3 y0 c        p1_minus_p2=temp_p1-p2;
  b. r# r: h8 w3 D2 p  _else7 a6 G& c" F; ]/ k
    temp_p2=[zeros(length_of_p1-length_of_p2) p2];; ]1 D! X- _; M' w5 S( K
    p1_plus_p2 =p1+temp_p2;/ O- o, C4 B- r
    p1_minus_p2=p1-temp_p2;
7 g3 ^) e( {+ M- b% E* G' }end
$ U8 M+ t% ?4 a: wp1_multiply_p2=conv(p1,p2);         %多项式相乘' _+ u) p. G- k
p1_divide_p2  =deconv(p1,p2);       %多项式除法
5 p/ g' m5 M# zp1=poly2sym(p1)                     %显示多项式 p1
7 z3 Q, h) h+ e1 kp1=poly2sym(p2)                     %显示多项式 p2
* A; B2 Z  c0 J# k7 |+ H* ]6 G" Qp1_plus_p2 =poly2sym(p1_plus_p2)
9 u+ N) r% J7 w# Y7 b3 bp1_minus_p2=poly2sym(p1_minus_p2)6 H( E2 u; p) U9 M' i; e% o
p1_multiply_p2=poly2sym(p1_multiply_p2)( y1 S5 g# b0 n: J8 k; ~: x$ \
p1_divide_p2  =poly2sym(p1_divide_p2)  x  U7 f% d; C

. \; \/ h! Q* z+ [3 f+ N : l; |1 A  m# W* P+ k
1 U' x8 A3 C! p& m" O8 A8 s
! v; _$ Q" J% y+ J0 S  s

# e0 z  s" ^' o+ K 9 R7 h" y1 Q( P4 Z, J: R' n

4 w3 ]  t3 W% S+ k; H' Lp1 =
, e# n3 k0 C5 }' ~( o/ \
2 V4 C; T7 r+ A* A; {. ~x^2 + 2*x + 1; H  w1 w8 s% d
, K' S, z2 F8 |1 Y% C

1 r4 l. \- ~5 ^; Qp1 =% a. C  ]7 E% h7 D) i
& x9 P! C  x0 J, D' X
x + 11 ~9 g% Z; _& m3 M# L& A7 }: c1 Z

: f! Q+ G: y+ R# a7 g+ p2 e 1 @  \% ~2 k; e
p1_plus_p2 =
. f0 A7 i; y' u" {3 @
. O; h) o& N: b7 Wx^2 + 3*x + 2
  ~- y. r. }: C+ c$ ?4 _: o 6 M$ G' F+ G) Z& B! I4 l3 n

- }5 P# |/ R! Ap1_minus_p2 =9 R$ x" v3 _+ v" r, [! {' K5 k
6 @* [+ M2 @. q
x^2 + x# L% w9 w1 j% d2 P& i

5 D2 u& w* j; L2 K7 O5 _ 5 c1 W1 _% o2 ^
p1_multiply_p2 =
5 O0 A1 J. G1 s2 V " _, I$ _4 U1 D9 J7 X
x^3 + 3*x^2 + 3*x + 1
+ H; P! ^/ I2 i6 L' J/ c 7 w: `% D7 `0 x5 L
& a, @( Y- c: H8 r- |( g
p1_divide_p2 =
: j5 n5 m/ U6 s( {* ~% B0 v# A* `) J  P# B : I. q' G, t+ ?6 c6 v& o
x + 1
9 T& h# q$ f3 ~' R5 P3 [" d0 @( `$ N. h, t7 r
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%0 W  h% f5 t& I6 X, l
" |2 X1 m6 c! W) B" }, k9 G
$ a0 t' g  ^6 o  y. s
. ~. w- _9 w5 K; {
2.编写一个脚本,判断输入字符串中每个单词的首字母是否为大写,若不是则将其修改为大写,其他字母为小写
3 p' b+ w+ ~& s
, j4 C2 [$ _5 a+ y2 c6 @参考答案:/ j0 B( N" I, j. M/ B

- J: G8 B2 }0 q脚本文件内容为:
+ Y  U1 ~. E$ M4 b% ]; G  T( j
7 A3 v1 `; C* ^/ x! x' B" N; Cstr = 'this is the string to be converted';0 H+ {9 Y) b, z6 g& d

& C! r* l( c" l. anlength = length(str);  H3 B4 b9 P7 d1 G/ D: D1 J9 O8 X

/ ^# L" i1 y/ j& M1 v8 K" Efor k=1:nlength1 ?8 Y8 n4 T0 \$ I
, H& ^/ Q9 F  ~  y
    if (k==1 || isspace(str(k-1))) && (str(k)<='z' && str(k)>='a'): R1 W' b8 e$ k" f' b9 j* a

" {0 g) o5 s! f; Q  I( w  q        str(k) = char(double(str(k)) - 32);
0 b( b# z- _8 e! f
3 o' }% G' y3 i! U    end
! R$ e/ G; f8 T. W# G
2 L  Y# a' N; U8 _& ?9 R) wend. ]* `1 M7 R$ p( t( T
/ s# M6 D% I7 x, P/ y
disp(str);
- C1 V5 {$ |  J# n- V2 Z. C
. d  e% V0 X& {0 G8 t" s8 K ' F* M( E/ v9 E( y
  z- ?4 Z% `. p. s  b  L$ x6 [
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
5 \  g- K2 |/ Y& \9 }! a, W+ o& a  V9 ?$ M
4.创建一个结构体,用于统计学生的情况,包括学生的姓名、学号、各科成绩等。然后使用该结构体对一个班级的学生成绩进行管理,如计算总分、平均分、排列名次等。
, l/ q( j) R# o7 P0 R, L) W, z% M# |3 ?  W) ?+ V7 j
参考答案:, P) B7 d, C/ y% [% S

& \% n! X- g' d>> structtest=struct('name',{},'number',{},'scores',{})& E& ^. U( }8 R, E) w* u( h
) w! ?9 s1 a4 \. H5 D

/ {" x  a. X4 a0 U5 g  y+ }2 l- s
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% k2 W5 j* ~5 f) K
& E% i* L# J- a
1.创建符号表达式
3 H3 o0 j% y6 X2 F4 b7 K" q3 a* o/ f& T* l
参考答案:
1 e$ q% B: Q  N# s' W3 Q/ {; O! {& W0 \: l' a* L1 r
>> f = sym('sin(x)+x');1 V( \: o4 z" o
( K& m; m+ V2 j. {) h- W8 [
2.计算习题 1 中表达式在 、 、 处的值% C, n5 w& M( l6 ~
/ V2 U/ o8 O1 l3 y- e( S
>> subs(f,x,0)* ?8 N( _2 g4 m) |  l+ Y
( @3 V6 z. I* k
ans =
7 Q6 L  [# J8 }) x" {! A0 M* f1 `8 U+ {7 }0 a! ]! g6 i# O
     0, g$ `  m! U; f. y+ P! e3 x

0 H' p" h6 Z8 d0 _% i>> subs(f,x,pi/4)% F/ |3 u( y# W9 [: y' S  d) Q. j

/ m9 o4 {7 c1 V  g' zans =
! W) x% x9 ^" i. s! G, F8 d: K0 n
    1.4925
: S5 J( j5 k5 x( J# [) l" p$ Y. t- ^

# S! ^! ]4 B. a5 l7 ?
7 A7 V0 X6 s/ [) y" o0 s%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%( L; g0 I8 U6 w' o
5 H3 h6 `  Z, w# i5 w
xth = 0;
3 f8 B: S/ P. w' V- f( atic( L  z& S: S8 O3 P; i; ?* u
for x = -10:0.5:106 `1 e% U3 N5 f, [( r
    xth = xth + 1;
5 F0 t4 D7 R7 E$ k8 A0 Z/ \    if x <0+ `/ E4 m* X0 G- F. _- p5 i, Q
        y(xth) = -x^3 + 5;) p" t; m" t1 F% g; Z+ X
    else. c6 ]2 q4 }" N5 l
        y(xth) = x^3 + 5;
/ m. Z# a. _7 e9 E: r, p8 F; D    end/ M" I# @" j( z$ a7 Z/ N
end. H4 ]- m. e) C+ r" e2 T
toc& R' n5 v7 R+ c2 A  g- Q

; F5 g/ L; U" X$ N) Z; A%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
8 E' X4 n; E, h, H# U
$ m* F3 k1 L- W- Ltic$ s# U7 u5 e+ x% B7 Y+ o7 Z
x = -10:0.5:10;6 J4 Y- j8 m! V# {! V( N+ b7 H; U
y = zeros(1,length(x));( A$ D1 }8 p6 K6 x( y( h3 Z4 U2 z7 A1 V
x0 = find(x>0,1,'first');' Y  p; P/ N; O6 Q
y(1:x0-1) = -x(1:x0-1).^3 + 5;5 v5 s% M! c2 N' I: U
y(x0:end) = x(x0:end).^3 + 5;
' ?7 i4 }& Z# d, Ttoc8 l: |; B% r1 ^, b2 U5 g

* `9 K& Q7 j  B; j %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%+ o% r3 _* [& E3 h4 w

+ g# ^( v8 {; W3 E, ^" w! k, J# k/ F
" ^; F8 H) o  W! Z$ J: l+ v" b
: ~2 H! \4 w) |+ t4 O: l1. 在同一窗口中绘制函数在 之间的正弦曲线和余弦曲线,步长为 ,线宽为 4 个象素,正弦曲线设置为蓝色实线,余弦曲线颜色设置为红色虚线,两条曲线交点处,用红色星号标记
1 A6 D  s3 h! V1 z5 }+ Q7 `
# U* ~5 k  c9 A1 L6 S0 L参考答案:
+ I. n2 M" u6 w5 v$ s/ ?. B7 B( ]6 f- G# _. ]$ d& {
>> x=0:pi/10:2*pi;1 R: k$ N" h4 P
5 p" y7 J3 b' @  @/ F; u
>> sinx = sin(x);2 k! {7 L; f1 T% r
, q( y$ H$ i" C0 \
>> cosx = cos(x);" O) q  V& k8 I0 m+ Y
9 a: V$ ~+ ]  c. o! y0 E! V
>> figure,plot(x,sinx,'LineWidth',4)8 H6 U1 i2 j& N$ }1 ^5 C! p! }5 t
" D4 B  A' [7 M1 s& M) z
>> hold on,plot(x,cosx,'r:','LineWidth',4)$ |$ ?5 ^, g4 P
) H  W) ]7 T( Q# @4 C; I
>> hold on,plot(x(find(cosx==sinx)),cosx(find(cosx==sinx)),'r*','LineWidth',4)# Y+ {; j; i: }/ g  D) M3 b. p

) q, I" C2 r+ G$ p2 H/ i 4 k( w# h5 b. C6 w

& ^6 U& T( k5 q%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%& t9 y3 D8 R( t

4 P3 P1 |. W& j1. 编写 MATLAB 程序,绘制下面的函数:
& ]" c' M1 ]$ y( A& ]/ B' D: c- I0 g0 y1 i7 g
,其中* K4 F: y2 i  }8 g9 W3 l

$ E) F, _7 N0 d& X该程序在绘制图形之后等待用户的鼠标输入,每单击其中一条曲线,就随机修改该曲线的颜色,包括红色、绿色、蓝色、黑色和黄色。; w; x# r8 Q4 F

( q/ [, o- D0 c: Y. Z( w% z* K参考答案:! l; `7 C' q' S

7 A, v+ @; E( h6 R1 ct = -2:0.1:2;5 f6 |9 ^* `7 ]( Y6 [

% |, Q- Q0 `' Y% V" r# t! d( ]x = cos(t/pi);
) x' s2 n. U0 O/ N/ n% F  t7 n3 `+ a# ~" i0 H: h/ o, A% M9 Y
y = 2*sin(t/(2*pi));2 o3 M: ]( b- |0 O

) e0 c# x. T4 [2 h! w% o5 afigure,plot(t,x);) y/ E2 b" @3 \. a5 U
' `/ f9 L# _+ ~7 a1 c' M
hold on; plot(t,y);+ J6 B' F# Q" c# D, G, v6 E
  }  T) Q* V, ~7 K/ _+ G
%if waitforbuttonpress
" f4 r+ s7 A4 K
4 N! C6 I- h+ j6 e" Y5 gwhile(1)
5 v! k& q! Q6 V& U, x7 ?3 ]$ s+ ?! b: G6 G! z4 r# C
    if waitforbuttonpress==0" q' Y5 E- j, K$ d0 Q
. _* R, N3 b: l$ z2 d% V  f& z
        get(gcf,'CurrentObject');% h' G. M2 E! k, {
# b* m" y9 C- k2 @) |# E; f
        c = ceil((rand) * 5);
$ F# M$ j. g1 Z% |; J, z/ ?2 `; \* ]" O3 c( l* v5 v
        switch c
5 [) W2 K2 b4 Y6 ?
3 J! c$ P; M% }# J; m            case 1( [8 q1 x. u) ]2 N, \! x7 n8 T4 q
7 y3 o2 G: T" p
                set(get(gcf,'CurrentObject'),'Color', 'r');
" ?9 b7 X4 L" T6 w# N4 }' ]0 v0 }/ I/ n7 U: X' R/ H
            case 2& I3 h7 M# `. X: O
, }: f$ L' X. L1 ^; H! ^
                set(get(gcf,'CurrentObject'),'Color', 'g');
9 K+ K0 p0 g, x; m% U" k7 t5 A# l- V% _
            case 3
/ s$ Z  D, b4 n/ [# G$ @, z2 O  ^. W5 n
                set(get(gcf,'CurrentObject'),'Color', 'b');9 W- N# P% d4 d! h

- @6 G4 e. {. x. D            case 4
" ~( m7 ^: X) p: R
: a# \0 y" v8 E( a4 o8 g/ E                set(get(gcf,'CurrentObject'),'Color', 'k');2 e) q5 y: i6 Z7 g: [# j
0 z" h( C% ]% d# v; Z; w  s
            case 55 K& K/ ?# o  b6 ]6 }9 N

  O, p* G3 S, M7 }( M0 e' h: i7 M                set(get(gcf,'CurrentObject'),'Color', 'y');
0 o! Z  c! y  e
% B, s! v5 h8 s6 _5 j  k$ }        end4 D1 ]9 M, X3 D
  R7 Q/ Q3 L! R* c9 E
    end
  `' a2 I/ R* }- {( o
% I. y$ P  k8 c' wend+ B/ F. ^/ W/ T3 B
" y( q% O- p# m/ [' n3 s* p

$ ]$ k& a  ~- m( n  M* K( J+ W& b7 p7 n
% p" A8 f5 A8 L! J% {# M! c- [: p( k/ J% t3 E' b' A( E" n

7 i* V0 Y/ N8 ]
作者: CCxiaom    时间: 2020-3-25 17:56
MATLAB基础教程之实例原文件 部分




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