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标题: PCB线宽与电流(PCB line width and current) [打印本页]

作者: ddddaaaaa    时间: 2020-2-17 15:30
标题: PCB线宽与电流(PCB line width and current)
PCB 线宽与电流(PCB line width and current)1 P7 L4 s$ e! z% J  j* l% P
The withstand current of 1 square copper wire is 5 -- 8A, 380V can
9 l; h1 u) s& ^be brought with maximum 4KW, 220V can be maximum 2KW.
0 W& b$ g0 _4 d$ S' z. m4 w" Q2 square? Three square meters can be pushed like that
+ y# C) G! t, tPCB line width and current relationship
( i0 {! C0 U3 y( }I. calculation method is as follows:
: s/ w5 g3 C* HFirst, the section area of Track is calculated. The copper foil0 b# W$ h, o& C8 P/ d
thickness of most PCB is 35um (the PCB manufacturer can be asked if it
& {8 b- J6 k5 Pis not certain). The width of the PCB is the
. f/ A/ h7 L# ecross-sectional area. There is an experience value of current
) v. X; k- @* D$ q5 Ddensity for 15 ~ 25 amperes per square millimeter. We can just call it
$ W6 n5 E/ d% j! d0 c( `, j- nthe area where we get the volume.$ n$ A) n6 r( t5 u+ L
I = KT0.44 A0.75 (K is the correction factor, which is 0.024 in the! K/ [6 L2 h( a; u
inner layer of the copper line, and 0.048 in the outer layer)- Y& G$ Y: L" |  P! t
T to the maximum temperature rise, the unit for degrees Celsius4 ?2 B: B" _# N& {% H/ a; {
(copper melting point is 1060 ?)
1 _& k8 i6 b+ ^- |/ gA to cover the area of copper, the unit is square MIL (not mm mm,/ ]* x0 ]" [/ D! J0 \5 A/ ^
the attention is square MIL.): o% I. \2 z& b4 \6 A  B
I is the maximum allowable current, the unit is ampere (amp).$ D6 ^. i& O0 t& r" p
The average 10mil = 0.010 inch = 0.254 May be 1A, 250MIL = 6.35mm,
# \! C/ t7 P8 T7 O3 _7 Hwhich is 8.3 A  ' g# ?7 p6 T4 ?4 c

( `7 ^& E. v1 K$ @( g) [1 b$ k" L. f1 m0 L5 u( q

6 H5 B+ }7 }8 [& ~6 K; q1 {; G
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作者: ExxNEN    时间: 2020-2-26 14:30
PCB线宽与电流
作者: lqf    时间: 2020-3-3 14:24
学习一下,谢谢。
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